Hi, In case of paired data, if you have only differencies and not original data you can get this t test based on differencies: Say d is the vector with differencies data and suppose you wish to test if the mean of differency is equal to zero: md<-mean(d) ## sample mean of differencies sdd<-sd(d) ## sample sd of differencies n<-length(d) ## sample size t.value<-(md/(sdd/sqrt(n))) ## sample t-value with n-1 df pt(t.value,n-1,lower.tail=FALSE) ## p-value of test
set.seed(13) d<-rnorm(50) md<-mean(d) ## sample mean of differencies sdd<-sd(d) ## sample sd of differencies n<-length(d) ## sample size t.value<-(md/(sdd/sqrt(n))) ## sample t-value with
n-1 df
pt(t.value,n-1,lower.tail=FALSE) ## p-value of test
[1] 0.5755711 Best regards, Vito
Steven F. Freeman wrote:
I'd like to do a t-test to compare the Delta values of
items with Crit=1
with Delta values of items with Crit=0. What is the
t.test syntax?
It should produce a result like this below (I can't
get in touch with the
person who originally did this for me)
Welch Two Sample t-test
data: t1$Delta by Crit
t = -3.4105, df = 8.674, p-value = 0.008173
alternative hypothesis: true
difference in means is not equal to 0
95 percent confidence interval:
-0.04506155 -0.00899827
sample estimates:
mean in group FALSE mean in group TRUE
0.03331391 0.06034382
Thanks.
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