Hi,
I am wondering how I can separate whether it is covariate or predictor in the ANOVA analysis. For example
A<-structure(list(Machine = c(1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L,
2L, 3L, 3L, 3L, 3L, 3L), Diameter = c(20L, 25L, 24L, 25L, 32L,
22L, 28L, 22L, 30L, 28L, 21L, 23L, 26L, 21L, 15L), Strength = c(36L,
41L, 39L, 42L, 49L, 40L, 48L, 39L, 45L, 44L, 35L, 37L, 42L, 34L,
32L)), .Names = c("Machine", "Diameter", "Strength"), class = "data.frame", row.names = c(NA,
-15L))
attach(A)
b<-aov(Strength~Diameter)
summary(b)
c<-aov(Strength~Diameter+as.factor(Machine))
summary(c)
I am confused here whether the "Mechine" is covariate or predictor. How do I know which one is covariate and predictor?
If Machine is predictor (just like Diameter), how I am supposed to write in the model?
is the equation (below) for this one in the condition that the Machine is predictor?
c1<-aov(Strength~Diameter+Machine), ?????. If it is so, it means that co-variate is dummy variable, right????
Your help will really help me to clear the concept.
Thanks
KG
covariate or predictor
4 messages · Kristi Glover, Rolf Turner, Bert Gunter
On 26/11/14 13:57, Kristi Glover wrote:
Hi,
I am wondering how I can separate whether it is covariate or predictor in the ANOVA analysis. For example
A<-structure(list(Machine = c(1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L,
2L, 3L, 3L, 3L, 3L, 3L), Diameter = c(20L, 25L, 24L, 25L, 32L,
22L, 28L, 22L, 30L, 28L, 21L, 23L, 26L, 21L, 15L), Strength = c(36L,
41L, 39L, 42L, 49L, 40L, 48L, 39L, 45L, 44L, 35L, 37L, 42L, 34L,
32L)), .Names = c("Machine", "Diameter", "Strength"), class = "data.frame", row.names = c(NA,
-15L))
attach(A)
b<-aov(Strength~Diameter)
summary(b)
c<-aov(Strength~Diameter+as.factor(Machine))
summary(c)
I am confused here whether the "Mechine" is covariate or predictor. How do I know which one is covariate and predictor?
If Machine is predictor (just like Diameter), how I am supposed to write in the model?
is the equation (below) for this one in the condition that the Machine is predictor?
c1<-aov(Strength~Diameter+Machine), ?????. If it is so, it means that co-variate is dummy variable, right????
Your help will really help me to clear the concept.
(1) Please don't post in HTML; messages with code in them become unreadable. (2) This isn't really an R question is it? Possibly better posted to stackexchange. (3) What in your mind is the difference between "covariate" and "predictor"? In my (possibly limited) understanding, the words are synonymous. (4) Are you perhaps concerned with the difference between a continuous predictor and a categorical (factor) predictor? (5) In your example "Machine" is pretty clearly *categorical*; the numbers 1, 2, and 3 are just *labels* for the machines; their numerical value is of no significance. The labels could just as well be "A", "B" and "C", or "melvin", "irving" and "clyde". (6) OTOH "Diameter" is pretty obviously interpretable as a *numerical* measurement. (7) I have no idea what you mean by "If it is so, it means that co-variate is dummy variable, right????" Would you care to translate that into English? cheers, Rolf Turner
Rolf Turner Technical Editor ANZJS
Yes, Rolf -- she seems to think that covariates must be categorical and predictors categorical -- or maybe it's vice-versa. Anyway, she apparently has not done any homework (e.g. by reading an Intro to R) and so doesn't understand the use of modeling formulas in lm() and thus does not understand the use of contrasts (= dummy variables). As you said, either stackexchange or perhaps a local consultant is probably where she should be seeking advice, Cheers, Bert Bert Gunter Genentech Nonclinical Biostatistics (650) 467-7374 "Data is not information. Information is not knowledge. And knowledge is certainly not wisdom." Clifford Stoll
On Tue, Nov 25, 2014 at 6:13 PM, Rolf Turner <r.turner at auckland.ac.nz> wrote:
On 26/11/14 13:57, Kristi Glover wrote:
Hi,
I am wondering how I can separate whether it is covariate or predictor in
the ANOVA analysis. For example
A<-structure(list(Machine = c(1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L,
2L, 3L, 3L, 3L, 3L, 3L), Diameter = c(20L, 25L, 24L, 25L, 32L,
22L, 28L, 22L, 30L, 28L, 21L, 23L, 26L, 21L, 15L), Strength = c(36L,
41L, 39L, 42L, 49L, 40L, 48L, 39L, 45L, 44L, 35L, 37L, 42L, 34L,
32L)), .Names = c("Machine", "Diameter", "Strength"), class =
"data.frame", row.names = c(NA,
-15L))
attach(A)
b<-aov(Strength~Diameter)
summary(b)
c<-aov(Strength~Diameter+as.factor(Machine))
summary(c)
I am confused here whether the "Mechine" is covariate or predictor. How
do I know which one is covariate and predictor?
If Machine is predictor (just like Diameter), how I am supposed to write
in the model?
is the equation (below) for this one in the condition that the Machine is
predictor?
c1<-aov(Strength~Diameter+Machine), ?????. If it is so, it means that
co-variate is dummy variable, right????
Your help will really help me to clear the concept.
(1) Please don't post in HTML; messages with code in them become unreadable. (2) This isn't really an R question is it? Possibly better posted to stackexchange. (3) What in your mind is the difference between "covariate" and "predictor"? In my (possibly limited) understanding, the words are synonymous. (4) Are you perhaps concerned with the difference between a continuous predictor and a categorical (factor) predictor? (5) In your example "Machine" is pretty clearly *categorical*; the numbers 1, 2, and 3 are just *labels* for the machines; their numerical value is of no significance. The labels could just as well be "A", "B" and "C", or "melvin", "irving" and "clyde". (6) OTOH "Diameter" is pretty obviously interpretable as a *numerical* measurement. (7) I have no idea what you mean by "If it is so, it means that co-variate is dummy variable, right????" Would you care to translate that into English? cheers, Rolf Turner -- Rolf Turner Technical Editor ANZJS
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On 26/11/14 15:49, Bert Gunter wrote:
Yes, Rolf -- she seems to think that covariates must be categorical and predictors categorical -- or maybe it's vice-versa.
You of course meant "... covariates must be categorical and predictors numerical -- or maybe it's vice-versa." (I can't help persistently putting my Technical Editor hat on. :-)) cheers, Rolf
Rolf Turner Technical Editor ANZJS