automatic selection of object without loop
You have to give more specifications as to what you want to do with
the data that is being processed. You have values being put into 'q1'
and 'i1' that don't seem to be used in the loop. Do you just want
these values returned? You can easily do it "without a loop" using
lapply:
result <- lapply(names(kinderrechte), function(.name){
# return a list with the result
list(q1 = kinderrechte[, .name], i1 = get(paste(.name, "_l", sep = "")
})
So what is the problem that you are trying to solve?
On Fri, Sep 16, 2011 at 8:34 AM, jim holtman <jholtman at gmail.com> wrote:
did not see the "_l" so changes below: On Fri, Sep 16, 2011 at 8:33 AM, jim holtman <jholtman at gmail.com> wrote:
for (i in names(kinderrechte)){
? ?q1 <- kinderrechte[, i]
? ?i 1 <- get(paste(i, "_l", sep = ""))
}
On Fri, Sep 16, 2011 at 4:47 AM, Marion Wenty <marion.wenty at gmail.com> wrote:
Hello, does anyone know the solution to this problem: I imported a dataframe from Spss into R and saved it as an object called "kinderrechte". I have got the following command lines: q1 <- kinderrechte[,"q0007_0001"] l1 <- q0007_0001_l now i would like to be able to change the column name in the first command line (e.g. into q0007_0002) and to get R to automatically change q0007_0001_l in the second command line into q0007_0002_l without using a loop. Thank you in advance for your help! Marion ? ? ? ?[[alternative HTML version deleted]]
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-- Jim Holtman Data Munger Guru What is the problem that you are trying to solve?
-- Jim Holtman Data Munger Guru What is the problem that you are trying to solve?
Jim Holtman Data Munger Guru What is the problem that you are trying to solve?