check a list that a sublist exists
Hello, Alaios, try is.null( Mylist[[i]]$parameters) It returns TRUE if your list doesn't have a component named "parameters" or if that component contains NULL. HtH -- Gerrit
On Tue, 3 Mar 2015, Alaios via R-help wrote:
Hi all,I have a list that has the following fields.
$`80`
[1] "Error in if (fitcass1[[2]] == \"Error\") { : \n? Fehlender Wert, wo TRUE/FALSE n?tig ist\n"
attr(,"class")
[1] "try-error"
attr(,"condition")
<simpleError in if (fitcass1[[2]] == "Error") {??? print(sprintf("error at fitting gamma distribution with %s periods. Mean %f %f Sd %f %f",???????? flag, mean1, mean2, sd1, sd2))} else {??? return(fitcass1)}: Fehlender Wert, wo TRUE/FALSE n?tig ist>
$`81`
[1] 0
$`9`
[1] 0
$`79`
$parameters
??????????? pi?????????? mu??? sigma
1 0.9996796725???? 1.654832 127.6542
2 0.0003203275 17183.001125 302.8063
$se
???????? pi.se????? mu.se sigma.se
1 2.113882e-05? 0.1439152 14.22274
2 2.113882e-05 38.3582148????? NaN
$distribution
[1] "gamma"
and so one. The content of each first level sublist are never the same. I want for each first-level sublist my list has to check fast that the current element , lets say the 79th has the $parameters.then I would keep only the numbers from the sublists that have this $parameters inside them and skip all the rest.
I tried something like exists(Mylist[[i]]$parameters) but it does not workI also tried the is.numeric(Mylist[[i]]$parameters)) but this line fails when the current sublist does not contain the $parameters field.
Can you please help me sort this out?
RegardsAlex
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