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pretty formatting of lists

3 messages · Thomas Petzoldt, jim holtman

Thomas Petzoldt
# 
Hello,

is there already a function in any R package which does
source code formatting of deparsed lists?

Let's create the following list:

x <- list(a = round(rnorm(3), 2),
           b = round(rnorm(3), 2))

xx <-c(aa = round(rnorm(30)), f = function(a) a + b, list(x, x))


Now, I want deparse it in a way that yields something like:


list(
   aa = c(0.25, 0.18, 0.84, -1.25, 0.09, -0.99, 1.64,
     1.42, -1.29, -0.14, -1.07, -1.05, 0.98, 0.33,
     1.76, -1.66, 0.96, -0.21, -1.29, 0.78, -0.4,
     -1.63, -0.78, -1.05, 1.27, -1.44, 0.12, -0.4,
     0.02, 1.03),
   f = function (a) a + b,
   list(
     a = c(2.22, 0.36, 0.74),
     b = c(0.46, 0.41, 1.46)
   ),
   list(
     a = c(2.22, 0.36, 0.74),
     b = c(0.46, 0.41, 1.46)
   )
)


Thanks a lot!

Thomas P.
jim holtman
# 
Is this basically what you want?
$aa
 [1]  1.34 -0.21 -0.18 -0.10  0.71 -0.07 -0.04 -0.68 -0.32  0.06 -0.59
 0.53 -1.52  0.31 -1.54 -0.30
[17] -0.53 -0.65 -0.06 -1.91  1.18 -1.66 -0.46 -1.12 -0.75  2.09  0.02
-1.29 -1.64  0.45

$f
function(a) a + b

$a
$a$a
[1] -0.06 -0.16 -1.47

$a$b
[1] -0.48  0.42  1.36


$b
$b$a
[1] -0.06 -0.16 -1.47

$b$b
[1] -0.48  0.42  1.36
On Sun, Mar 16, 2008 at 8:47 AM, Thomas Petzoldt <thpe at simecol.de> wrote:

  
    

      
      
    

  


  


      

    

    

      
      

        


  

        

      Thomas Petzoldt
    

    

      
      #
    

  


  

      
jim holtman wrote:

            

      
      
      
    

        
No, I want a neat source code representation, not simply the printed
content -- technically something like the following, but more reader
friendly:

            

      
      
      
    

        
structure(list(aa = c(0.25, 0.18, 0.84, -1.25, 0.09, -0.99, 1.64,
1.42, -1.29, -0.14, -1.07, -1.05, 0.98, 0.33, 1.76, -1.66, 0.96,
-0.21, -1.29, 0.78, -0.4, -1.63, -0.78, -1.05, 1.27, -1.44, 0.12,
-0.4, 0.02, 1.03), f = function (a)
a + b, structure(list(a = c(2.22, 0.36, 0.74), b = c(0.46, 0.41,
1.46)), .Names = c("a", "b")), structure(list(a = c(2.22, 0.36,
0.74), b = c(0.46, 0.41, 1.46)), .Names = c("a", "b"))), .Names =
c("aa",  "f", "", ""))


I wonder whether a function for some kind of "pretty deparsing" already
exists before I start to write my own solution.

Thomas P.