That was exacly what i was looking for! Thanks a lot! Cheers! -- View this message in context: http://r.789695.n4.nabble.com/ifelse-reformulation-tp4645981p4645990.html Sent from the R help mailing list archive at Nabble.com.
ifelse reformulation
2 messages · brunosm, arun
HI, Try this: count40<- ifelse(test1$x3==40|test1$x4==40|test1$x5==40,0,1) count40 # [1] 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 as.vector(apply(test1,1,function(x) ifelse(any(x[4:6]==40),0,1))) # [1] 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 A.K. ----- Original Message ----- From: brunosm <brunosm87 at gmail.com> To: r-help at r-project.org Cc: Sent: Friday, October 12, 2012 10:18 AM Subject: Re: [R] ifelse reformulation That was exacly what i was looking for! Thanks a lot! Cheers! -- View this message in context: http://r.789695.n4.nabble.com/ifelse-reformulation-tp4645981p4645990.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.