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Interquartile Range

19 messages · Jim Lemon, Michael Artz, William Dunlap +2 more

#
Hi,
  I am trying to show an interquartile range while grouping values using
the function ddply().  So my function call now is like

groupedAll <- ddply(data
                 ,~groupColumn
                 ,summarise
                 ,col1_mean=mean(col1)
                 ,col2_mode=Mode(col2) #Function I wrote for getting the
mode shown below

 ,col3_Range=paste(as.character(round(quantile(datat$tenure,c(.25)))),
as.character(round(quantile(data$tenure,c(.75)))), sep = "-")
                 )

#custom Mode function
Mode <- function(x) {
  ux <- unique(x)
  ux[which.max(tabulate(match(x, ux)))]
}

I am not sre what is going wrong on my interquartile range function, it
works on its own outside of ddply()
#
Hi Michael,
At a guess, try this:

iqr<-function(x) {
 return(paste(round(quantile(x,0.25),0),round(quantile(x,0.75),0),sep="-")
}

.col3_Range=iqr(datat$tenure)

Jim
On Tue, Apr 19, 2016 at 11:15 AM, Michael Artz <michaeleartz at gmail.com> wrote:
#
That didn't work Jim!

Thanks anyway
On Mon, Apr 18, 2016 at 9:02 PM, Jim Lemon <drjimlemon at gmail.com> wrote:

            

  
  
#
Are you aware that there *already is* a function that does this?

?IQR

(also your "function" iqr" is just a character string and would have
to be parsed and evaluated to become a function. But this is a
TERRIBLE way to do things in R as it completely circumvents R's
central functional programming paradigm).

Cheers,
Bert


Bert Gunter

"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Tue, Apr 19, 2016 at 7:56 AM, Michael Artz <michaeleartz at gmail.com> wrote:
#
Hi bert,

I understand the difference between a character string and a number. I need
to return a character string, that is a requirement.  It needs to be in
that format.  Getting the range with IQR is trivial I already tried it. The
grouping function accepts only one return value,  and IQR returns two.
Thanks for the reply though sir.
On Apr 19, 2016 10:20 AM, "Bert Gunter" <bgunter.4567 at gmail.com> wrote:

            

  
  
#
It always helps to say how the suggestion did not work.  Jim's
function had a typo in it - was that the problem?  Or did you not
change the call to ddply to use that function.  Here is something
that might "work" for you:

 library(plyr)

 data <- data.frame(groupColumn=rep(1:5,1:5), col1=2^(0:14))
 myIqr <- function(x) {
     paste(round(quantile(x,0.25),0),round(quantile(x,0.75),0),sep="-")
 }
 ddply(data, ~groupColumn, summarise, col1_myIqr=myIqr(col1),
col1_IQR=stats::IQR(col1))
 #  groupColumn col1_myIqr col1_IQR
 #1           1        1-1        0
 #2           2        2-4        1
 #3           3      12-24       12
 #4           4    112-320      208
 #5           5  2048-8192     6144

The important point is that
    paste(round(quantile(x,0.25),0),round(quantile(x,0.75),0),sep="-")
is not a function, it is an expression.   ddplyr wants functions.


Bill Dunlap
TIBCO Software
wdunlap tibco.com

On Tue, Apr 19, 2016 at 7:56 AM, Michael Artz <michaeleartz at gmail.com>
wrote:

  
  
#
HI that did not work for me either.  The value I got returned from that
function was "<rounded mean> - <rounded mean>"  :(. thanks for the reply
through
On Tue, Apr 19, 2016 at 10:34 AM, William Dunlap <wdunlap at tibco.com> wrote:

            

  
  
#
Can you show us a self-contained example, along with the output of
running conflicts()?

Bill Dunlap
TIBCO Software
wdunlap tibco.com

On Tue, Apr 19, 2016 at 8:57 AM, Michael Artz <michaeleartz at gmail.com>
wrote:

  
  
#
To be precise:

paste(round(quantile(x,0.25),0),round(quantile(x,0.75),0),sep="-")

is an expression that evaluates to a character string:
"round(quantile(x,.25),0) - round(quantile(x,0.75),0)"

no matter what the argument of your function, x. Hence

return(paste(...)) will return this exact character string and never
evaluates x.


Cheers,
Bert








Bert Gunter

"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )


On Tue, Apr 19, 2016 at 8:34 AM, William Dunlap via R-help
<r-help at r-project.org> wrote:
#
NO NO  -- I am wrong! The paste() expression is of course evaluated.
It's just that a character string is returned of the form "something -
something".

I apologize for the confusion.

-- Bert




Bert Gunter

"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Tue, Apr 19, 2016 at 10:25 AM, Bert Gunter <bgunter.4567 at gmail.com> wrote:
#
... and I'm getting another cup of coffee...

