6 messages · oliver, Earl F. Glynn, Barry Rowlingson +2 more
Hello, please look here: =================================================================
sprintf("%03s", as.character(1:5))
[1] " 1" " 2" " 3" " 4" " 5"
================================================================= There should be a leading "0" isntead of space-chars?! I use R version 2.6.2 (2008-02-08) Ciao, Oliver
"Oliver Bandel" <oliver at first.in-berlin.de> wrote in message news:1221513552.6194.5.camel at calcman...
Hello,
sprintf("%03s", as.character(1:5))
[1] " 1" " 2" " 3" " 4" " 5"
Would this be OK as an alternative?
sprintf("%3.3d", 1:5)
[1] "001" "002" "003" "004" "005" efg Earl F. Glynn Scientific Programmer Stowers Institute for Medical Research
2008/9/15 Oliver Bandel <oliver at first.in-berlin.de>:
sprintf("%03s", as.character(1:5))
[1] " 1" " 2" " 3" " 4" " 5"
================================================================= There should be a leading "0" isntead of space-chars?!
In R, sprintf is a wrapper for the C printf functions, and if you read the C man page it says this about the 0 prefix: 0 The value should be zero padded. For d, i, o, u, x, X, a, A, e, E, f, F, g, and G conversions, the converted value is padded on the left with zeros rather than blanks. If the 0 and - flags both appear, the 0 flag is ignored. For other conversions, the behavior is undefined. Interestingly R seems to pad with spaces (like yours), but my cygwin C version pads with zeroes. Such is the nature of undefined behaviour! Barry
Try
sprintf("%03.0f", 1:5)
formatC(1:5, width=3, flag="0")
Regards, Adai
Hello, please look here: =================================================================
sprintf("%03s", as.character(1:5))
[1] " 1" " 2" " 3" " 4" " 5" ================================================================= There should be a leading "0" isntead of space-chars?! I use R version 2.6.2 (2008-02-08) Ciao, Oliver
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
On Mon, Sep 15, 2008 at 2:19 PM, Oliver Bandel
Hello, please look here: =================================================================
sprintf("%03s", as.character(1:5))
[1] " 1" " 2" " 3" " 4" " 5"
================================================================= There should be a leading "0" isntead of space-chars?!
No, the '0' flag only applies to numeric types (e.g. 'd'), and you specify a string. Instead, you want to do something like:
sprintf("%03d", 1:5)
[1] "001" "002" "003" "004" "005" /Henrik
I use R version 2.6.2 (2008-02-08) Ciao, Oliver
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Zitat von Henrik Bengtsson <hb at stat.berkeley.edu>:
On Mon, Sep 15, 2008 at 2:19 PM, Oliver Bandel <oliver at first.in-berlin.de> wrote:
Hello, please look here: =================================================================
sprintf("%03s", as.character(1:5))
[1] " 1" " 2" " 3" " 4" " 5"
================================================================= There should be a leading "0" isntead of space-chars?!
No, the '0' flag only applies to numeric types (e.g. 'd'), and you specify a string. Instead, you want to do something like:
sprintf("%03d", 1:5)
[1] "001" "002" "003" "004" "005"
[...] Oh, well... ok. Thanks to all. :) Ciao, Oliver