Chron object in time series plot

You seen to be under the mistaken impression that the internal  
representation of DateTime classes of 08:00 would be 80000. Since the  
internal representation of time is in seconds, the even number hours  
would be at integer multiples of 60*60. In addition the conversion of  
numeric to string in this situation may present some need to check for  
missing leading "0"'s. You ether need to describe the data situation  
more completely or adjust your expectations (or both).

?as.POSIXct
?strptime

-- 
David.

Thanks for the quick reply David.

What I need is a simple conversion that can say 80000=08:00, 94500=09:45 and
100000=10:00 and so on.
I agree with you that the extra leading "0s" would need an extra check.

The data situation is the following: I have several thousands of
observations  each day and I want to average them out throughout bins of a
specified size (either 15 or 5 minutes). An example of the data follows,
where the first column is the time and the second represents seconds between
different events.

example.txt

070002,1
070002,0
070002,0
070003,1
070003,0
070003,0
070003,0
070003,0
...
100210,0
100210,0
100210,0
100210,0
100210,0
100210,0
100210,0
...

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