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when to use which apply function?
4 messages · Rui Barradas, David Winsemius, C W
Hello, The correct syntax would be sapply(1:10, function(i) newfun(x=mat[i, 1], y=mat[i, 2], a=a, b=b)) Hope this helps, Rui Barradas Em 26-03-2013 21:51, C W escreveu:
Dear list,
I am a little confused as to when to use apply, sapply, tapply, vapply,
replicate. I've encountered this several times,
This is time, this is what I am working on,
mat <- matrix(c(seq(from=1, to=10), rnorm(10)), ncol=2)
a=1; b=5
newfun <- function(x, y, a, b)
{
x*y+a+b
}
sapply(i=1:10, newfun(x=mat[i, 1], y=mat[i, 2], a=a, b=b))
Error in match.fun(FUN) : argument "FUN" is missing, with no default
I want to use ith row of mat, evaluate newfun(). Am I making a parameter
mistake, or should I use a different apply function?
Thanks in a advance,
Mike
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On Mar 26, 2013, at 2:51 PM, C W wrote:
Dear list,
I am a little confused as to when to use apply, sapply, tapply, vapply,
replicate. I've encountered this several times,
This is time, this is what I am working on,
mat <- matrix(c(seq(from=1, to=10), rnorm(10)), ncol=2)
a=1; b=5
newfun <- function(x, y, a, b)
{
x*y+a+b
}
sapply(i=1:10, newfun(x=mat[i, 1], y=mat[i, 2], a=a, b=b))
Error in match.fun(FUN) : argument "FUN" is missing, with no default
I want to use ith row of mat, evaluate newfun(). Am I making a parameter
mistake,
There is nothing that would naturally "catch" the values. After they are evaluated sequentially by `sapply` the values 1:10 no longer are named "i" and so don't naturally fall into the slots you thought you had constructed for them. By constructing an anonymous function with any formal argument name (as already demonstrated by another poster) you could get to use positional matching.
or should I use a different apply function?
Yes, "some other function" since all those operations are vectorized, this could be more easily done with: mat[ ,1]*mat[ ,2]+a+b # and no need for a loop, right?
David Winsemius Alameda, CA, USA
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