Message-ID: <CADv2QyHz1u4V1YZsAWLVtpWpGTrq3cKrw5j-46O-Ah6+yBmYow@mail.gmail.com>
Date: 2011-11-09T00:33:59Z
From: Dennis Murphy
Subject: Sorting Panel Data by Time
In-Reply-To: <1320782329255-4017271.post@n4.nabble.com>
Here's another approach using the plyr and data.table packages, where
df is the name I gave to your example data:
# plyr
library('plyr')
ddply(df, .(TIME), mutate, L1 = sort(S1))
# Another way with the data.table package:
library('data.table')
dt <- data.table(df, key = 'TIME')
dt[, list(X1, S1, L1 = sort(S1)), by = 'TIME']
HTH,
Dennis
On Tue, Nov 8, 2011 at 11:58 AM, economicurtis <curtisesjunk at gmail.com> wrote:
> I have panel data in the following form:
>
> TIME ? X1 ? ? S1
> ?1 ? ? ? 1 ? ? ?0.99
> ?1 ? ? ? 2 ? ? ?0.50
> ?1 ? ? ? 3 ? ? ?0.01
> ?2 ? ? ? 3 ? ? ?0.99
> ?2 ? ? ? 1 ? ? ?0.99
> ?2 ? ? ? 2 ? ? ?0.25
> ?3 ? ? ? 3 ? ? ?0.75
> ?3 ? ? ? 2 ? ? ?0.50
> ?3 ? ? ? 1 ? ? ?0.25
> ... ? ? ?... ? ? ......
>
> And desire a new vector of observations in which one column (S1 above) is
> sorted for each second from least to largest.
>
> That is, a new vector (L1 below) of the form:
>
> TIME ? X1 ? ? S1 ? ? ? L1
> ?1 ? ? ? 1 ? ? ?0.99 ? ?0.01
> ?1 ? ? ? 2 ? ? ?0.50 ? ?0.50
> ?1 ? ? ? 3 ? ? ?0.01 ? ?0.99
> ?2 ? ? ? 3 ? ? ?0.99 ? ?0.25
> ?2 ? ? ? 1 ? ? ?0.99 ? ?0.99
> ?2 ? ? ? 2 ? ? ?0.25 ? ?0.99
> ?3 ? ? ? 3 ? ? ?0.75 ? ?0.25
> ?3 ? ? ? 2 ? ? ?0.50 ? ?0.50
> ?3 ? ? ? 1 ? ? ?0.25 ? ?0.75
> ... ? ? ?... ? ? ...... ? ?.....
>
> Sorry for the NOOB question, but any help would be great.
>
> Curtis Kephart
>
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