-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
project.org] On Behalf Of Christian Raschke
Sent: Thursday, April 15, 2010 8:28 PM
To: r-help at r-project.org
Subject: Re: [R] Replace / with - in date
Is there anything that speaks against just applying gsub to the factor
levels if one would like to keep everything as factors (and not
consider
true Date classes or character vectors)? I.e:
> x <- c("2000/01/01", "2001/02/01")
> xd <- as.data.frame(x)
> levels(xd$x) <- gsub("/", "-", levels(xd$x))
Christian
On 04/15/2010 01:08 PM, David Winsemius wrote:
On Apr 15, 2010, at 1:51 PM, prem_R wrote:
Hi,every one .I have searched the solutions in the forum for
replacing my
date value which is in a data frame ,01/01/2000 to 01-01-2000 using
replace
function but got the following warning message
x<-"2000/01/01"
xd<-as.data.frame(x)
xd$x<-replace(xd$x,xd$x=="/","-")
The replace function does not work with factors, it works with
(complete) vectors, not substrings. It's also a real hassle to do
operations on factors, so just use character vectors and try gsub
instead:
x<-"2000/01/01"
xd<-as.data.frame(x, stringsAsFactors=FALSE)
xd$x2<-gsub("/","-", xd$x)
xd
x x2
1 2000/01/01 2000-01-01
Warning message:
In `[<-.factor`(`*tmp*`, list, value = "-") :
invalid factor level, NAs generated
Is there any other method of doing it? or am i missing something?.
please
let me know if you need any more information.
Thanks.
Prem
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