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simple question beginner
3 messages · Λεωνίδας Μπαντής, Michael Lawrence, PIKAL Petr
names() is a great function for finding out how to get info from objects of unknown structure, so try: names(out) 2009/3/10 ???????? ??????? <bleonidas25 at yahoo.gr>:
Hi there,
I am beginner in R and I have some basic question. Suppose I run a common procedure such as a t test or cox model like below:
out<-coxph( Surv(tstart,tstop, death1) ~ x1+x1:log(tstop+1) , test1,method=c("breslow"))
Which yields the following result:
Call:
coxph(formula = Surv(tstart, tstop, death1) ~ x1 + x1:log(tstop +
??? 1), data = test1, method = c("breslow"))
?????????????????? coef exp(coef) se(coef)???? z??? p
x1??????????????? -9.58? 6.89e-05???? 6.83 -1.40 0.16
x1:log(tstop + 1)? 6.90? 9.93e+02???? 5.63? 1.23 0.22
Likelihood ratio test=2.97? on 2 df, p=0.226? n= 120
Now I simply want to create an array (let "a") with the coefficients. I.e. I want
a<-c(-9.58, 6.90)
Generally how can take the elements I want from the output matrix above for further manipulation?
Thanks in advance for any answer!!
___________________________________________________________ ?????????????? Yahoo!; ?????????? ?? ?????????? ???????? (spam); ?? Yahoo! Mail ???????? ??? ???????? ?????? ????????? ???? ??? ??????????? ????????? http://login.yahoo.com/config/mail?.intl=gr ? ? ? ?[[alternative HTML version deleted]] ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Mike Lawrence Graduate Student Department of Psychology Dalhousie University Looking to arrange a meeting? Check my public calendar: http://tinyurl.com/mikes-public-calendar ~ Certainty is folly... I think. ~
Hi r-help-bounces at r-project.org napsal dne 10.03.2009 12:21:38:
Hi there, I am beginner in R and I have some basic question. Suppose I run a
common
procedure such as a t test or cox model like below: out<-coxph( Surv(tstart,tstop, death1) ~ x1+x1:log(tstop+1) ,
test1,method=c
("breslow"))
Which yields the following result:
Call:
coxph(formula = Surv(tstart, tstop, death1) ~ x1 + x1:log(tstop +
1), data = test1, method = c("breslow"))
coef exp(coef) se(coef) z p
x1 -9.58 6.89e-05 6.83 -1.40 0.16
x1:log(tstop + 1) 6.90 9.93e+02 5.63 1.23 0.22
Likelihood ratio test=2.97 on 2 df, p=0.226 n= 120
Now I simply want to create an array (let "a") with the coefficients.
I.e. I want Most probably coef will work here If you had tried help.search ??"coefficients" you would find several appropriate items. Besides str(object) is also a good starting point for inspection of any object. Regards Petr
a<-c(-9.58, 6.90) Generally how can take the elements I want from the output matrix above
for
further manipulation? Thanks in advance for any answer!!
___________________________________________________________ ?????????????? Yahoo!; ?????????? ?? ?????????? ???????? (spam); ?? Yahoo! Mail ???????? ??? ???????? ?????? ????????? ???? ??? ??????????? ????????? http://login.yahoo.com/config/mail?.intl=gr [[alternative HTML version deleted]] ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.