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Using lm to estimate a parameter?

3 messages · hellen, Uwe Ligges, Hans W Borchers

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On 19.02.2013 11:23, hellen wrote:
Neither, it is nonlinear in the parameters. See ?nls or ?optim, for example.

Uwe Ligges
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Uwe Ligges <ligges <at> statistik.tu-dortmund.de> writes:
Well, if the Z values are not too small, you can linearize it as

    U = (X Y - Y Z) / Z = L X

and solve it with lm(U ~ X - 1), that is without absolute term.