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vector decreasing by a factor
3 messages · andre bedon, (Ted Harding), Uwe Ligges
On 02-May-11 07:55:27, andre bedon wrote:
Hi, I'm quite new to R so this question will sound quite fundamental. I need to create a vector of length 160. The first element should be (1+r)^159 and each element thereafter should decrease by a factor of (1+r) until the 160th element that should be 1. Is there a function similar to seq() but increasing or decreasing by factors? I need to do this in one step i.e, not using loops. Any help would be greatly appreciated. Regards, Andre
One expression which would do what you want is rev((1+r)^(0:159)) though there may be more efficient ways to do it. This assumes that r, hence (1+r), is given. If you are given the value X1 of the first element, which is to be interpreted as (1+r)^159, then perhaps take (1+r) as X1^(1/159), though there is a potential slight inaccuracy in recovering X0 from (1+r)^159. So check this first. Hoping this helps, Ted. -------------------------------------------------------------------- E-Mail: (Ted Harding) <ted.harding at wlandres.net> Fax-to-email: +44 (0)870 094 0861 Date: 02-May-11 Time: 09:50:55 ------------------------------ XFMail ------------------------------
On 02.05.2011 09:55, andre bedon wrote:
Hi, I'm quite new to R so this question will sound quite fundamental. I need to create a vector of length 160. The first element should be (1+r)^159 and each element thereafter should decrease by a factor of (1+r) until the 160th element that should be 1. Is there a function similar to seq() but increasing or decreasing by factors? I need to do this in one step i.e, not using loops. Any help would be greatly appreciated.
Yes: (1+r)^(159:0) Uwe Ligges
Regards, Andre [[alternative HTML version deleted]]
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