-- Bert
Bert Gunter

"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Tue, Apr 19, 2016 at 10:30 AM, Bert Gunter <bgunter.4567 at gmail.com> wrote:
#
Oh thanks for that clarification Bert!  Hope you enjoyed your coffee!  I
ended up just using the transform argument in the ddply function.  It
worked and it repeated, then I called a mode function in another call to
ddply that summarised.  Kinda hacky but oh well!

On Tue, Apr 19, 2016 at 12:31 PM, Bert Gunter <bgunter.4567 at gmail.com>
wrote:

  
  
#
If you show us, not just tell us about, a self-contained example
someone might show you a non-hacky way of getting the job done.
(I don't see an argument to plyr::ddply called 'transform'.)

Bill Dunlap
TIBCO Software
wdunlap tibco.com

On Tue, Apr 19, 2016 at 12:18 PM, Michael Artz <michaeleartz at gmail.com>
wrote:

  
  
#
Hi,
  Here is what I am doing

notGroupedAll <- ddply(data
                 ,~groupColumn
                 ,summarise
                 ,col1_mean=mean(col1)
                 ,col2_mode=Mode(col2) #Function I wrote for getting the
mode shown below
                 ,col3_Range=myIqr(col3)
                 )

groupedAll <- ddply(data
                 ,~groupColumn
                 ,summarise
                 ,col1_mean=mean(col1)
                 ,col2_mode=Mode(col2) #Function I wrote for getting the
mode shown below
                 ,col3_Range=Mode(col3)
                 )

#custom Mode function
Mode <- function(x) {
  ux <- unique(x)
  ux[which.max(tabulate(match(x, ux)))]

#the range function
myIqr <- function(x) {
  paste(round(quantile(x,0.375),0),round(quantile(x,0.625),0),sep="-")
}


}


Here is what I am doing!! :)
On Tue, Apr 19, 2016 at 2:57 PM, William Dunlap <wdunlap at tibco.com> wrote:

            

  
  
#
Well, instead of your functions try:

Mode <- function(x) {
     tabx <- table(x)
     tabx[which.max(tabx)]
}

and use R's IQR function instead of yours.

... so I still don't get why you want to return a character string
instead of a value for the IQR;
and the mode of a sample defined as above is generally a bad estimator
of the mode of the distribution. To say more than that would take me
too far afield. Post on stats.stackexchange.com if you want to know
why (if it's even relevant).

Cheers,
Bert
Bert Gunter

"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Tue, Apr 19, 2016 at 4:25 PM, Michael Artz <michaeleartz at gmail.com> wrote:
#
Hi,

Jumping into this thread mainly on the point of the mode of the distribution, while also supporting Bert's comments below on theory.

If the vector 'x' that is being passed to this function is an integer vector, then a tabulation of the integers can yield a 'mode', presuming of course that there is only one unique mode. You may have to decide how you want to handle a multi-modal discrete distribution.

If the vector 'x' is continuous (e.g. contains floating point values), then a tabulation is going to be problematic for a variety of reasons.

In that case, prior discussions on this point, have yielded the following estimation of the mode of a continuous distribution by using:

Mode <- function(x) {
  D <- density(x)
  D$x[which.max(D$y)]
}

where the second line of the function gets you the value of 'x' at the maximum of the density estimate. Of course, there is still the possibility of a multi-modal distribution and the nuances of which kernel is used, etc., etc.

Food for thought.

Regards,

Marc Schwartz
#
Again, IQR returns two both a .25 and a .75 value and it failed, which is
why I didn't use it before. Also, the first function just returns tha same
value repeating.  Since they are the same, before the second call, using
the mode function is just a way to grab one value. I could have used
average, min, max, they all would have returned the same thing.

Mike
On Tue, Apr 19, 2016 at 7:24 PM, Marc Schwartz <marc_schwartz at me.com> wrote:

            

  
  
#
???

IQR returns a single number.
[1] 1.090168

To your 2nd response:
"I could have used average, min, max, they all would have returned the
same thing., "

I can only respond: huh?? Are all your values identical?

You really need to provide a small reproducible example as requested
by the posting guide -- I certainly don't get it, and I'm done
guessing. Maybe others will see what I am missing and say something
useful. I clearly can't.

Cheers,
Bert





Bert Gunter

"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Tue, Apr 19, 2016 at 5:29 PM, Michael Artz <michaeleartz at gmail.com> wrote:
#
I already found a solution, you suggested I try to find a non hacky
solution, which was not really my priority. I should have declined
politely, which I will do now. Or, ifyou just want me to post reproducible
code because you are bored or because you like solving problems then let me
know and I will accommodate. You have been helpful and I wouldnt mind in
that case.  Also, IQR was not a help from the beginning. If it supplies one
value, then its not even a candidate to be helpful for my problem. I
already talked about the format i was looking for.  I dont think I violated
any posting guideline, I asked for help, and people pointed me in a
direction and it helped me. Thanks again, I appreciate it.
On Apr 19, 2016 10:53 PM, "Bert Gunter" <bgunter.4567 at gmail.com> wrote: