Skip to content

evaluating string variables

9 messages · Leonardo Sepulveda Durán, Sean O'Riordain, Dimitris Rizopoulos +4 more

#
Hello!!!

I have a folder (C:/R/) with matrix files, named by number, i.e.
0.mat, 1.mat,...,1250.mat. In this case, they are 5x5 simetric
matrices. I would like to compute a property for each matrix and put
calculated values into a data frame for posterior ploting and
printing. Below there is an example for 7 matrices (0.mat..6.mat)

#define data frame
L <- data.frame(frame=numeric(7), L=numeric(7))
f0<-1/(5*(5-1)) # first variable for computation

#loop over matrices, Open it , calculate property and put into data frame
for(i in 0:6){
	m<-matrix(scan('C:/R/i.mat', n=5*5),5,5, byrow=TRUE) # load matrix
	f1<-geodist(m)                                                           
	f2<-sum(colSums(f1$gdist))                                        
	l <-f0*f2                                                            
       # Calculate property
	L[i+1, ]<-c(i,l)                                                     
      # Fill data frame
}

but the matrix cannot be loaded, because it try to open a file named
"i.mat". I don`t know how to loop with a counter named 'i', and use it
to define the name of the file too. How can i do it? I have not found
the way.
 
Leonardo
#
use paste() to construct the file name 
e.g. fn <- paste(i,".mat",sep="")

Sean
On 12/08/05, Leonardo Sepulveda Dur??n <leonardosepulveda at gmail.com> wrote:
#
look at ?paste(), e.g.,

paste("C:/R/", i, "mat", sep = "")

I hope it helps.

Best,
Dimitris

----
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven

Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/16/336899
Fax: +32/16/337015
Web: http://www.med.kuleuven.be/biostat/
     http://www.student.kuleuven.be/~m0390867/dimitris.htm


----- Original Message ----- 
From: "Leonardo Sepulveda Dur??n" <leonardosepulveda at gmail.com>
To: <r-help at stat.math.ethz.ch>
Sent: Friday, August 12, 2005 4:44 PM
Subject: [R] evaluating string variables
#
Le 12.08.2005 16:44, Leonardo Sepulveda Dur??n a ??crit :
Here are two ways :

paste('C:/R/',i,'.mat',sep="")
sprintf("C:/R/%d.mat",i)

Romain
#
Given my own language inadequacies (I speak only one), I must, of necessity,
refrain from criticizing  the multilingual. However, in this one instance my
sensibilities have been overwhelmed: "symmetric" , please :-)   .

Incidentally, you may find that file.path() is also useful.

Cheers,
Bert

-- Bert Gunter
Genentech Non-Clinical Statistics
South San Francisco, CA
 
"The business of the statistician is to catalyze the scientific learning
process."  - George E. P. Box
17 days later
#
Mac OS 10.3.9 R framework  v. 2.1.1

I am attempting to put a fitted curve into each panel of a lattice 
graph, but am failing to do so. I have tried writing a very 
sophisticated function to do so. The function seems to work when used 
with plot(), but does not do so inside a panel function in xyplot().
Any pointers would be appreciated.

#The example data
fact <- gl(2,7)
x <- rep(1:7,2)
y <- c(1,1,2,3,2,3,4,1,2,1,2,3,3,4)
plot(jitter(y/6) ~ x)

# The following user defined function puts a curve (I believe the 
correct one) into the scatterplot
panel.predglm <- function(x, y) {	
	model.trial <- glm(cbind(y,6-y) ~ poly(x,2), 
family=quasibinomial(link="logit"))
	xfit <- seq(1,7, length=21)
	yfit <- predict(model.trial, newdata=data.frame(x=xfit), 
type="response")
	lines(xfit,yfit)  }

panel.predglm(x, y)


# My attempt to use it in a lattice xyplot, however, fails. It draws a 
curve which in most cases is outside the dimensions of the plot. I 
suspect that the prediction is on the scale of the link functions.

library(lattice)
xyplot(y/6 ~ x|fact, ylim=c(0,.8),
panel=function(x, y,...) {
	panel.xyplot(jitter(x),jitter(y))
	panel.predglm(x,y) }
	)

Any thoughts?
Hank Stevens


Dr. Martin Henry H. Stevens, Assistant Professor
338 Pearson Hall
Botany Department
Miami University
Oxford, OH 45056

Office: (513) 529-4206
Lab: (513) 529-4262
FAX: (513) 529-4243
http://www.cas.muohio.edu/botany/bot/henry.html
http://www.muohio.edu/ecology/
http://www.muohio.edu/botany/
"E Pluribus Unum"
#
Martin Henry H. Stevens wrote:
Two:

1. The "y" argument in your panel function ranges from 0 to 1 and not 0 
to 6 as your plot example assumes.

2. You need to use llines in your panel function and not lines.

Here's a working example:

library(lattice)
fact <- gl(2,7)
x <- rep(1:7,2)
y <- c(1,1,2,3,2,3,4,1,2,1,2,3,3,4)

# The following user defined function puts a curve (I believe the 
correct one) into the scatterplot
panel.predglm <- function(x, y) {	
	model.trial <- glm(cbind(y,6-y) ~ poly(x,2),
                          family=quasibinomial(link="logit"))
	xfit <- seq(1, 7, length=21)
	yfit <- predict(model.trial, newdata=data.frame(x=xfit), type="response")
	llines(xfit,yfit)
}

xyplot(y/6 ~ x|fact, ylim=c(0,.8),
        panel = function(x, y, ...) {
          panel.xyplot(jitter(x), jitter(y))
          panel.predglm(x, y * 6)
        })
#
Problem Solved (see below) - Many thanks to Sundar Dorai-Raj!
Hank Stevens
On Aug 29, 2005, at 3:44 PM, Sundar Dorai-Raj wrote:

            
Dr. Martin Henry H. Stevens, Assistant Professor
338 Pearson Hall
Botany Department
Miami University
Oxford, OH 45056

Office: (513) 529-4206
Lab: (513) 529-4262
FAX: (513) 529-4243
http://www.cas.muohio.edu/botany/bot/henry.html
http://www.muohio.edu/ecology/
http://www.muohio.edu/botany/
"E Pluribus Unum"