this is a bad question but I can't figure it out and i've tried. if i
sort the 2 column
matrix , temp1, by the first column, then things work as expected. But,
if I sort the 1 column matrix, temp2, then it gets turned coerced to a
vector. I realize that I
need to use drop=FALSE but i've put it in a few different places with no
success. Thanks.
temp1 <- matrix(rnorm(10),nc=2,nrow=5)
rownames(temp1) <- c("a","b","c","d","e")
print(temp2)
temp1 <- temp1[order(temp1[,1]),]
print(temp1)
temp2 <- matrix(rnorm(10),nc=1,nrow=5)
rownames(temp2) <- c("a","b","c","d","e","f","g","h","i")
print(temp2)
temp2 <- temp2[order(temp2[,1]),] # PROBLEM IS HERE
print(temp2)
sorting a matrix by the column
3 messages · Mark Leeds, Gabor Grothendieck, jim holtman
This is what I get:
temp2 <- matrix(rnorm(10),nc=1,nrow=5)
rownames(temp2) <- c("a","b","c","d","e","f","g","h","i")
Error in dimnames(x) <- dn : length of 'dimnames' [1] not equal to array extent
R.version.string
[1] "R version 2.8.1 Patched (2008-12-26 r47350)"
On Wed, Feb 11, 2009 at 1:18 AM, <markleeds at verizon.net> wrote:
this is a bad question but I can't figure it out and i've tried. if i sort
the 2 column
matrix , temp1, by the first column, then things work as expected. But,
if I sort the 1 column matrix, temp2, then it gets turned coerced to a
vector. I realize that I
need to use drop=FALSE but i've put it in a few different places with no
success. Thanks.
temp1 <- matrix(rnorm(10),nc=2,nrow=5)
rownames(temp1) <- c("a","b","c","d","e")
print(temp2)
temp1 <- temp1[order(temp1[,1]),]
print(temp1)
temp2 <- matrix(rnorm(10),nc=1,nrow=5)
rownames(temp2) <- c("a","b","c","d","e","f","g","h","i")
print(temp2)
temp2 <- temp2[order(temp2[,1]),] # PROBLEM IS HERE
print(temp2)
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Use 'drop=FALSE'
temp2 <- matrix(rnorm(10),nc=1)
rownames(temp2) <- c("a","b","c","d","e","f","g","h","i",'j')
print(temp2)
[,1] a -0.5686687 b -0.1351786 c 1.1780870 d -1.5235668 e 0.5939462 f 0.3329504 g 1.0630998 h -0.3041839 i 0.3700188 j 0.2670988
temp2 <- temp2[order(temp2[,1]),,drop=FALSE] # PROBLEM IS HERE print(temp2)
[,1] d -1.5235668 a -0.5686687 h -0.3041839 b -0.1351786 j 0.2670988 f 0.3329504 i 0.3700188 e 0.5939462 g 1.0630998 c 1.1780870
On Wed, Feb 11, 2009 at 1:18 AM, <markleeds at verizon.net> wrote:
this is a bad question but I can't figure it out and i've tried. if i sort
the 2 column
matrix , temp1, by the first column, then things work as expected. But,
if I sort the 1 column matrix, temp2, then it gets turned coerced to a
vector. I realize that I
need to use drop=FALSE but i've put it in a few different places with no
success. Thanks.
temp1 <- matrix(rnorm(10),nc=2,nrow=5)
rownames(temp1) <- c("a","b","c","d","e")
print(temp2)
temp1 <- temp1[order(temp1[,1]),]
print(temp1)
temp2 <- matrix(rnorm(10),nc=1,nrow=5)
rownames(temp2) <- c("a","b","c","d","e","f","g","h","i")
print(temp2)
temp2 <- temp2[order(temp2[,1]),] # PROBLEM IS HERE
print(temp2)
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem that you are trying to solve?