Regular expression substitution ...

I would like to replace all occurences of

    /pc

with

   \%

using something like

sub("/pc", "\%", x)

but I am unable to make the '\' pass through.

Any hint?

Thanks,

Roberto
It's a bit strange:

 > sub("/pc", '\\%', x)
[1] "%"
 >
 > sub("/pc", '\\\\%', x)
[1] "\\%"

Also with fixed I'm not able to get a single \ as return value.

Sander

I would like to replace all occurences of

   /pc

with

  \%

using something like

sub("/pc", "\%", x)

but I am unable to make the '\' pass through.

Any hint?

Thanks,

Roberto

______________________________________________
R-help at r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
It's a bit strange:

 > sub("/pc", '\\%', x)
[1] "%"
 >
 > sub("/pc", '\\\\%', x)
[1] "\\%"

Also with fixed I'm not able to get a single \ as return value.
Well, you get the printed representation (i.e. the quoted backslash - 
quoted with anotern backslash).
Use cat(sub("/pc", '\\\\%', x)) to see the raw characters.

Uwe Ligges
Sander

On 2 nov 2009, at 12:36, Roberto Brunelli wrote:

I would like to replace all occurences of

   /pc

with

  \%

using something like

sub("/pc", "\%", x)

but I am unable to make the '\' pass through.

Any hint?

Thanks,

Roberto

______________________________________________
R-help at r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide 
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.