How to do it in R

Dear all,

I`ve got to calculate the ratio of methanogens to bacteria, but I
wouldn`t
like to divide the total copy numbers of methanogens ( on average 10^8)
by
bacteria (10^10) because they have different exponents and bases. So, my
idea is to standardize both microorganisms counts to 10^3.

Hypothetical example of what I`d like to do:

Total Methanogens: 28 x 10^3
Total bacteria: 710 x 10^3


Total: 710 + 28= 738 x 10^3

Met/bac Ratio : (28/738)*100 = 3.79%

How could I perform this calculation in R?

Thanks,

-- 
Andre

	[[alternative HTML version deleted]]

t_m <- 28e3
t_b <- 710e3
ratio <- t_m / (t_m + t_b) * 100
ratio

Dear all,

I`ve got to calculate the ratio of methanogens to bacteria, but I wouldn`t
like to divide the total copy numbers of methanogens ( on average 10^8) by
bacteria (10^10) because they have different exponents and bases. So, my
idea is to standardize both microorganisms counts to 10^3.

Hypothetical example of what I`d like to do:

Total Methanogens: 28 x 10^3
Total bacteria: 710 x 10^3


Total: 710 + 28= 738 x 10^3

Met/bac Ratio : (28/738)*100 = 3.79%

How could I perform this calculation in R?

Thanks,

--
Andre

        [[alternative HTML version deleted]]

Dear all,

I`ve got to calculate the ratio of methanogens to bacteria, but I wouldn`t
like to divide the total copy numbers of methanogens ( on average 10^8) by
bacteria (10^10) because they have different exponents and bases. So, my
idea is to standardize both microorganisms counts to 10^3.

a <- 6.2E8; b <- 5.4E10
a/b

Hypothetical example of what I`d like to do:

Total Methanogens: 28 x 10^3
Total bacteria: 710 x 10^3


Total: 710 + 28= 738 x 10^3

Met/bac Ratio : (28/738)*100 = 3.79%

How could I perform this calculation in R?

Thanks,

--
Andre

        [[alternative HTML version deleted]]