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'par mfrow' and not filling horizontally

8 messages · Greg Snow, William Dunlap, Marc Schwartz +4 more

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Greetings, Folks.
I'd appreciate being shown the way out of this one!
I've been round the documentation in ever-drecreasing
circles, and along other paths, without stumbling on
the answer.

The background to the question can be exemplified by
the example (no graphics window open to start with):

  set.seed(54321)
  X0 <- rnorm(50) ; Y0 <- rnorm(50)

  par(mfrow=c(2,1),mfg=c(1,1),cex=0.5)
  plot(X0,Y0,pch="+",col="blue",xlim=c(-3,3),ylim=c(-3,3),
  xlab="X",ylab="Y",main="My Plot",asp=1)

  par(mfg=c(2,1))
  plot(X0,Y0,pch="+",col="blue",xlim=c(-3,3),ylim=c(-3,3),
  xlab="X",ylab="Y",main="My Plot",asp=1)

As you will see, both plots have been extended laterally
to fill the plotting area horizontally, hence extend from
approx X = -8 to approx X = +8 (on my X11 display), despite
the xlim=c(-3,3); however, the "ylim=c(-3,3)" has been
respected, as has "asp=1".

What I would like to see, independently of the shape of
the graphics window, is a pair of square plots, each with
X and Y ranging from -3 to 3, even if this leaves empty
space in the graphics window on either side.

Hints?

With thanks,
Ted.

--------------------------------------------------------------------
E-Mail: (Ted Harding) <Ted.Harding at manchester.ac.uk>
Fax-to-email: +44 (0)870 094 0861
Date: 08-Sep-10                                       Time: 20:01:19
------------------------------ XFMail ------------------------------
#
Look at the squishplot function in the TeachingDemos package.
#
Try par(pty="s").

Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
#
On Sep 8, 2010, at 2:01 PM, Ted Harding wrote:

            
Ted, 

Try this:

 set.seed(54321)
 X0 <- rnorm(50) ; Y0 <- rnorm(50)

 # add pty = "s"
 par(mfrow=c(2, 1), mfg = c(1, 1), cex = 0.5,
     pty = "s")  

 plot(X0, Y0, pch = "+", col = "blue",
      xlim = c(-3, 3), ylim = c(-3, 3),
      xlab = "X", ylab = "Y", main = "My Plot",
      asp = 1)

 par(mfg = c(2, 1))
 plot(X0, Y0, pch = "+", col = "blue", 
      xlim= c(-3, 3), ylim = c(-3, 3),
      xlab = "X", ylab = "Y", main = "My Plot",
      asp = 1)


See ?par and 'pty', which defaults to "m".

HTH,

Marc Schwartz
#
Ted:

?layout

Is this close to what you want?

layout(matrix(1:2, nrow=2),wid=1,heigh=c(1,1), resp= TRUE)

 set.seed(54321)
 X0 <- rnorm(50) ; Y0 <- rnorm(50)

 plot(X0,Y0,pch="+",col="blue",xlim=c(-3,3),ylim=c(-3,3),
 xlab="X",ylab="Y",main="My Plot",asp=1)

 plot(X0,Y0,pch="+",col="blue",xlim=c(-3,3),ylim=c(-3,3),
 xlab="X",ylab="Y",main="My Plot",asp=1)


On Wed, Sep 8, 2010 at 12:01 PM, Ted Harding
<Ted.Harding at manchester.ac.uk> wrote:

  
    
#
On 08-Sep-10 19:16:15, Bert Gunter wrote:
Thanks Greg, William, Marc & Bert for the suggestions. It seems
that Bert's suggestion of 'layout' may work best for my real example
(the one I posted was a simple one). It is also necessary to add
par(pty="s").

Greg: I must study squishplot() -- it looks useful.

William, Marc: I had tried pty="s" in my real example (I inadvertently
omitted it from the dummy example I posted), but it still did not
work -- see Case B of the real example below.

Anyway, here is an instance of the real problem. DISCLAIMER: This
is being done as an "exploration of concept" and does not necessarily
represent my true state of mind ...

