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quotation marks and scan
7 messages · Rolf Turner, michael.weylandt at gmail.com (R. Michael Weylandt, Erin Hodgess +3 more
(1) The backslashes are not really there; they are an artefact of the R
print() function.
Try cat(u,"\n"). I think this might be an FAQ.
(2) Is not your problem the fact that your are setting "replacement"
equal to the
thing you are trying to get rid of? I.e. don't you want
v <- gsub(pattern='\"',replacement='',x=u) ???
Either I am misunderstanding your intent or you need another cup of coffee.
cheers,
Rolf
On 11/18/13 11:07, Erin Hodgess wrote:
Dear R People:
I'm sure that this is a very simple problem, but I have been wresting with
it for some time.
I have the following file that has the following one line:
CRS("+init=epsg:28992")
Fair enough. I scan it into R and get the following:
u
[1] "CRS(\"+init=epsg:28992\")"
gsub(pattern='\"',replacement='"',x=u)
[1] "CRS(\"+init=epsg:28992\")" I need to get rid of the extra quotation marks and slashes. I've tried all sorts of things, including gsub, as you see, but no good.
They're not actually there so don't try too hard to rid yourself of them: x <- "\'" length(x) print(x) cat(x, "\n") Make sure you're clear on the difference between what's stored by the computer and what it print()s. Rarely the same, though cat() is often slightly more honest.
On Nov 17, 2013, at 17:07, Erin Hodgess <erinm.hodgess at gmail.com> wrote:
Dear R People:
I'm sure that this is a very simple problem, but I have been wresting with
it for some time.
I have the following file that has the following one line:
CRS("+init=epsg:28992")
Fair enough. I scan it into R and get the following:
u
[1] "CRS(\"+init=epsg:28992\")"
gsub(pattern='\"',replacement='"',x=u)
[1] "CRS(\"+init=epsg:28992\")" I need to get rid of the extra quotation marks and slashes. I've tried all sorts of things, including gsub, as you see, but no good. Thank you for any help. Sincerely, Erin -- Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University of Houston - Downtown mailto: erinm.hodgess at gmail.com [[alternative HTML version deleted]]
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
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[See in-line below]
On 17-Nov-2013 22:38:30 Rolf Turner wrote:
(1) The backslashes are not really there; they are an artefact of the R
print() function.
Try cat(u,"\n"). I think this might be an FAQ.
(2) Is not your problem the fact that your are setting "replacement"
equal to the
thing you are trying to get rid of? I.e. don't you want
v <- gsub(pattern='\"',replacement='',x=u) ???
Either I am misunderstanding your intent or you need another cup of coffee.
Is the above line a Fortune?
cheers,
Rolf
On 11/18/13 11:07, Erin Hodgess wrote:
Dear R People:
I'm sure that this is a very simple problem, but I have been wresting with
it for some time.
I have the following file that has the following one line:
CRS("+init=epsg:28992")
Fair enough. I scan it into R and get the following:
u
[1] "CRS(\"+init=epsg:28992\")"
gsub(pattern='\"',replacement='"',x=u)
[1] "CRS(\"+init=epsg:28992\")" I need to get rid of the extra quotation marks and slashes. I've tried all sorts of things, including gsub, as you see, but no good.
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
------------------------------------------------- E-Mail: (Ted Harding) <Ted.Harding at wlandres.net> Date: 17-Nov-2013 Time: 23:55:48 This message was sent by XFMail
On Sun, 17 Nov 2013, Ted Harding wrote:
[See in-line below] On 17-Nov-2013 22:38:30 Rolf Turner wrote:
(1) The backslashes are not really there; they are an artefact of the R
print() function.
Try cat(u,"\n"). I think this might be an FAQ.
(2) Is not your problem the fact that your are setting "replacement"
equal to the
thing you are trying to get rid of? I.e. don't you want
v <- gsub(pattern='\"',replacement='',x=u) ???
Either I am misunderstanding your intent or you need another cup of coffee.
Is the above line a Fortune?
Why not? ;-) On R-Forge now. Z
cheers,
Rolf
On 11/18/13 11:07, Erin Hodgess wrote:
Dear R People:
I'm sure that this is a very simple problem, but I have been wresting with
it for some time.
I have the following file that has the following one line:
CRS("+init=epsg:28992")
Fair enough. I scan it into R and get the following:
u
[1] "CRS(\"+init=epsg:28992\")"
gsub(pattern='\"',replacement='"',x=u)
[1] "CRS(\"+init=epsg:28992\")" I need to get rid of the extra quotation marks and slashes. I've tried all sorts of things, including gsub, as you see, but no good.
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
------------------------------------------------- E-Mail: (Ted Harding) <Ted.Harding at wlandres.net> Date: 17-Nov-2013 Time: 23:55:48 This message was sent by XFMail
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
I know you have a solution, but I would have suggested using print() with quote=FALSE as a better way to illuminate what is going on, as in this example:
foo <- 'bah"bah' foo
[1] "bah\"bah"
print(foo)
[1] "bah\"bah"
print(foo, quote=FALSE)
[1] bah"bah As others said, the backslash isn't really there. So you only have to get rid of the " which you can do with
gsub('"','',foo)
[1] "bahbah" To summarize, in R, due to its rules for formatting printed output, what you see isn't always exactly what you have, and this is an example.
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 11/17/13 2:07 PM, "Erin Hodgess" <erinm.hodgess at gmail.com> wrote:
>Dear R People:
>
>I'm sure that this is a very simple problem, but I have been wresting with
>it for some time.
>
>I have the following file that has the following one line:
>
> CRS("+init=epsg:28992")
>
>Fair enough. I scan it into R and get the following:
>
>> u
>[1] "CRS(\"+init=epsg:28992\")"
>> gsub(pattern='\"',replacement='"',x=u)
>[1] "CRS(\"+init=epsg:28992\")"
>
>I need to get rid of the extra quotation marks and slashes. I've tried
>all
>sorts of things, including gsub, as you see, but no good.
>
>Thank you for any help.
>
>Sincerely,
>Erin
>
>
>--
>Erin Hodgess
>Associate Professor
>Department of Computer and Mathematical Sciences
>University of Houston - Downtown
>mailto: erinm.hodgess at gmail.com
>
> [[alternative HTML version deleted]]
>
>______________________________________________
>R-help at r-project.org mailing list
>https://stat.ethz.ch/mailman/listinfo/r-help
>PLEASE do read the posting guide
>http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.