dear all,
i have a quite simple question, i want to fill up a Matrix like done in the
following function,
but the performance is very bad for large dimensions
is there a way to do this like with apply or something similar?
makeMatrix <- function(a, b,dim) {
X=matrix(0,ncol=dim,nrow=dim)
for (i in c(1:dim)){
for (j in c(1:dim)) {
if (i==j) {X[i,j]<-a}
else { X[i,j]<- exp(( -1*abs(i-j))/(3*b)) }
}
}
X
}
--
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fill Matrix quicker
5 messages · monk, Jean V Adams, Patrick Burns +1 more
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Most certainly you can speed it up: X <- exp(-abs(row(X) - col(X)) / (3*b)) diag(X) <- a should do what you want. This is called 'vectorization' and is discussed lots of places -- for instance, in the two documents mentioned below in my signature.
On 01/08/2011 19:12, monk wrote:
dear all,
i have a quite simple question, i want to fill up a Matrix like done in the
following function,
but the performance is very bad for large dimensions
is there a way to do this like with apply or something similar?
makeMatrix<- function(a, b,dim) {
X=matrix(0,ncol=dim,nrow=dim)
for (i in c(1:dim)){
for (j in c(1:dim)) {
if (i==j) {X[i,j]<-a}
else { X[i,j]<- exp(( -1*abs(i-j))/(3*b)) }
}
}
X
}
--
View this message in context: http://r.789695.n4.nabble.com/fill-Matrix-quicker-tp3710428p3710428.html
Sent from the R help mailing list archive at Nabble.com.
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Patrick Burns pburns at pburns.seanet.com twitter: @portfolioprobe http://www.portfolioprobe.com/blog http://www.burns-stat.com (home of 'Some hints for the R beginner' and 'The R Inferno')
thanks a lot , that will do the trick -- View this message in context: http://r.789695.n4.nabble.com/fill-Matrix-quicker-tp3710428p3710533.html Sent from the R help mailing list archive at Nabble.com.
On Aug 1, 2011, at 20:12 , monk wrote:
dear all,
i have a quite simple question, i want to fill up a Matrix like done in the
following function,
but the performance is very bad for large dimensions
is there a way to do this like with apply or something similar?
makeMatrix <- function(a, b,dim) {
X=matrix(0,ncol=dim,nrow=dim)
for (i in c(1:dim)){
for (j in c(1:dim)) {
if (i==j) {X[i,j]<-a}
else { X[i,j]<- exp(( -1*abs(i-j))/(3*b)) }
}
}
X
}
I'd go for something like X <- outer(1:dim, 1:dim, function(i,j) exp(-abs(i-j)/3/b)) diag(X) <- a
-- View this message in context: http://r.789695.n4.nabble.com/fill-Matrix-quicker-tp3710428p3710428.html Sent from the R help mailing list archive at Nabble.com.
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Peter Dalgaard, Professor, Center for Statistics, Copenhagen Business School Solbjerg Plads 3, 2000 Frederiksberg, Denmark Phone: (+45)38153501 Email: pd.mes at cbs.dk Priv: PDalgd at gmail.com "D?den skal tape!" --- Nordahl Grieg