Skip to content

Submodel selection using dredge and gam (mgcv)

5 messages · Arnaud Mosnier, Kamil Bartoń

#
Hi,

I want to use dredge to test several gam submodels including interactions.
I tried to find a way in order to keep models with interaction only if the
single variables occurring in the interaction are also included.

i.e.: for
 y~s(x0)+s(x1)+ti(x0, x1)

I want to keep
y ~ s(x0)
y ~ s(x1)
y ~ s(x0) + s(x1)
y ~ s(x0) + s(x1) + ti(x0,x1)

and I want to remove

y ~ s(x0) + ti(x0,x1)
y ~ s(x1) + ti(x0,x1)
y ~ ti(x0,x1)


I know that I should use the "subset" option of the dredge function.
However, I can not find the correct matrix / expression to obtain what I
need !


Here a small example.

################

# Create some data (use mgcv example)
library(mgcv)
set.seed(2)
dat <- gamSim(1,n=400,dist="normal",scale=2)

# Create the global gam model
# Here a model with interaction. Note the use of ti()
bt <- gam(y~s(x0)+s(x1)+s(x2)+s(x3)+ti(x1,x2), data=dat,method="ML")

# Use dredge to test sub-models
library(MuMIn)
print(modstab <- dredge(bt))

# Here the 11th model include the interaction but do not include the single
variables x1 and x2
# ... I want to avoid that kind of model.
get.models(modstab, subset = 11)

################


Any help would be appreciated !

Arnaud
#
Hi Arnaud,
your question has in fact nothing to do with gam or model selection. 
What you are asking is: what is the logical expression that yields True 
when AB is False or both A and B are True. Now replace the words with 
operators (!AB | (A & B)) and voil?.

See also:
help("Logic", "base")
fortunes::fortune(350)

best,
kamil
On 2014-11-10 21:26, Arnaud Mosnier wrote:
1 day later
#
Hi Kamil,

Thanks for your answer. In fact, I already tried something with operators
in such a way you advise, but it seems more complicated due to the use of
the s() and ti() operators.

Can you provide a solution for the following example ?

library(mgcv)
set.seed(2)
dat <- gamSim(1,n=400,dist="normal",scale=2)

bt <- gam(y~s(x0)+s(x1)+ti(x0,x1), data=dat,method="ML")

library(MuMIn)

# this does not work
dredge(bt, subset = (!(x0,x1) | (x0 & x1)))
dredge(bt, subset = (!ti(x0,x1) | (s(x0) & s(x1))))

Cheers,

Arnaud


2014-11-11 4:11 GMT-05:00 Kamil Barto? <kamil.barton at o2.pl>:

  
  
#
Hi Arnaud,
please read ?dredge -> "Details" -> "Subsetting", where this is explained.
On 2014-11-12 15:19, Arnaud Mosnier wrote:
#
Argh ! Ok ... my fault ... the use of back-ticks was the solution !!!
Thanks,

Arnaud

2014-11-12 14:19 GMT-05:00 Kamil Barto? <kamil.barton at o2.pl>: