The values read into z2 came from a CSV file. Please consider this R
session:
> length(x2)
[1] 1632
> length(x)
[1] 1632
> length(z2)
[1] 1632
> head(z2)
[1] 28914.0 28960.5 28994.5 29083.0 29083.0 29083.0
> tail(z2)
[1] 32729.65 32751.85 32386.05 32379.75 32379.15 31977.15
> lm ( y ~ x2 + x, z2 )
Error in eval(predvars, data, env) :
numeric 'envir' arg not of length one
> lm ( y ~ x2 + x, as.data.frme(z2) )
Error in as.data.frme(z2) : could not find function "as.data.frme"
> lm ( y ~ x2 + x, as.data.frame(z2) )
Error in eval(predvars, data, env) :
numeric 'envir' arg not of length one
lm(formula = y ~ x2 + x, data = as.data.frame(z2))
Coefficients:
(Intercept) x2 x
-1.475e-09 1.000e+00 6.044e-13
> min(z2)
[1] 24420
> max(z2)
[1] 35524.85
> class(z2)
[1] "numeric"
>
where x is set to x = seq(1:1632)
and x2 is set to x^2
I am looking for an interpolating polynomial of the form:
Ax^2 + Bx + C
I do not think the results I got make sense. I believe that I have a
data type error. I do not understand why
I need to convert z2 to a data frame if it is already numeric.
Thanks,
Bob
Problem with LM
4 messages · Richard M. Heiberger, rsherry8, Bert Gunter
## This example, with your variable names, works correctly. z2 <- data.frame(y=1:5, x=c(1,5,2,3,5), x2=c(1,5,2,3,5)^2) z2 class(z2) length(z2) dim(z2) lm(y ~ x + x2, data=z2) ## note that that variable names y, x, x2 are column names of the ## data.frame z2 ## please review the definitions and examples of data.frame in ?data.frame ## also the argument requirements for lm in ?lm
On Tue, Dec 18, 2018 at 6:32 PM rsherry8 <rsherry8 at comcast.net> wrote:
The values read into z2 came from a CSV file. Please consider this R session:
> length(x2)
[1] 1632
> length(x)
[1] 1632
> length(z2)
[1] 1632
> head(z2)
[1] 28914.0 28960.5 28994.5 29083.0 29083.0 29083.0
> tail(z2)
[1] 32729.65 32751.85 32386.05 32379.75 32379.15 31977.15
> lm ( y ~ x2 + x, z2 )
Error in eval(predvars, data, env) : numeric 'envir' arg not of length one
> lm ( y ~ x2 + x, as.data.frme(z2) )
Error in as.data.frme(z2) : could not find function "as.data.frme"
> lm ( y ~ x2 + x, as.data.frame(z2) )
Error in eval(predvars, data, env) : numeric 'envir' arg not of length one lm(formula = y ~ x2 + x, data = as.data.frame(z2)) Coefficients: (Intercept) x2 x -1.475e-09 1.000e+00 6.044e-13
> min(z2)
[1] 24420
> max(z2)
[1] 35524.85
> class(z2)
[1] "numeric"
>
where x is set to x = seq(1:1632)
and x2 is set to x^2
I am looking for an interpolating polynomial of the form:
Ax^2 + Bx + C
I do not think the results I got make sense. I believe that I have a
data type error. I do not understand why
I need to convert z2 to a data frame if it is already numeric.
