Hi, Ive been trying to write a program for bootstrapping residuals in R but
without much success.
A lecturer wants to predict the performance of students in an end-of-year
physics exam, y. The lecturer has the students results from a mid-term
physics exam, x, and a mid-term biology exam, z.
He proposes the following linear model for the end-of-year exam result
yi = ? + ?xi + ?zi + qi, where q is the error.
Y is a matrix of the data and we have y=first column of the data and
X=second 2 columns(the x & z data)
Now I need to write a program for obtaining bootstrap estimates, i have:
x=scan(data)
Y=matrix(x,ncol=3,byrow=T)
y=Y[,1]
X=Y[,2:3]
ls=lsfit(X,y)
beta=ls$coef
yest=beta[1]+beta[2]*X[,1]+beta[3]*X[,2]
res=y-yest
boot=function(X,res,beta,b)
{
n=24
output=matrix(0,ncol=2,nrow=b)
for(i in 1:b)
{
error=sample(res,n,replace=T)
ystar=beta[1]+beta[2]*X[,1]+beta[3]*X[,2]+error
ls=lsfit(X,ystar)
output[i,]=ls$coef
}
output
}
I think the first 8 lines are right but my function might be wrong?
Any help?
--
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Bootstrapping for residuals
4 messages · bubbles1990, David Winsemius
On Nov 30, 2011, at 11:31 AM, bubbles1990 wrote:
Hi, Ive been trying to write a program for bootstrapping residuals
in R but
without much success.
A lecturer wants to predict the performance of students in an end-of-
year
physics exam, y. The lecturer has the students results from a mid-term
physics exam, x, and a mid-term biology exam, z.
He proposes the following linear model for the end-of-year exam result
yi = ? + ?xi + ?zi + qi, where q is the error.
Y is a matrix of the data and we have y=first column of the data and
X=second 2 columns(the x & z data)
Now I need to write a program for obtaining bootstrap estimates, i
have:
x=scan(data)
Y=matrix(x,ncol=3,byrow=T)
y=Y[,1]
X=Y[,2:3]
ls=lsfit(X,y)
beta=ls$coef
yest=beta[1]+beta[2]*X[,1]+beta[3]*X[,2]
res=y-yest
boot=function(X,res,beta,b)
{
n=24
output=matrix(0,ncol=2,nrow=b)
for(i in 1:b)
{
error=sample(res,n,replace=T)
ystar=beta[1]+beta[2]*X[,1]+beta[3]*X[,2]+error
ls=lsfit(X,ystar)
output[i,]=ls$coef
}
output
}
I think the first 8 lines are right but my function might be wrong?
Any help?
You should ask your instructor or teaching assistant for help.
David Winsemius, MD West Hartford, CT
I study a part-time long distance learning course so only really have access to online sources for help, i'm sure ill crack it eventually. I understand how to do it with 2 variables, its just having 3 that is confusing me -- View this message in context: http://r.789695.n4.nabble.com/Bootstrapping-for-residuals-tp4123657p4125325.html Sent from the R help mailing list archive at Nabble.com.
On Nov 30, 2011, at 11:31 AM, bubbles1990 wrote:
Hi, Ive been trying to write a program for bootstrapping residuals in R but without much success. A lecturer wants to predict the performance of students in an end-of- year physics exam, y. The lecturer has the students results from a mid-term physics exam, x, and a mid-term biology exam, z. He proposes the following linear model for the end-of-year exam result yi = ? + ?xi + ?zi + qi, where q is the error. Y is a matrix of the data and we have y=first column of the data and X=second 2 columns(the x & z data) Now I need to write a program for obtaining bootstrap estimates,
You replied but included no context, a common and not appreciated (in both senses of that verb) failing in posts from Nabble. My question would be: bootstrap estimate ... of what?
David.
> i have:
>
> x=scan(data)
> Y=matrix(x,ncol=3,byrow=T)
> y=Y[,1]
> X=Y[,2:3]
>
> ls=lsfit(X,y)
> beta=ls$coef
>
> yest=beta[1]+beta[2]*X[,1]+beta[3]*X[,2]
> res=y-yest
>
> boot=function(X,res,beta,b)
> {
> n=24
> output=matrix(0,ncol=2,nrow=b)
> for(i in 1:b)
> {
> error=sample(res,n,replace=T)
> ystar=beta[1]+beta[2]*X[,1]+beta[3]*X[,2]+error
> ls=lsfit(X,ystar)
> output[i,]=ls$coef
> }
> output
> }
>
> I think the first 8 lines are right but my function might be wrong?
> Any help?
>
> --
> View this message in context: http://r.789695.n4.nabble.com/Bootstrapping-for-residuals-tp4123657p4123657.html
> Sent from the R help mailing list archive at Nabble.com.
>
David Winsemius, MD
West Hartford, CT