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understanding I() in lmer formula

4 messages · Don Cohen, Bert Gunter, S Ellison

#
Is there a difference between I(x*y) and I(y*x) ?
I have a call to lmer that results in this complaint:
  Error in is.alpha2.subordinate * ~z.min.co.res :  
  non-numeric argument to binary operator
when I change this line:
  I(is.alpha2.subordinate*z.min.co.res)+
to this:
  I(z.min.co.res*is.alpha2.subordinate)+
the complaint goes away.
I'd like to understand why.
#
If you don't get a prompt reply here, you might do better posting this
on the r-sig-mixed-models list (for obvious reasons).

Cheers,
Bert


Bert Gunter

"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Tue, Jun 13, 2017 at 11:25 AM, Don Cohen <don-r-help at isis.cs3-inc.com> wrote:
1 day later
#
A reproducible example would help ...

In the absence of that, check the classes of the two variables in I() and, if you run the product on the command line, either inside I() or not, what's the class of the result?
If that is order-dependent for the object types you're combining, while I don't know why that might be it would go some way to explaining the outcome.

S Ellison



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#
The suggestion to post on R-sig-ME was a good one.
The problem turned out to be a bug in lmer parsing, which is now fixed.

S Ellison writes:
 > >  Is there a difference between I(x*y) and I(y*x) ?
 > > I have a call to lmer that results in this complaint:
 > >   Error in is.alpha2.subordinate * ~z.min.co.res :
 > 
 > A reproducible example would help ...