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Question about #1 zoo-faq

3 messages · Alexander Salim, Gabor Grothendieck, Duncan Murdoch

Alexander Salim
# 
Hi all,

I have a zoo object issue. When I create a zoo object I have following error
message: "some methods for 'zoo' objects do not work if the index entries in
'order.by' are not unique."

I checked if I have some duplicates in the 'Time' column, R says yes, but
when I check the data set I can't explain why. Here is the code.
[1] 5
Time fkl010z0 tre200s0 gre000z0 prestas0 rre150z0
tde200s0 ure200s0

4046 2009-03-29 02:10:00      0.5      3.0        0    942.1        0
1.9     92.7

4047 2009-03-29 02:20:00      0.3      2.7        0    942.1        0
1.7     93.4

4048 2009-03-29 02:30:00      0.6      2.8        0    942.2        0
1.8     92.9

4049 2009-03-29 02:40:00      0.4      2.8        0    942.3        0
1.6     92.0

4050 2009-03-29 02:50:00      0.8      2.8        0    942.2        0
1.6     92.1
Enclosed is a dput file with the data set.

 

Thank you for your help.

 

Regards,

Alex
Gabor Grothendieck
#
On Sat, Dec 4, 2010 at 5:40 AM, Alexander Salim <salim at gmx.ch> wrote:
There is nothing attached.  Try again putting the dput output in the
body of your email or else make sure the attached file is a text file
with the extension .txt .
Duncan Murdoch
#
On 04/12/2010 5:40 AM, Alexander Salim wrote:
Remember that duplicated() doesn't return TRUE for all copies, only the 
second (and later ones).  For example,

duplicated(c(1,1,2,2,1))

returns

[1] FALSE  TRUE FALSE  TRUE  TRUE

I believe the %in% operator works on zoo objects, so you can see all 
copies using

x <- with(dataSet1, Time %in% Time[duplicated(Time)])
dataSet1[x,]

Duncan Murdoch