Selecting First Incidence from Longitudinal Data

Hi
Thank you very much, but I forgot to tell that I also want to include the patients for which no complication occurred. That is, for my data I want to include patient no. 4, for which the COMPL value will be 0.

In that case, what R function should I write? 




On Sat, Feb 23, 2013 at 12:23 PM, Xiaogang Su <xiaogangsu at gmail.com> wrote:

My bad. I didn't try it out with the real data. Here you go. HTH, X
>
>
>dat <- read.table(text="
>ID ? ?COMPL ?SEX ?HEREDITY
>1 ? ?0 ? ? ?1 ? ? ?2
>1 ? ?0 ? ? ?1 ? ? ?2
>1 ? ?3 ? ? ?1 ? ? ?2
>2 ? ?0 ? ? ?0 ? ? ?1
>2 ? ?1 ? ? ?0 ? ? ?1
>2 ? ?2 ? ? ?0 ? ? ?1
>2 ? ?2 ? ? ?0 ? ? ?1
>3 ? ?0 ? ? ?0 ? ? ?1
>3 ? ?0 ? ? ?0 ? ? ?1
>3 ? ?0 ? ? ?0 ? ? ?1
>3 ? ?0 ? ? ?0 ? ? ?1
>3 ? ?2 ? ? ?0 ? ? ?1
>4 ? ?0 ? ? ?1 ? ? ?2
>4 ? ?0 ? ? ?1 ? ? ?2
>", header = TRUE)
>
>
>dat0 <- dat[dat$COMPL!=0, ]
>dat0$sequence <- as.vector(unlist(lapply(aggregate(dat0$ID, by=list(dat0$ID),FUN=length)$x, FUN=function(x){seq(1, x)})))
>dat0 <- dat0[dat0$sequence==1, ]?
>dat0
>
>
>
>
>On Sat, Feb 23, 2013 at 2:09 PM, arun <smartpink111 at yahoo.com> wrote:
>
>HI,
>>Tried your approach:
>>
>>
>>?dat1$sequence <- as.vector(unlist(lapply( aggregate(dat1$ID, by=list(dat1$ID),FUN=length)$x, FUN=function(x){seq(1, x)})))
>>?dat0 <- dat1[dat1$sequence==1 & dat1$COMPL!= 0, ] #your second solution
>>?dat0
>>#[1] ID?????? COMPL??? SEX????? HEREDITY sequence
>>#<0 rows> (or 0-length row.names)
>>?
>>
>>dat1[dat1$sequence==1,] #here the OP wanted first incidence where COMPL!=0
>>#?? ID COMPL SEX HEREDITY sequence
>>#1?? 1???? 0?? 1??????? 2??????? 1
>>#4?? 2???? 0?? 0??????? 1??????? 1
>>#8?? 3???? 0?? 0??????? 1??????? 1
>>#13? 4???? 0?? 1??????? 2??????? 1
>>A.K.
>>
>>
>>
>>
>>----- Original Message -----
>>From: Xiaogang Su <xiaogangsu at gmail.com>
>>To: Rui Barradas <ruipbarradas at sapo.pt>
>>Cc: r-help at r-project.org
>>Sent: Saturday, February 23, 2013 2:15 PM
>>Subject: Re: [R] Selecting First Incidence from Longitudinal Data
>>
>>Try this:
>>dat$sequence <- as.vector(unlist(lapply( aggregate(dat$ID, by=list(x),
>>FUN=length)$x, FUN=function(x){seq(1, x))))
>>dat0 <- dat[dat$sequence==1, ]
>>
>>HTH, X
>>
>>
>>On Sat, Feb 23, 2013 at 1:07 PM, Rui Barradas <ruipbarradas at sapo.pt> wrote:
>>
>>> Hello,
>>>
>>> You can use ?aggregate and ?head to do what you want. Try the following.
>>>
>>>
>>>
>>> dat <- read.table(text="
>>>
>>> ID? ? COMPL? SEX? HEREDITY
>>> 1? ? 0? ? ? 1? ? ? 2
>>> 1? ? 0? ? ? 1? ? ? 2
>>> 1? ? 3? ? ? 1? ? ? 2
>>> 2? ? 0? ? ? 0? ? ? 1
>>> 2? ? 1? ? ? 0? ? ? 1
>>> 2? ? 2? ? ? 0? ? ? 1
>>> 2? ? 2? ? ? 0? ? ? 1
>>> 3? ? 0? ? ? 0? ? ? 1
>>> 3? ? 0? ? ? 0? ? ? 1
>>> 3? ? 0? ? ? 0? ? ? 1
>>> 3? ? 0? ? ? 0? ? ? 1
>>> 3? ? 2? ? ? 0? ? ? 1
>>> 4? ? 0? ? ? 1? ? ? 2
