> Date: Mon, 31 Mar 2008 08:47:48 -0400
> From: murdoch at stats.uwo.ca
> To: pisicandru at hotmail.com
> CC: r-help at r-project.org
> Subject: Re: [R] unexpected GAM result - at least for me!
>
> On 3/31/2008 8:34 AM, Monica Pisica wrote:
> >
> > Hi
> >
> >
> > I am afraid i am not understanding something very fundamental....
and does not matter how much i am looking into the book "Generalized
Additive Models" of S. Wood i still don't understand my result.
> >
> > I am trying to model presence / absence (presence = 1, absence = 0)
of a species using some lidar metrics (i have 4 of these). I am using
different models and such .... and when i used gam i got this very weird
(for me) result which i thought it is not possible - or i have no idea
how to interpret it.
> >> can3.gam <- gam(can>0~s(be)+s(crr)+s(ch)+s(home), family = 'binomial')
> >> summary(can3.gam)
> > Family: binomial
> > Link function: logit
> > Formula:
> > can> 0 ~ s(be) + s(crr) + s(ch) + s(home)
> > Parametric coefficients:
> > Estimate Std. Error z value Pr(>|z|)
> > (Intercept) 85.39 162.88 0.524 0.6
> > Approximate significance of smooth terms:
> > edf Est.rank Chi.sq p-value
> > s(be) 1.000 1 0.100 0.751
> > s(crr) 3.929 8 0.380 1.000
> > s(ch) 6.820 9 0.396 1.000
> > s(home) 1.000 1 0.314 0.575
> > R-sq.(adj) = 1 Deviance explained = 100%
> > UBRE score = -0.81413 Scale est. = 1 n = 148
> >
> > Is this a perfect fit with no statistical significance, an
over-estimating or what???? It seems that the significance of the
smooths terms is "null". Of course with such a model i predict perfectly
presence / absence of species.
> >
> > Again, i hope you don't mind i'm asking you this. Any explanation
will be very much appreciated.
>
> Look at the data. You can get a perfect fit to a logistic regression
> model fairly easily, and it looks as though you've got one. (In fact,
> the huge intercept suggests that all predictions will be 1. Do you
> actually have any variation in the data?)
>
> Duncan Murdoch