## Code common to all approaches (Alterbative continuations A and B):
library(MASS)
M <- 10 ; N <- 2  ; plur <- "'s"
set.seed(54321)
mu <- (-3)+6*(0:(M-1))/(M-1)
mu <- rep(mu, N)   ## M evenly spaced on (-3,3)
Y <- matrix(rnorm(M*N,mean=mu),ncol=N) ## N Y's for each mu
KDE <- kde2d(x=mu, y=Y, h=2.5,  n=100, lims=c(-5,5,-5,5,-5.0,5.0))
S.x <- KDE$x ; S.y <- KDE$y ; S.z <- KDE$z
## For each value of Y in the KDE grid, find the mu with max KDE:
Mxs <- numeric(100)
for(j in (1:100)){ Mxs[j] <- S.x[which(S.z[,j]==max(S.z[,j]))] }

## A: Using Bert's 'layout' approach with pty="s" as well:
layout(matrix(1:2, nrow=2),wid=1,height=c(1,1), resp=TRUE)
par(cex=0.5,pty="s")

plot(mu,Y,pch="+",col="blue",asp=1,xlim=c(-5,5),ylim=c(-5,5),
     xlab="True mu", ylab="Sampled Y's",
     main=paste("KDE for (mu,Y)    ",
     M," mu's, ",N," Y",plur," per mu",sep=""))
contour(S.x, S.y, S.z, nlevels=7, drawlabels=FALSE, add=TRUE)
lines(S.x,S.y,col="green")
for(j in (1:100)){ Mxs[j] <- S.x[which(S.z[,j]==max(S.z[,j]))] }
lines(Mxs,S.x,col="red")

plot(S.x[1:100],Mxs[1:100],asp=1,pch="+",col="red",
xlim=c(-5,5),ylim=c(-5,5),
xlab="Future Observed Y",ylab="MLE of mu by KDE",
main="MLE of mu by KDE for this Sim vs Future Y")
lines(c(-3,3),c(-3,3),col="green")
lines(c(-3,-3),c(-3,3)) ; lines(c( 3, 3),c(-3,3))
text(0,3.5,"<-- Range of True mu used -->")

##C: Using par(pty="s") with par(mfrow) leaving out 'layout':
plot.new()
par(mfrow=c(2,1),mfg=c(1,1),cex=0.5,pty="s")
plot(mu,Y,pch="+",col="blue",asp=1,xlim=c(-5,5),ylim=c(-5,5),
     xlab="True mu", ylab="Sampled Y's",pty="s",
     main=paste("KDE for (mu,Y)    ",
     M," mu's, ",N," Y",plur," per mu",sep=""))
contour(S.x, S.y, S.z, nlevels=7, drawlabels=FALSE, add=TRUE)
lines(S.x,S.y,col="green")
for(j in (1:100)){ Mxs[j] <- S.x[which(S.z[,j]==max(S.z[,j]))] }
lines(Mxs,S.x,col="red")

par(mfg=c(2,1))
plot(S.x[1:100],Mxs[1:100],asp=1,pch="+",col="red",
xlim=c(-5,5),ylim=c(-5,5),
xlab="Future Observed Y",ylab="MLE of mu by KDE",
main="MLE of mu by KDE for this Sim vs Future Y")
lines(c(-3,3),c(-3,3),col="green")
lines(c(-3,-3),c(-3,3)) ; lines(c( 3, 3),c(-3,3))
text(0,3.5,"<-- Range of True mu used -->")
#################################################

Anyway, thanks! It has helped.
Ted.

--------------------------------------------------------------------
E-Mail: (Ted Harding) <Ted.Harding at manchester.ac.uk>
Fax-to-email: +44 (0)870 094 0861
Date: 08-Sep-10                                       Time: 21:39:53
------------------------------ XFMail ------------------------------
#
remove your asp=1 and try again to see if that is what you want.

On Wed, Sep 8, 2010 at 3:01 PM, Ted Harding
<Ted.Harding at manchester.ac.uk> wrote: