how to convert all columns of a data frame into factors
Alternatively: x[] <- lapply(x, factor) Recall that a data frame is a list, so lapply() is a natural choice. Andy From: Gabor Grothendieck
Try this: replace(BOD, TRUE, lapply(BOD, factor)) On 10/4/06, Weiwei Shi <helprhelp at gmail.com> wrote:
Hi, I use "apply" apply(x, 2, factor) but it does not work. please help. thanks. -- Weiwei Shi, Ph.D Research Scientist GeneGO, Inc. "Did you always know?" "No, I did not. But I believed..." ---Matrix III
______________________________________________ R-help at stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
______________________________________________ R-help at stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
------------------------------------------------------------------------------
Notice: This e-mail message, together with any attachments,...{{dropped}}