9 messages · John, David Winsemius, Jeff Newmiller +1 more
Hi, Is there any way to find the permutation function of the sorting and to apply the function (or its inverse) elsewhere? For example, the following permutation function from the sorting in the matrix form is c(1,2,3), c(2,1,3)
sort(c("bc","ac","dd"))
[1] "ac" "bc" "dd" I try to find it in the permutations/permute package, but I can't find it John
On May 22, 2018, at 10:06 PM, John <miaojpm at gmail.com> wrote: Hi, Is there any way to find the permutation function of the sorting and to apply the function (or its inverse) elsewhere? For example, the following permutation function from the sorting in the matrix form is c(1,2,3), c(2,1,3)
sort(c("bc","ac","dd"))
[1] "ac" "bc" "dd"
I think you are asking for the `order` function.
I try to find it in the permutations/permute package, but I can't find it John [[alternative HTML version deleted]]
Thanks, David. I got the answer from the web. Is there any easy way to permute a set (e.g., a set of characters) by the permutation it returns? Thanks,
x <- c(10,7,4,3,8,2) sort(x, index.return=TRUE)
$x [1] 2 3 4 7 8 10 $ix [1] 6 4 3 2 5 1 2018-05-23 10:49 GMT+08:00 David Winsemius <dwinsemius at comcast.net>:
On May 22, 2018, at 10:06 PM, John <miaojpm at gmail.com> wrote: Hi, Is there any way to find the permutation function of the sorting and to apply the function (or its inverse) elsewhere? For example, the following permutation function from the sorting in the matrix form is c(1,2,3), c(2,1,3)
sort(c("bc","ac","dd"))
[1] "ac" "bc" "dd"
I think you are asking for the `order` function.
I try to find it in the permutations/permute package, but I can't find
it
John
[[alternative HTML version deleted]]
On May 22, 2018, at 10:57 PM, John <miaojpm at gmail.com> wrote: Thanks, David. I got the answer from the web. Is there any easy way to permute a set (e.g., a set of characters) by the permutation it returns? Thanks,
x <- c(10,7,4,3,8,2) sort(x, index.return=TRUE)
$x [1] 2 3 4 7 8 10 $ix [1] 6 4 3 2 5 1
I don't understand what is being requested. The $ix value is the same as the one returned `by order`. David.
2018-05-23 10:49 GMT+08:00 David Winsemius <dwinsemius at comcast.net>:
On May 22, 2018, at 10:06 PM, John <miaojpm at gmail.com> wrote: Hi, Is there any way to find the permutation function of the sorting and to apply the function (or its inverse) elsewhere? For example, the following permutation function from the sorting in the matrix form is c(1,2,3), c(2,1,3)
sort(c("bc","ac","dd"))
[1] "ac" "bc" "dd"
I think you are asking for the `order` function.
I try to find it in the permutations/permute package, but I can't find it
John
[[alternative HTML version deleted]]
Perhaps the question was "what is indexing"?
On May 22, 2018, at 10:57 PM, John <miaojpm at gmail.com> wrote: Thanks, David. I got the answer from the web. Is there any easy way to permute a set (e.g., a set of characters) by
the permutation it returns? Thanks,
x <- c(10,7,4,3,8,2) sort(x, index.return=TRUE)
$x [1] 2 3 4 7 8 10 $ix [1] 6 4 3 2 5 1
I don't understand what is being requested. The $ix value is the same as the one returned `by order`. David.
2018-05-23 10:49 GMT+08:00 David Winsemius <dwinsemius at comcast.net>:
On May 22, 2018, at 10:06 PM, John <miaojpm at gmail.com> wrote: Hi, Is there any way to find the permutation function of the sorting
and to
apply the function (or its inverse) elsewhere? For example, the following permutation function from the sorting
in the
matrix form is c(1,2,3), c(2,1,3)
sort(c("bc","ac","dd"))
[1] "ac" "bc" "dd"
I think you are asking for the `order` function.
I try to find it in the permutations/permute package, but I can't
find it
John
[[alternative HTML version deleted]]
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Sent from my phone. Please excuse my brevity.
sort(c("bc","ac","dd"), index.return=TRUE)
$x
[1] "ac" "bc" "dd"
$ix
[1] 2 1 3
We have the permutation, namely 1-->2, 2-->1, 3-->3.
