how to Subset based on partial matching of columns?

Hi,

Please don't put quotes around your code. It makes it hard to copy and
paste. Alternatively, don't post in HTML, because it screws up your
code.

So I have a list that contains certain characters as shown below

`list <- c("MY","GM+" ,"TY","RS","LG")`

That's a character vector, not a list. A list is a specific type of object in R.

And I have a variable named "CODE" in the data frame as follows

`code <- c("MY GM+", ,"LGTY", "RS","TY")`

That doesn't work, and I have no idea what you expect to have there,
so I'm deleting the extra comma. Also, your vector is named code, not
CODE.

code <- c("MY GM+", "LGTY", "RS","TY")
x <- c(1:4)

'x <- c(1:5)
`df <- data.frame(x,code)`

You problably actually want
mydf <- data.frame(x, code, stringsAsFactors=FALSE)

Note I changed the name, because df() is a base R function.

Now I want to create 5 new variables named "MY","GM+","TY","RS","LG"

Which takes binary value, 1 if there's a match case in the CODE variable

    df
     x  code         MY GM+ TY RS LG
    1  MY GM+  1     1      0    0   0
    2                  0     0      0    0   0
    3  LGTY       0     0     1     0   1
    4  RS           0     0      0    1    0
    5  TY           0     0      1    0    0

grepl() will give you a logical match

data.frame(mydf, sapply(code, function(x)grepl(x, mydf$code)),
stringsAsFactors=FALSE, check.names=FALSE)

Sarah

Sarah Goslee
http://www.functionaldiversity.org