Thanks,
Bob
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Richard, It is now working. Thank you very much. Bob
On 12/18/2018 7:10 PM, Richard M. Heiberger wrote:
## This example, with your variable names, works correctly. z2 <- data.frame(y=1:5, x=c(1,5,2,3,5), x2=c(1,5,2,3,5)^2) z2 class(z2) length(z2) dim(z2) lm(y ~ x + x2, data=z2) ## note that that variable names y, x, x2 are column names of the ## data.frame z2 ## please review the definitions and examples of data.frame in ?data.frame ## also the argument requirements for lm in ?lm On Tue, Dec 18, 2018 at 6:32 PM rsherry8 <rsherry8 at comcast.net> wrote:
The values read into z2 came from a CSV file. Please consider this R session:
> length(x2)
[1] 1632
> length(x)
[1] 1632
> length(z2)
[1] 1632
> head(z2)
[1] 28914.0 28960.5 28994.5 29083.0 29083.0 29083.0
> tail(z2)
[1] 32729.65 32751.85 32386.05 32379.75 32379.15 31977.15
> lm ( y ~ x2 + x, z2 )
Error in eval(predvars, data, env) :
numeric 'envir' arg not of length one
> lm ( y ~ x2 + x, as.data.frme(z2) )
Error in as.data.frme(z2) : could not find function "as.data.frme"
> lm ( y ~ x2 + x, as.data.frame(z2) )
Error in eval(predvars, data, env) :
numeric 'envir' arg not of length one
lm(formula = y ~ x2 + x, data = as.data.frame(z2))
Coefficients:
(Intercept) x2 x
-1.475e-09 1.000e+00 6.044e-13
> min(z2)
[1] 24420
> max(z2)
[1] 35524.85
> class(z2)
[1] "numeric"
>
where x is set to x = seq(1:1632)
and x2 is set to x^2
I am looking for an interpolating polynomial of the form:
Ax^2 + Bx + C
I do not think the results I got make sense. I believe that I have a
data type error. I do not understand why
I need to convert z2 to a data frame if it is already numeric.
Thanks,
Bob
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
... Perhaps worth adding is the use of poly() rather than separately created terms for (non/orthogonal) polynomials: lm(y ~ poly(x, degree =2) #orthogonal polyomial of degree 2 see ?poly for details. -- Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Tue, Dec 18, 2018 at 6:14 PM rsherry8 <rsherry8 at comcast.net> wrote:
Richard, It is now working. Thank you very much. Bob On 12/18/2018 7:10 PM, Richard M. Heiberger wrote:
## This example, with your variable names, works correctly. z2 <- data.frame(y=1:5, x=c(1,5,2,3,5), x2=c(1,5,2,3,5)^2) z2 class(z2) length(z2) dim(z2) lm(y ~ x + x2, data=z2) ## note that that variable names y, x, x2 are column names of the ## data.frame z2 ## please review the definitions and examples of data.frame in
?data.frame
## also the argument requirements for lm in ?lm On Tue, Dec 18, 2018 at 6:32 PM rsherry8 <rsherry8 at comcast.net> wrote:
The values read into z2 came from a CSV file. Please consider this R session:
> length(x2)
[1] 1632
> length(x)
[1] 1632
> length(z2)
[1] 1632
> head(z2)
[1] 28914.0 28960.5 28994.5 29083.0 29083.0 29083.0
> tail(z2)
[1] 32729.65 32751.85 32386.05 32379.75 32379.15 31977.15
> lm ( y ~ x2 + x, z2 )
Error in eval(predvars, data, env) :
numeric 'envir' arg not of length one
> lm ( y ~ x2 + x, as.data.frme(z2) )
Error in as.data.frme(z2) : could not find function "as.data.frme"
> lm ( y ~ x2 + x, as.data.frame(z2) )
Error in eval(predvars, data, env) :
numeric 'envir' arg not of length one
lm(formula = y ~ x2 + x, data = as.data.frame(z2))
Coefficients:
(Intercept) x2 x
-1.475e-09 1.000e+00 6.044e-13
> min(z2)
[1] 24420
> max(z2)
[1] 35524.85
> class(z2)
[1] "numeric"
>
where x is set to x = seq(1:1632)
and x2 is set to x^2
I am looking for an interpolating polynomial of the form:
Ax^2 + Bx + C
I do not think the results I got make sense. I believe that I have a
data type error. I do not understand why
I need to convert z2 to a data frame if it is already numeric.
Thanks,
Bob
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.