How can I apply the permutation function to a new set
c("D","E", "F")?
so that the result is
c("E","D", "F").
2018-05-23 11:06 GMT+08:00 David Winsemius <dwinsemius at comcast.net>:
On May 22, 2018, at 10:57 PM, John <miaojpm at gmail.com> wrote: Thanks, David. I got the answer from the web. Is there any easy way to permute a set (e.g., a set of characters) by
the permutation it returns? Thanks,
x <- c(10,7,4,3,8,2) sort(x, index.return=TRUE)
$x [1] 2 3 4 7 8 10 $ix [1] 6 4 3 2 5 1
I don't understand what is being requested. The $ix value is the same as the one returned `by order`. David.
2018-05-23 10:49 GMT+08:00 David Winsemius <dwinsemius at comcast.net>:
On May 22, 2018, at 10:06 PM, John <miaojpm at gmail.com> wrote: Hi, Is there any way to find the permutation function of the sorting and
to
apply the function (or its inverse) elsewhere? For example, the following permutation function from the sorting in
the
matrix form is c(1,2,3), c(2,1,3)
sort(c("bc","ac","dd"))
[1] "ac" "bc" "dd"
I think you are asking for the `order` function.
I try to find it in the permutations/permute package, but I can't
find it
John
[[alternative HTML version deleted]]
On May 22, 2018, at 11:37 PM, John <miaojpm at gmail.com> wrote:
sort(c("bc","ac","dd"), index.return=TRUE)
$x
[1] "ac" "bc" "dd"
$ix
[1] 2 1 3
We have the permutation, namely 1-->2, 2-->1, 3-->3.
How can I apply the permutation function to a new set
c("D","E", "F")?
so that the result is
c("E","D", "F").
So you want:
x <- sort(c("bc","ac","dd"), index.return=TRUE)
x
$x [1] "ac" "bc" "dd" $ix [1] 2 1 3
c("D","E", "F")[ x$ix ]
[1] "E" "D" "F"
2018-05-23 11:06 GMT+08:00 David Winsemius <dwinsemius at comcast.net>:
On May 22, 2018, at 10:57 PM, John <miaojpm at gmail.com> wrote: Thanks, David. I got the answer from the web. Is there any easy way to permute a set (e.g., a set of characters) by the permutation it returns? Thanks,
x <- c(10,7,4,3,8,2) sort(x, index.return=TRUE)
$x [1] 2 3 4 7 8 10 $ix [1] 6 4 3 2 5 1
I don't understand what is being requested. The $ix value is the same as the one returned `by order`. David.
2018-05-23 10:49 GMT+08:00 David Winsemius <dwinsemius at comcast.net>:
On May 22, 2018, at 10:06 PM, John <miaojpm at gmail.com> wrote: Hi, Is there any way to find the permutation function of the sorting and to apply the function (or its inverse) elsewhere? For example, the following permutation function from the sorting in the matrix form is c(1,2,3), c(2,1,3)
sort(c("bc","ac","dd"))
[1] "ac" "bc" "dd"
I think you are asking for the `order` function.
I try to find it in the permutations/permute package, but I can't find it
John
[[alternative HTML version deleted]]
Hello,
Like David said, what you are trying to do with sort() can be done with
order() in a much easier way.
First, your code
x <- sort(c("bc","ac","dd"), index.return=TRUE)
Now, with function order()
i <- order(c("bc", "ac", "dd"))
y <- c("D","E", "F")[i]
y
#[1] "E" "D" "F"
# This will give you the inverse,
# just apply order() to the output of order(),
# function order() is its own inverse
y[ order(i) ]
#[1] "D" "E" "F"
Finally, compare the results and see that they are exactly the same.
identical(x$ix, i)
#[1] TRUE
Hope this helps,
Rui Barradas
sort(c("bc","ac","dd"), index.return=TRUE)
$x
[1] "ac" "bc" "dd"
$ix
[1] 2 1 3
We have the permutation, namely 1-->2, 2-->1, 3-->3.