>>> 4? ? 0? ? ? 1? ? ? 2
>>> ", header = TRUE)
>>>
>>> aggregate(. ~ ID, data = subset(dat, COMPL != 0), head, 1)
>>>
>>>
>>> Hope this helps,
>>>
>>> Rui Barradas
>>>
>>> Em 23-02-2013 14:28, Tasnuva Tabassum escreveu:
>>>
>>>? I have a longitudinal competing risk data of the form:
>>>>
>>>> ID? ? COMPL? SEX? ?HEREDITY
>>>> 1? ? ?0? ? ? ?1? ? ? 2
>>>> 1? ? ?0? ? ? ?1? ? ? 2
>>>> 1? ? ?3? ? ? ?1? ? ? 2
>>>> 2? ? ?0? ? ? ?0? ? ? 1
>>>> 2? ? ?1? ? ? ?0? ? ? 1
>>>> 2? ? ?2? ? ? ?0? ? ? 1
>>>> 2? ? ?2? ? ? ?0? ? ? 1
>>>> 3? ? ?0? ? ? ?0? ? ? 1
>>>> 3? ? ?0? ? ? ?0? ? ? 1
>>>> 3? ? ?0? ? ? ?0? ? ? 1
>>>> 3? ? ?0? ? ? ?0? ? ? 1
>>>> 3? ? ?2? ? ? ?0? ? ? 1
>>>> 4? ? ?0? ? ? ?1? ? ? 2
>>>> 4? ? ?0? ? ? ?1? ? ? 2.
>>>>
>>>> Where, COMPL= health complication of diabetic patients which has value
>>>> labels? ?as? 0= no complication,1=coronary heart disease, 2=retinopathy,
>>>> 3=
>>>> nephropathy.
>>>>
>>>>
>>>> I want to select only the first complication that occurred to each
>>>> patient.
>>>> What R function can I use?
>>>>
>>>>? ? ? ? ?[[alternative HTML version deleted]]
>>>>
>>>> ______________________________**________________
>>>> R-help at r-project.org mailing list
>>>> https://stat.ethz.ch/mailman/**listinfo/r-help<https://stat.ethz.ch/mailman/listinfo/r-help>
>>>> PLEASE do read the posting guide http://www.R-project.org/**
>>>> posting-guide.html <http://www.R-project.org/posting-guide.html>
>>
>>>> and provide commented, minimal, self-contained, reproducible code.
>>>>
>>>>
>>> ______________________________**________________
>>> R-help at r-project.org mailing list
>>> https://stat.ethz.ch/mailman/**listinfo/r-help<https://stat.ethz.ch/mailman/listinfo/r-help>
>>> PLEASE do read the posting guide http://www.R-project.org/**
>>> posting-guide.html <http://www.R-project.org/posting-guide.html>
>>
>>> and provide commented, minimal, self-contained, reproducible code.
>>>
>>
>>
>>
>>--
>>==============================
>>Xiaogang Su, Ph.D.
>>Associate Professor & Statistician
>>School of Nursing, University of Alabama
>>Birmingham, AL 35294-1210
>>(205) 934-2355?[Office]
>>xgsu at uab.edu
>>xiaogangsu at gmail.com
>>https://sites.google.com/site/xgsu00/
>>
>>
>>??? [[alternative HTML version deleted]]
>>
>>______________________________________________
>>R-help at r-project.org mailing list
>>https://stat.ethz.ch/mailman/listinfo/r-help
>>PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>>and provide commented, minimal, self-contained, reproducible code.
>>
>>
>
>
>
>-- 
>==============================
>Xiaogang Su, Ph.D.
>Associate Professor & Statistician 
>School of Nursing, University of Alabama 
>Birmingham, AL 35294-1210
>(205) 934-2355 [Office]
>xgsu at uab.edu
>xiaogangsu at gmail.com? 
>https://sites.google.com/site/xgsu00/