how to setdiff on lists of lists

aa<-list(c(1:3), c(4:6))
aa

bb<-list(3,5)
bb

lapply(aa, setdiff, bb)

-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
project.org] On Behalf Of Simone Gabbriellini
Sent: Friday, February 01, 2013 11:16 AM
To: r-help at r-project.org
Subject: [R] how to setdiff on lists of lists

Dear List,

I have a data structure like:

aa

[[1]]
[1] 1 2 3

[[2]]
[1] 4 5 6

bb

[[1]]
[1] 3

[[2]]
[1] 5

I would like to set differences between "aa" and "bb" and get as result
another list of lists like:

res

[[1]]
[1] 1 2

[[2]]
[1] 4 6

I am trying:

lapply(aa, setdiff, bb)

but I simply get "aa" back as result. Could you please point me in the
right direction about the combination of functions that I need to
accomplish this task?

Best regards,
Simone

--
Simone Gabbriellini, PhD

PostDoc at DISI, University of Bologna
mobile: +39 340 39 75 626
email: simone.gabbriellini at unibo.it
home: www.digitaldust.it

DigitalBrains srl
Amministratore
mobile: +39 340 39 75 626
email: simone.gabbriellini at digitalbrains.it
home: www.digitalbrains.it

aa<-list(c(1:3), c(4:6))
 bb<-list(3,5)
mapply(setdiff, aa, bb)

Dear List,

I have a data structure like:

aa

[[1]]
[1] 1 2 3

[[2]]
[1] 4 5 6

bb

[[1]]
[1] 3

[[2]]
[1] 5

I would like to set differences between "aa" and "bb" and get as
result another list of lists like:

res

[[1]]
[1] 1 2

[[2]]
[1] 4 6

I am trying:

lapply(aa, setdiff, bb)

but I simply get "aa" back as result. Could you please point me in the
right direction about the combination of functions that I need to
accomplish this task?

Best regards,
Simone

--
Simone Gabbriellini, PhD

PostDoc at DISI, University of Bologna
mobile: +39 340 39 75 626
email: simone.gabbriellini at unibo.it
home: www.digitaldust.it

DigitalBrains srl
Amministratore
mobile: +39 340 39 75 626
email: simone.gabbriellini at digitalbrains.it
home: www.digitalbrains.it