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How to replace NA with zero (0)

5 messages · Christopher Kelvin, James, Rolf Turner +2 more

Christopher Kelvin
# 
Hello,
?When i generate data with the code below there appear NA as part of the generated data, i prefer to have zero (0) instead of NA on my data.
Is there a command i can issue to replace the NA with zero (0) even if it is after generating the data??
Thank you
library(survival)

p1<-0.8;b<-1.5;rr<-1000
for(i in 1:rr){
r<-runif(45,min=0,max=1)
t<-rweibull(45,p1,b)
w=Surv(r,t,type="interval2")

x[1:45]<-(w[,1])
u<-x[1:45]

y[1:45]<-(w[,2])
v<-y[1:45]
}
w
u
v

Chris G
Researcher
Institute for Mathematical Research
UPM
James
# 
On Thu, May 3, 2012 at 10:43 AM, Christopher Kelvin
<chris_kelvin2001 at yahoo.com> wrote:

            

      
      
      
    

        
Chris,

I didn't try your example code, so this suggestion is far more
general, but you might try something along the lines of:

x[which(is.na(x))] <- 0

Best,

James

  
  


  


      

    

    

      
      

        


  

        

      Rolf Turner
    

    

      
      #
    

  


  

      
On 04/05/12 03:43, Christopher Kelvin wrote:

            

      
      
      
    

        
<SNIP>

Just ***DON'T***.  NAs and zeroes are completely different concepts.
You will simply confuse everybody including yourself.

     cheers,

         Rolf Turner

  
  


  


      

    

    

      
      

        


  

        

      Steve Lianoglou
    

    

      
      #
    

  


  

      
Also,

        
On Thu, May 3, 2012 at 1:57 PM, J Toll <jctoll at gmail.com> wrote:

            

      
      
      
    

        
Random note from left field: the call to `which` is unnecessary here.

-steve

  
    

      
      
    

  


  


      

    

    

      
      

        


  

        

      Mercier Eloi
    

    

      
      #
    

  


  

          

      
      
      
    

        
?Surv

time2: ending time of the interval for interval censored or counting
           process data only

and

w=Surv(r,t,type="interval2")
Warning message:
In Surv(r, t, type = "interval2") :
   Invalid interval: start>  stop, NA created

=>  r needs to be greater that t.

            

      
      
      
    

        
I can only agree with that.

        
On 12-05-03 05:18 PM, Steve Lianoglou wrote:

        

            

      
      
      
    

        
set.seed(1)
r1=runif(10)
set.seed(2)
t=runif(10)
w=Surv(r,t,type="interval2")

w1=w
w1[is.na(w)] = 0
w1
  [1] 0.00000000+             [0.37212390, 0.7023740] [0.57285336, 
0.5733263]
  [4] 0.00000000+             [0.20168193, 0.9438393] [0.89838968, 
0.9434750]
  [7] 0.00000000+             [0.66079779, 0.8334488] 0.00000000+
[10] [0.06178627, 0.5499837]

w2=w
w2[which(is.na(w2))] = 0
w2
  [1] [0.00000000, 0.1848823] [0.37212390, 0.7023740] [0.57285336, 
0.5733263]
  [4] [0.00000000, 0.1680519] [0.20168193, 0.9438393] [0.89838968, 
0.9434750]
  [7] [0.00000000, 0.1291590] [0.66079779, 0.8334488] [0.00000000, 
0.4680185]
[10] [0.06178627, 0.5499837]

Eloi