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Proportions of a vector
3 messages · Jim Silverton, Sarah Goslee, R. Michael Weylandt
If the values in xm are always going to be consecutive integers 1:n, then this:
prob.xm[xm]
xm
1 2 3 4 5 5 5 6 6
0.111 0.111 0.111 0.111 0.333 0.333 0.333 0.222 0.222
otherwise:
prob.xm[as.numeric(as.factor(xm))]
xm
1 2 3 4 5 5 5 6 6
0.111 0.111 0.111 0.111 0.333 0.333 0.333 0.222 0.222
(equivalent in this case).
Sarah
On Thu, Sep 22, 2011 at 3:41 PM, Jim Silverton <jim.silverton at gmail.com> wrote:
Hi all, I have a vector xm say: ?xm = c(1,2,3,4,5,5,5,6,6) I want to return a vector with the corresponding probabilities based on the amount of times the numbers occurred. For example, I should get the following vector for xm: prob.xm = c(1/9, 1/9, 1/9, 1/9, 3/9, 3/9, 3/9, 2/9, 2/9)
Using prop.table gives: Usage (with table)
prob.xm <- round( prop.table(table(xm)), digits=3) prob.xm
xm ? 1 ? ? 2 ? ? 3 ? ? 4 ? ? 5 ? ? 6 0.111 0.111 0.111 0.111 0.333 0.222 But I want the entire length of probabilities, not just a condensed version. Any help is greatl appreciated.
Sarah Goslee http://www.functionaldiversity.org
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