Hi all, Sorry for what might be a trivial issue. However, I am
completely flummoxed!
I'm making a filled contour plot for a publication. It's a continuous
wavelet transform should anybody care. The problem I'm having is
correctly demarking the ticks on the y axis. I have a matrix that has
100 columns. Every 10th column represents a power of 2. So:
col[10] <- 2
col[20] <- 4
col[30] <- 8
and so on until col[100] <- 2^10
I'm having trouble scaling my plot accordingly. Can anybody help? I
imagine that one uses the plot.axes argument but I'm having trouble
figuring out how to do it. The matrix is already a log scale so the
ticks and numbers are evenly spaced by 10.
Thanks in advance, Andy
Example:
junk.mat <- matrix(rnorm(12800), 128, 100)
xYears <- 1:nrow(junk.mat)
yPeriod <- 1:ncol(junk.mat)
filled.contour(xYears,
yPeriod,
junk.mat,
color = terrain.colors)
#? plot.axes = { axis(2, seq(??))}
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filled.contour - plot.axes
6 messages · Andy Bunn, Mohamed A. Kerasha, Paul Gilbert +2 more
Hi all, Does any one know if there is Kalman Filter code or library in R. Thanks, Mohamed. -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._
"Mohamed A. Kerasha" wrote:
Hi all, Does any one know if there is Kalman Filter code or library in R.
In addition to the code in package ts there is multivariate Kalman filter and smoother code in the dse bundle on CRAN. See help(l.SS, package=dse1) or the Users' Guide. (I believe there is also Kalman filter code in one or two other packages.) Paul Gilbert -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._
1 day later
Dear list readers,
This question is concerned with the use of the chisq.test() in R.
A test was conducted to determine the difference between 2 samples A and
B. Column I consisted of correct and incorrect assessment of 30 matched
pairs (AA or BB) , whereas column II consisted of correct and incorrect
assessment of 30 unmatched pairs (AB or BA). This example is given in a
book on the sensory evaluation techniques. The author's did not use
Yate?s correction for continuity in their analysis of the data.
I am trying to decide whether Yate?s correction for continuity should be
used when analysing a 2x2 contigency table using the chi-square test. I
have found conflicting views in literature with some people for and
others against. The analysis with or without Yate?s correction gives
conflicting results.
> x <- matrix(c(17, 13, 9, 21), nc = 2)
> chisq.test(x,correct = TRUE)
Pearson's Chi-squared test with Yates' continuity correction
data: x
X-squared = 3.3258, df = 1, p-value = 0.0682
> chisq.test(x,correct = F)
Pearson's Chi-squared test
data: x
X-squared = 4.3439, df = 1, p-value = 0.03714
>
The same data analysed using Fisher's exact test is similar to the
chi-square with Yate?s correction
> fisher.test(x)
Fisher's Exact Test for Count Data
data: x
p-value = 0.06728
alternative hypothesis: true odds ratio is not equal to 1
95 percent confidence interval:
0.9354766 10.1716022
sample estimates:
odds ratio
2.992580
I suppose looking at the results, the correct conclusion should be taken
using the correction for continuity. In fact, the statistics books I
have read suggest the use of Yate?s correction for continuity. (for
example, Nonparametric statistics - Sidney Siegel and John Castellan 1988)
I would like to hear anyone's view on this, especially statisticians.
Thanks in advance
Peter
----------------------------------
ISR-Porto
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On Wed, 20 Nov 2002 21:51:56 +0000
Peter Ho <peter at fe.up.pt> wrote:
Dear list readers, This question is concerned with the use of the chisq.test() in R. A test was conducted to determine the difference between 2 samples A and B. Column I consisted of correct and incorrect assessment of 30 matched pairs (AA or BB) , whereas column II consisted of correct and incorrect assessment of 30 unmatched pairs (AB or BA). This example is given in a book on the sensory evaluation techniques. The author's did not use used when analysing a 2x2 contigency table using the chi-square test. I have found conflicting views in literature with some people for and conflicting results.
