factor as seq() in for loop

	  Does the follow help?

 > aFactor <- factor(rep(letters[1:3], 1:3))
 > aFactor

[1] a b b c c c
Levels: a b c

 > for(af in levels(aFactor)){

+   print(sum(aFactor==af))
+ }
[1] 1
[1] 2
[1] 3

	  spencer graves

Tord Snall wrote:

Dear all,
I would like to use the values in vegaggr.BLMCMR02$colony 

str(vegaggr.BLMCMR02)
`data.frame':   1678 obs. of  3 variables:
$ vegtype       : Factor w/ 27 levels "2010","2020",..: 3 4 5 19 4 5 19

5  

$ colony        : Factor w/ 406 levels "0","1","10","100",..: 1 1 1 1 2

2 2 

$ Totvegproparea: num  0.00055 0.03956 0.95705 0.00284 0.05215 ...

as the seq in a for loop (for(var in seq)), and therefore first picked

them 

out as 
cols = aggregate(list(A = vegaggr.BLMCMR02$Totvegproparea), 
                list(colony = vegaggr.BLMCMR02$colony), sum)[,1]

str(cols)

 Factor w/ 406 levels "0","1","10","100",..: 1 2 3 4 5 6 7 8 9 10 ...

I next planned to transform cols using as.integer(cols). However, this

transformation gives a vector corresponding to

seq(from=1,to=length(cols)). 

Could someone please give advice on how to make use of a factor as the

seq 

in a for loop (which is strictly not allowed' according to ?Control).

Thanks!

Tord