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How to find the non matching vectors among these five, if so how we can find the non matching element of that vectors?

4 messages · Sri krishna Devarayalu Balanagu, Richard M. Heiberger, David Winsemius +1 more

Richard M. Heiberger
# 
This should get you started.

Rich


aa <- c(1,2,3)
bb <- c(1,2,3,4)
cc <- c(1,2,3)
dd <- c(1,2,3)
ee <- c(1,4,5)


outer.all.equal <- function(input.list) {
  nn <- names(input.list)
  if (is.null(nn)) stop("input must be a named list.")
  n <- length(input.list)
  result <- vector("list", n*n)
  dim(result) <- c(n, n)
  dimnames(result) <- list(nn, nn)

  for (i in nn)
    for (j in nn)
      result[[i, j]] <- all.equal(input.list[[i]], input.list[[j]])
  result
}

outer.all.equal.TRUE <- function(x) {
  y <- array(vector(length=length(x)), dim(x), dimnames(x))
  y[] <- sapply(result, function(x) length(x)==1 && x == TRUE)
  y
}

input.list <- list(aa=aa, bb=bb, cc=cc, dd=dd, ee=ee)
result <- outer.all.equal(input.list)

result
str(result)
outer.all.equal.TRUE(result)


On 9/6/12, Sri krishna Devarayalu Balanagu
<balanagudevarayulu at gvkbio.com> wrote:
David Winsemius
#
On Sep 6, 2012, at 1:40 AM, Sri krishna Devarayalu Balanagu wrote:

            

      
      
      
    

        
"non-matching" is not a well-defined mathematical expression. What is the "right answer" to you question?

            

      
      
      
    

        
The `identical function only takes two arguments.

For instance, does majority rule if there are multiple duplicated items?

            

      
      
      
    

        
This will identify the items that are identical to the first duplicated item:

list(a=a,b=b,c=c,d=d,e=e) %in% 
       list(a=a,b=b,c=c,d=d,e=e)[duplicated(  list(a=a,b=b,c=c,d=d,e=e) )][1]
[1]  TRUE FALSE  TRUE  TRUE FALSE

  
    

      
      
    

  


  


      

    

    

      
      

        


  

        

      arun
    

    

      
      #
    

  


  

      
Hi,
Try this:


list1<-list(a=a,b=b,c=c,d=d,e=e)
dat1<-as.matrix(do.call(rbind,lapply(list1,`[`,1:4)))
dat1[duplicated(dat1)|duplicated(dat1,fromLast=TRUE),]
? [,1] [,2] [,3] [,4]
#a??? 1??? 2??? 3?? NA
#c??? 1??? 2??? 3?? NA
#d??? 1??? 2??? 3?? NA

dat1[!(duplicated(dat1)|duplicated(dat1,fromLast=TRUE)),]
? #[,1] [,2] [,3] [,4]
#b??? 1??? 2??? 3??? 4
#e??? 1??? 4??? 5?? NA

which(!(duplicated(dat1)|duplicated(dat1,fromLast=TRUE)))
#[1] 2 5


dat2<-dat1[!(duplicated(dat1)|duplicated(dat1,fromLast=TRUE)),]

?do.call(rbind,apply(dat2,2,function(x)x[!(duplicated(x)|duplicated(x,fromLast=TRUE))]))
???? b? e
#[1,] 2? 4
#[2,] 3? 5
#[3,] 4 NA
A.K.

----- Original Message -----
From: Sri krishna Devarayalu Balanagu <balanagudevarayulu at gvkbio.com>
To: "r-help at r-project.org" <r-help at r-project.org>
Cc: 
Sent: Thursday, September 6, 2012 4:40 AM
Subject: [R] How to find the non matching vectors among these five, if so how we can find the non matching element of that vectors?

Hello,

Say all the below five vectors should have same elements in any situation.
How to find the non matching vectors among these five, if so how we can find the non matching elements of those vectors?
Can anyone help?

a=c(1,2,3)
b=c(1,2,3,4)
c=c(1,2,3)
d=c(1,2,3)
e=c(1,4,5)
identical(a,b,c,d,e)
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