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how to get the numbers of factors in a matrix

10 messages · 张以春, Liu, Jun Yi, PIKAL Petr +3 more

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Dear YZ,

I guess this is what you want:

1. http://stackoverflow.com/questions/3418128/how-to-convert-a-factor-to-an-integer-numeric-without-a-loss-of-information
2.?http://stackoverflow.com/questions/6979625/arithmetic-operations-on-r-factors/6980780#6980780
3.?http://toddjobe.blogspot.jp/2010/08/converting-r-contingency-tables-to-data.html

but beware of that ?If you really want the levels of the factor to be used, you're either doing something very wrong or too clever for its own good."

All the best?
JY

------------------------------------------------------
From:???? yczhang at nigpas.ac.cn
Reply:???? yczhang at nigpas.ac.cn
Date:?21 January 2014 at 16:57:38
To:?r-help at r-project.org r-help at r-project.org
Subject:? [R] how to get the numbers of factors in a matrix
#
Hi

It is rather difficult to understand what problem you have.

post some data e.g. by

dput(head(bigmatrix))

Maybe your problem is in a factor feature that it preserves also empty levels until you specifically drop them.
[1] "a" "b" "c" "d" "e"
[1] 5
[1] a b
Levels: a b c d e

Regards
Petr
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#
You are mis-using factors. Would you pretend that women do not exist just because your sample happens to include only men?

If you really need to ignore those other levels, convert your factor to character and summarize those values.
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"???" <yczhang at nigpas.ac.cn> wrote:
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On 21 Jan 2014, at 15:58 , Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote:

            
Actually, just factor(fff) will do. Or droplevels(fff).
#
I think that length(unique(x)) is a more direct and easier to remember
way of determining the number of unique values in the vector x,
rather than nlevels(factor(x)).

Bill Dunlap
TIBCO Software
wdunlap tibco.com
#
On 22 Jan 2014, at 15:51 , William Dunlap <wdunlap at tibco.com> wrote:

            
However, it may make you forget the possibility of NA:
[1] 3
[1] 2

-pd