3 messages · Jim Maas, William Dunlap, David Winsemius
I've dug around but not been able to find anything, am probably missing something obvious. How can I fill a three-dimensional (or higher dimension) array by rows instead of columns. eg new1 <- array(c(1:125), c(5,5,5)) works fine for me but fills it by columns and new2 <- array(c(1:125), c(5,5,5), byrow=TRUE) throws an error. Am I missing something obvious? I also tried transposing the 3-d array but that didn't work either. TIA Jim
Dr. Jim Maas University of East Anglia
Use aperm on the output of array:
> aperm(array(1:8, dim=c(2,2,2)), perm=c(2,1,3))
, , 1
[,1] [,2]
[1,] 1 2
[2,] 3 4
, , 2
[,1] [,2]
[1,] 5 6
[2,] 7 8
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-----Original Message----- From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of Jim Maas Sent: Thursday, February 09, 2012 9:47 AM To: r-help at r-project.org Subject: [R] fill an array by rows I've dug around but not been able to find anything, am probably missing something obvious. How can I fill a three-dimensional (or higher dimension) array by rows instead of columns. eg new1 <- array(c(1:125), c(5,5,5)) works fine for me but fills it by columns and new2 <- array(c(1:125), c(5,5,5), byrow=TRUE) throws an error. Am I missing something obvious? I also tried transposing the 3-d array but that didn't work either. TIA Jim -- Dr. Jim Maas University of East Anglia
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I've dug around but not been able to find anything, am probably missing something obvious. How can I fill a three-dimensional (or higher dimension) array by rows instead of columns. eg new1 <- array(c(1:125), c(5,5,5)) works fine for me but fills it by columns and new2 <- array(c(1:125), c(5,5,5), byrow=TRUE) throws an error. Am I missing something obvious? I also tried transposing the 3-d array but that didn't work either.
You might want to look at aperm: Perhaps: new2 <- aperm(new1, c(2,1,3))
David Winsemius, MD West Hartford, CT