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ordering in dotplot

6 messages · Luca De Benedictis, Chuck Cleland, Giampiero Salvi +3 more

Luca De Benedictis
# 
Dear R-friends,

the dataset I am using (data.it) is organized as follows

partner    stp    btp    reg
hk    0.64    1    s
ger    0.27    1    d
tur    0.27    1    s
rom    0.24    1    s-f
por    0.24    1    s
spa    0.23    1    s
gre    0.22    1    d-f
aus    0.17    1    d
uk    0.16    1    s
be    0.16    1    d
arg    0.15    1    s
usa    0.13    1    d-f
fra    0.13    1    s
neth    0.05    1    s-f
pol    0.05    1    d
bra    0.04    1    s
ko    0.006    1    s
un    -0.009    2    d-f
svi    -0.022    2    s-f
cin    -0.040    2   d
ru    -0.074    2    d-f
mex    -0.077    2    s
...    ...    ...    ...

and plotting it using dotplot, I specified the script as:

library(lattice)
attach(data.ita)
dotplot(reg~stp | partner, data=data.ita, groups=btp,
            xlab=list("Data - 
it",cex=1.5),col=c("black","red"),aspect=0.3,as.table=TRUE,xlim=c(-1,1))
detach(data.ita)

In the resulting plot the variable "reg" is ordered alphabetically. 
Instead, I would like the variable to be plotted in the following order: 
"s", "s-f", "d", "d-f".
How can I do it?

Many thanks
Luca
Chuck Cleland
#
Luca De Benedictis wrote:
Make that an ordered factor as follows:

data.it$reg <- ordered(data.it$reg, levels=c("s", "s-f", "d", "d-f"))

hope this helps,

Chuck Cleland
Giampiero Salvi
# 
Hi,
I'd like to store N vectors of different lengths, and to be able to
access them with an index, and eventually free the memory for one
of them without modifying the indexes to the others.

In C this would be a vector of N pointers that point to memory cells
independently allocated.

For example

int *pv[3];

pv[0] = (int *) malloc(13 * sizeof(int));
pv[1] = (int *) malloc(7 * sizeof(int));
pv[2] = (int *) malloc(110 * sizeof(int));

free(pv[1])
...

What is the best data type (or class) in R to do such a thing?

Thank you!
Giampiero
_________________________________________________________
Giampiero Salvi, M.Sc.          www.speech.kth.se/~giampi
Speech, Music and Hearing       Tel:      +46-8-790 75 62
Royal Institute of Technology   Fax:      +46-8-790 78 54
Drottning Kristinasv. 31,  SE-100 44,  Stockholm,  Sweden
Barry Rowlingson
#
Giampiero Salvi wrote:
A list, with vector elements (index starts at 1 in R):

  pv = list()
  pv[[1]] = real(13)
  pv[[2]] = real(7)
  pv[[3]] = real(110)

  then the equivalent of freeing the memory and keeping the indexing 
would be:

  pv[[2]] = real(0)

  and NOT

  pv[[2]] = NULL  (which deletes element 2)

  *BUT* I dont know if R will really free() the memory at that point. 
You may need to force the garbage collection with gc()....

Baz
Brian Ripley
#
On Mon, 2 Feb 2004, Giampiero Salvi wrote:

            

      
      
      
    

        
Sounds like an R list.  However, in R you cannot free memory, but what 
you can do (carefully) is to change the list element to NULL and then 
memory will be salvaged at a future garbage collection.

z <- vector("list", 3)
z[[1]] <- integer(13)
z[[2]] <- integer(7)
z[[3]] <- integer(110)

then

z[1] <- list(NULL)  # and not z[[1]] <- NULL

will potentially release the memory allocated for the first element.

  
    

      
      
    

  


  


      

    

    

      
      

        


  

        

      Uwe Ligges
    

    

      
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Giampiero Salvi wrote:

        

            

      
      
      
    

        
See ?list

Uwe Ligges