How can I apply the permutation function to a new set
c("D","E", "F")?
so that the result is
c("E","D", "F").
2018-05-23 11:06 GMT+08:00 David Winsemius <dwinsemius at comcast.net>:
On May 22, 2018, at 10:57 PM, John <miaojpm at gmail.com> wrote: Thanks, David. I got the answer from the web. Is there any easy way to permute a set (e.g., a set of characters) by
the permutation it returns? Thanks,
x <- c(10,7,4,3,8,2) sort(x, index.return=TRUE)
$x [1] 2 3 4 7 8 10 $ix [1] 6 4 3 2 5 1
I don't understand what is being requested. The $ix value is the same as the one returned `by order`. David.
2018-05-23 10:49 GMT+08:00 David Winsemius <dwinsemius at comcast.net>:
On May 22, 2018, at 10:06 PM, John <miaojpm at gmail.com> wrote: Hi, Is there any way to find the permutation function of the sorting and
to
apply the function (or its inverse) elsewhere? For example, the following permutation function from the sorting in
the
matrix form is c(1,2,3), c(2,1,3)
sort(c("bc","ac","dd"))
[1] "ac" "bc" "dd"
I think you are asking for the `order` function.
I try to find it in the permutations/permute package, but I can't
find it
John
[[alternative HTML version deleted]]
[[alternative HTML version deleted]]
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Thanks, David, Rui and Jeff!!! The function order works much better. I should have used an example where the permutation and its inverse are not identical:
i <- order(c("B", "C", "A"))
i
[1] 3 1 2
c("D","E", "F")[i]
[1] "F" "D" "E"
c("D","E", "F")[order(i)]
[1] "E" "F" "D" 2018-05-23 14:18 GMT+08:00 Rui Barradas <ruipbarradas at sapo.pt>:
Hello,
Like David said, what you are trying to do with sort() can be done with
order() in a much easier way.
First, your code
x <- sort(c("bc","ac","dd"), index.return=TRUE)
Now, with function order()
i <- order(c("bc", "ac", "dd"))
y <- c("D","E", "F")[i]
y
#[1] "E" "D" "F"
# This will give you the inverse,
# just apply order() to the output of order(),
# function order() is its own inverse
y[ order(i) ]
#[1] "D" "E" "F"
Finally, compare the results and see that they are exactly the same.
identical(x$ix, i)
#[1] TRUE
Hope this helps,
Rui Barradas
On 5/23/2018 4:37 AM, John wrote:
sort(c("bc","ac","dd"), index.return=TRUE)
$x
[1] "ac" "bc" "dd"
$ix
[1] 2 1 3
We have the permutation, namely 1-->2, 2-->1, 3-->3.
How can I apply the permutation function to a new set
c("D","E", "F")?
so that the result is
c("E","D", "F").
2018-05-23 11:06 GMT+08:00 David Winsemius <dwinsemius at comcast.net>:
On May 22, 2018, at 10:57 PM, John <miaojpm at gmail.com> wrote:
Thanks, David. I got the answer from the web. Is there any easy way to permute a set (e.g., a set of characters) by
the permutation it returns? Thanks,
x <- c(10,7,4,3,8,2)
sort(x, index.return=TRUE)
$x [1] 2 3 4 7 8 10 $ix [1] 6 4 3 2 5 1
I don't understand what is being requested. The $ix value is the same as the one returned `by order`. David. 2018-05-23 10:49 GMT+08:00 David Winsemius <dwinsemius at comcast.net>:
On May 22, 2018, at 10:06 PM, John <miaojpm at gmail.com> wrote:
Hi, Is there any way to find the permutation function of the sorting and
to
apply the function (or its inverse) elsewhere?
For example, the following permutation function from the sorting in
the
matrix form is
c(1,2,3), c(2,1,3)
sort(c("bc","ac","dd"))
[1] "ac" "bc" "dd"
I think you are asking for the `order` function. I try to find it in the permutations/permute package, but I can't
find it
John
[[alternative HTML version deleted]]
[[alternative HTML version deleted]]
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posti ng-guide.html and provide commented, minimal, self-contained, reproducible code.