splitting character vectors into multiple vectors using strsplit

I don't know if R has the equivalent of an identity
function, but the following solution accomplishes this:

splitvectors <- sapply(splitlist, function(x) x)

Indeed it does, called, not surprisingly, "identity." You managed to
guess the definition ;-)

?force also does the same, but the reason for the name is perhaps a
lesson for another time.

Also, note that in certain circumstances c(x) != x because c() strips
attributes.

Cheers,
Michael

HI,
You can also use ?abind() in this case:
library(abind)
abind(splitlist,along=2)
?# ?? [,1] [,2]
#[1,] "a1" "a2"
#[2,] "b1" "b2"
A.K.




----- Original Message -----
From: David Romano <romanod at grinnell.edu>
To: r-help at r-project.org
Cc: 
Sent: Friday, November 2, 2012 3:49 PM
Subject: Re: [R] splitting character vectors into multiple vectors using strsplit

Hi again,

I just wanted to thank folks for their suggestions; they led me to
understand the *apply family a little better, and to realize the issue was
really a question of how to convert a list of equal length vectors into a
matrix.? In this case sapply only needs to be asked to identify these
vectors individually; I don't know if R has the equivalent of an identity
function, but the following solution accomplishes this:

splitvectors <- sapply(splitlist, function(x) x)
splitvectors

? ?  [,1] [,2]
[1,] "a1" "a2"
[2,] "b1" "b2"

or, by replacing the anonymous function by c, we obtain a more elegant but
more wasteful solution.

Thanks again for everyone's help,
David Romano

Hi folks,

Suppose I create the character vector charvec by

charvec<-c("a1.b1","a2.b2")
charvec

[1] "a1.b1" "a2.b2"

and then I use strsplit on charvec as follows:

splitlist<-strsplit(charvec,split=".",fixed=TRUE)
splitlist

[[1]]
[1] "a1" "b1"

[[2]]
[1] "a2" "b2"


I was wondering whether there is already a function which can extract
the "a" and "b" parts of the list splitlist; that is, that can return
the same vectors as those created by c("a1","a2") and c("b1","b2").

Thanks,
David Romano

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