6 messages · cm, Uwe Ligges, michael.weylandt at gmail.com (R. Michael Weylandt +1 more
I have data X and Y, and I want to predict what the very next point would be based off the model. This is what I have:
model=lm(x~y)
I think I want to use the predict function, but I'm not exactly sure what to do. Thank you! -- View this message in context: http://r.789695.n4.nabble.com/Linear-Model-Prediction-tp4637644.html Sent from the R help mailing list archive at Nabble.com.
I have data X and Y, and I want to predict what the very next point would be based off the model. This is what I have:
model=lm(x~y)
Hmmm, are you sure about the above code?
I think I want to use the predict function, but I'm not exactly sure what to do.
Yes, use predict(). Is this homework? Uwe Ligges
Thank you! -- View this message in context: http://r.789695.n4.nabble.com/Linear-Model-Prediction-tp4637644.html Sent from the R help mailing list archive at Nabble.com.
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
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How do I set it up? Because when I do predict(model) I get a ton of points, not just one.
You need to supply newdata= . predict() without new data gives predicted values for the predictors you for the model to. Incidentally, repeating Uwe -- are you sure you want x~y ? Michael
----- Original Message ----- From: "Uwe Ligges-3 [via R]" Date: Tuesday, July 24, 2012 2:28 pm Subject: Re: Linear Model Prediction To: cm
On 24.07.2012 20:20, cm wrote:
I have data X and Y, and I want to predict what the very next
point would be
based off the model. This is what I have:
model=lm(x~y)
Hmmm, are you sure about the above code?
I think I want to use the predict function, but I'm not
exactly sure what to
do.
Yes, use predict(). Is this homework? Uwe Ligges
Thank you! -- View this message in context:
Sent from the R help mailing list archive at Nabble.com.
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-
project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
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Yes, why wouldn't I? It's a linear model between two sets of data: x and y. Also, what would the new data be if i want to predict into the future? So, for example, the data goes from a month ago to today. I want to predict what tomorrow's data would be. So what is "newdata"? -- View this message in context: http://r.789695.n4.nabble.com/Linear-Model-Prediction-tp4637644p4637660.html Sent from the R help mailing list archive at Nabble.com.
Hello,
The example below gives you some information about using predict().?? This was originally used to predict NAs.
dat1<-data.frame(Year=1962:1986,Discharge=c(rnorm(15,25),rep(NA,5),1:5))
lm1<-lm(Discharge~Year,dat1)
dat2<-data.frame(Year=dat1[,1])
dat1$fit<-predict(lm1,newdata=dat2)
#The code below is to replace the NA values with predicted.
#dat1<-within(dat1,{Dischargenew<-ifelse(is.na(Discharge)==T,fit,Discharge)})
#dat1new<-dat1[,c(1:2,4)]
A.K.
----- Original Message -----
From: cm <bunnylover23 at optonline.net>
To: r-help at r-project.org
Cc:
Sent: Tuesday, July 24, 2012 2:20 PM
Subject: [R] Linear Model Prediction
I have data X and Y, and I want to predict what the very next point would be
based off the model. This is what I have:
model=lm(x~y)
I think I want to use the predict function, but I'm not exactly sure what to do. Thank you! -- View this message in context: http://r.789695.n4.nabble.com/Linear-Model-Prediction-tp4637644.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.