seq(along= surprise

This surprised me:

reps <- 100
sims <- list(length=reps)
sims

$length
[1] 100

for(i in seq(along=sims))print(i)

[1] 1

This is R 2.8.1.

Kjetil

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Kjetil Halvorsen wrote:

This surprised me:

reps <- 100
sims <- list(length=reps)
sims

$length
[1] 100

for(i in seq(along=sims))print(i)

[1] 1

This is R 2.8.1.

What is surprising?

sims is now a list that contains 1 element called "length" with a 
numeric value of 100.
Then seq(along=sims) is exactly 1, because sims has length 1.
Hence i is printed once (1 iteration of the loop) and is 1 in the first 
(and only) iteration.

Uwe

Kjetil

    [[alternative HTML version deleted]]

sims <- list(length=100)

do.call(seq, sims)

Uwe Ligges wrote:

Kjetil Halvorsen wrote:

This surprised me:

reps <- 100
sims <- list(length=reps)
sims

$length
[1] 100

for(i in seq(along=sims))print(i)

[1] 1

This is R 2.8.1.

What is surprising?

sims is now a list that contains 1 element called "length" with a
numeric value of 100.
Then seq(along=sims) is exactly 1, because sims has length 1.
Hence i is printed once (1 iteration of the loop) and is 1 in the  
first
(and only) iteration.

Uwe

I should have added that you probably want

sims <- vector(mode="list", length=100)

Uwe

Kjetil

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