> x <- matrix(c(17, 13, 9, 21), nc = 2) > chisq.test(x,correct = TRUE)
Pearson's Chi-squared test with Yates' continuity correction
data: x
X-squared = 3.3258, df = 1, p-value = 0.0682
> chisq.test(x,correct = F)
Pearson's Chi-squared test
data: x
X-squared = 4.3439, df = 1, p-value = 0.03714
>
The same data analysed using Fisher's exact test is similar to the
> fisher.test(x)
Fisher's Exact Test for Count Data
data: x
p-value = 0.06728
alternative hypothesis: true odds ratio is not equal to 1
95 percent confidence interval:
0.9354766 10.1716022
sample estimates:
odds ratio
2.992580
I suppose looking at the results, the correct conclusion should be taken
using the correction for continuity. In fact, the statistics books I
example, Nonparametric statistics - Sidney Siegel and John Castellan 1988)
I would like to hear anyone's view on this, especially statisticians.
Thanks in advance
Peter
----------------------------------
ISR-Porto
In general you use Yates' correction if you want the results to be conservative as with Fisher's "exact" test. I generally use the chi-square test without continuity correction. The price of "exact" tests (those that guarantee the type I error is no greater than a set value) is conservatism. I prefer tests that get closest to the target alpha value even if they exceed it a little bit on occasion. This kind of question would be slightly more appropriate for the sci.stat.consult Usenet news group.
Frank E Harrell Jr Prof. of Biostatistics & Statistics Div. of Biostatistics & Epidem. Dept. of Health Evaluation Sciences U. Virginia School of Medicine http://hesweb1.med.virginia.edu/biostat -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._
Thanks for the reply Frank. I will in future send these types of questions to sci.stat.consult Usenet news group, of which I was not previously aware of. The interersting point about the two results, is the fact that the null hypothesis is not rejected using Yate's correction, but is rejected without Yate's correction. at 5% level of significance. I guess this will be better answered in sci.stat.consult . Thanks again Peter ---------------------------- ISR-Porto
Frank E Harrell Jr wrote:
On Wed, 20 Nov 2002 21:51:56 +0000 Peter Ho <peter at fe.up.pt> wrote:
Dear list readers, This question is concerned with the use of the chisq.test() in R. A test was conducted to determine the difference between 2 samples A and B. Column I consisted of correct and incorrect assessment of 30 matched pairs (AA or BB) , whereas column II consisted of correct and incorrect assessment of 30 unmatched pairs (AB or BA). This example is given in a book on the sensory evaluation techniques. The author's did not use used when analysing a 2x2 contigency table using the chi-square test. I have found conflicting views in literature with some people for and conflicting results.
x <- matrix(c(17, 13, 9, 21), nc = 2) chisq.test(x,correct = TRUE)
Pearson's Chi-squared test with Yates' continuity correction
data: x
X-squared = 3.3258, df = 1, p-value = 0.0682
chisq.test(x,correct = F)
Pearson's Chi-squared test
data: x
X-squared = 4.3439, df = 1, p-value = 0.03714
The same data analysed using Fisher's exact test is similar to the
fisher.test(x)
Fisher's Exact Test for Count Data
data: x
p-value = 0.06728
alternative hypothesis: true odds ratio is not equal to 1
95 percent confidence interval:
0.9354766 10.1716022
sample estimates:
odds ratio
2.992580
I suppose looking at the results, the correct conclusion should be taken
using the correction for continuity. In fact, the statistics books I
example, Nonparametric statistics - Sidney Siegel and John Castellan 1988)
I would like to hear anyone's view on this, especially statisticians.
Thanks in advance
Peter
----------------------------------
ISR-Porto
In general you use Yates' correction if you want the results to be conservative as with Fisher's "exact" test. I generally use the chi-square test without continuity correction. The price of "exact" tests (those that guarantee the type I error is no greater than a set value) is conservatism. I prefer tests that get closest to the target alpha value even if they exceed it a little bit on occasion. This kind of question would be slightly more appropriate for the sci.stat.consult Usenet news group.
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