Hi All,
I have a function like
my_func <- function(dataset)
{
some operation
}
Now I would like not only to operate on the dataset (how this is done is
obvious) but I would like to get the name of the dataset handed over as an
argument.
Example:
my_func <- function(dataset = iris)
{
print(dataset) # here I do not want to print the dataset but the name
of the object - iris in this case - instead
# quote() does not do the trick cause it prints "dataset" instead of
"iris"
# as.name() gives an error saying that the object can not coerced to a
symbol
}
Is there a way to do this?
Kind regards
Georg
Assessing the name of an object within an argument
5 messages · G.Maubach at weinwolf.de, Bert Gunter, Thomas Mailund +1 more
?
You can get that using `formals()`.
my_func <- function(dataset = iris)
{
? #print(dataset) # here I do not want to print the dataset but the name
? # of the object - iris in this case - instead
? print(formals()$dataset) # this is what you want
}
This gives you what the arguments were as an alist. It won?t always be a name, of course, but when it is, as in this case, that will be a symbol you can print.
Cheers
Thomas
On 10 January 2017 at 09:51:55, g.maubach at weinwolf.de (g.maubach at weinwolf.de(mailto:g.maubach at weinwolf.de)) wrote:
Hi All,
I have a function like
my_func <- function(dataset)
{
some operation
}
Now I would like not only to operate on the dataset (how this is done is
obvious) but I would like to get the name of the dataset handed over as an
argument.
Example:
my_func <- function(dataset = iris)
{
print(dataset) # here I do not want to print the dataset but the name
of the object - iris in this case - instead
# quote() does not do the trick cause it prints "dataset" instead of
"iris"
# as.name() gives an error saying that the object can not coerced to a
symbol
}
Is there a way to do this?
Kind regards
Georg
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
This is false. formals() gives the FORMAL argument list of the function, not the ACTUAL arguments supplied. That is obtained by the construction deparse(substitute(dataset)) The OP should consult a good R tutorial for this and other uses of substitute(), part of the "computing on the language" functionality of R. Bert
On Jan 10, 2017 4:04 AM, "Thomas Mailund" <mailund at birc.au.dk> wrote:
You can get that using `formals()`.
my_func <- function(dataset = iris)
{
#print(dataset) # here I do not want to print the dataset but the name
# of the object - iris in this case - instead
print(formals()$dataset) # this is what you want
}
This gives you what the arguments were as an alist. It won?t always be a
name, of course, but when it is, as in this case, that will be a symbol you
can print.
Cheers
Thomas
On 10 January 2017 at 09:51:55, g.maubach at weinwolf.de (g.maubach at weinwolf.de
(mailto:g.maubach at weinwolf.de)) wrote:
Hi All,
I have a function like
my_func <- function(dataset)
{
some operation
}
Now I would like not only to operate on the dataset (how this is done is
obvious) but I would like to get the name of the dataset handed over as an
argument.
Example:
my_func <- function(dataset = iris)
{
print(dataset) # here I do not want to print the dataset but the name
of the object - iris in this case - instead
# quote() does not do the trick cause it prints "dataset" instead of
"iris"
# as.name() gives an error saying that the object can not coerced to a
symbol
}
Is there a way to do this?
Kind regards
Georg
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/
posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Yes, I was too fast there, sorry. I sent a correction right after but must have picked Reply instead of Replay All. Cheers Thomas
On 10 January 2017 at 10:31:30, Bert Gunter (bgunter.4567 at gmail.com<mailto:bgunter.4567 at gmail.com>) wrote:
This is false. formals() gives the FORMAL argument list of the function, not the ACTUAL arguments supplied. That is obtained by the construction deparse(substitute(dataset)) The OP should consult a good R tutorial for this and other uses of substitute(), part of the "computing on the language" functionality of R. Bert
On Jan 10, 2017 4:04 AM, "Thomas Mailund" <mailund at birc.au.dk<mailto:mailund at birc.au.dk>> wrote:
You can get that using `formals()`.
my_func <- function(dataset = iris)
{
#print(dataset) # here I do not want to print the dataset but the name
# of the object - iris in this case - instead
print(formals()$dataset) # this is what you want
}
This gives you what the arguments were as an alist. It won?t always be a name, of course, but when it is, as in this case, that will be a symbol you can print.
Cheers
Thomas
On 10 January 2017 at 09:51:55, g.maubach at weinwolf.de<mailto:g.maubach at weinwolf.de> (g.maubach at weinwolf.de<mailto:g.maubach at weinwolf.de>(mailto:g.maubach at weinwolf.de<mailto:g.maubach at weinwolf.de>)) wrote:
Hi All,
I have a function like
my_func <- function(dataset)
{
some operation
}
Now I would like not only to operate on the dataset (how this is done is
obvious) but I would like to get the name of the dataset handed over as an
argument.
Example:
my_func <- function(dataset = iris)
{
print(dataset) # here I do not want to print the dataset but the name
of the object - iris in this case - instead
# quote() does not do the trick cause it prints "dataset" instead of
"iris"
# as.name<http://as.name>() gives an error saying that the object can not coerced to a
symbol
}
Is there a way to do this?
Kind regards
Georg
______________________________________________ R-help at r-project.org<mailto:R-help at r-project.org> mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
______________________________________________ R-help at r-project.org<mailto:R-help at r-project.org> mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
You might find http://adv-r.had.co.nz/Computing-on-the-language.html helpful. Hadley
On Tue, Jan 10, 2017 at 2:49 AM, <G.Maubach at weinwolf.de> wrote:
Hi All,
I have a function like
my_func <- function(dataset)
{
some operation
}
Now I would like not only to operate on the dataset (how this is done is
obvious) but I would like to get the name of the dataset handed over as an
argument.
Example:
my_func <- function(dataset = iris)
{
print(dataset) # here I do not want to print the dataset but the name
of the object - iris in this case - instead
# quote() does not do the trick cause it prints "dataset" instead of
"iris"
# as.name() gives an error saying that the object can not coerced to a
symbol
}
Is there a way to do this?
Kind regards
Georg
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.