Hello R user, Data below represent year in decimal. I would like to catagorize it in such a way that any valye [0,1] goes to catagory 1 , (1,2] goes to catagory 2 and so on.. Any suggestion how it can be done with if else statement or any other way? 2.880556 0.616667 5.083333 0.858333 0.466667 2.936111 4.258333 0.258333 2.033333 2.583333 1.088889 0.447222 1.872222 0.080556 4.033333 4.116667 1.633333 2.147222 Thank you for your help. Bibek
Defining categories
8 messages · Jorge I Velez, PIKAL Petr, arun +1 more
Hi, May be this: dat1<-read.table(text=" 2.880556 0.616667 5.083333 0.858333 0.466667 2.936111 4.258333 0.258333 2.033333 2.583333 1.088889 0.447222 1.872222 0.080556 4.033333 4.116667 1.633333 2.147222 ",sep="",header=FALSE) dat1$category<-ifelse(dat1$V1<=1 &dat1$V1>0,1,ifelse(dat1$V1>1 & dat1$V1<=2,2,ifelse(dat1$V1>2&dat1$V1<=3,3,ifelse(dat1$V1>3&dat1$V1<=4,4,ifelse(dat1$V1>4&dat1$V1<=5,5,6))))) ?head(dat1) #??????? V1 category #1 2.880556??????? 3 #2 0.616667??????? 1 #3 5.083333??????? 6 #4 0.858333??????? 1 #5 0.466667??????? 1 #6 2.936111??????? 3 A.K. ----- Original Message ----- From: bibek sharma <mbhpathak at gmail.com> To: r-help at r-project.org Cc: Sent: Wednesday, October 24, 2012 6:52 PM Subject: [R] Defining categories Hello R user, Data below represent year in decimal. I would like to catagorize it in such a way that any valye [0,1] goes to catagory 1 , (1,2] goes to catagory 2 and so on.. Any suggestion how it can be done with if else statement or any other way? 2.880556 0.616667 5.083333 0.858333 0.466667 2.936111 4.258333 0.258333 2.033333 2.583333 1.088889 0.447222 1.872222 0.080556 4.033333 4.116667 1.633333 2.147222 Thank you for? your help. Bibek ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
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Hi,
?(Jorge: Thanks for the suggestion.)
cut? will be much easier.
dat1<-read.table(text="
2.880556
0.616667
5.083333
0.858333
0.466667
2.936111
4.258333
0.258333
2.033333
2.583333
1.088889
0.447222
1.872222
0.080556
4.033333
4.116667
1.633333
2.147222
",sep="",header=FALSE)
?dat1$Categ<-cut(dat1$V1,breaks=c(0,1,2,3,4,5,6))
#Either
library(car)
dat1$Categ<-recode(dat1$Categ,"'(0,1]'=1;'(1,2]'=2;'(2,3]'=3;'(3,4]'=4;'(4,5]'=5;'(5,6]'=6")
#or
dat1$Categ<-as.numeric(gsub(".*\\,(\\d+).*","\\1",dat1$Categ))
#formats the Categ column.
head(dat1)
#??????? V1 Categ
#1 2.880556???? 3
#2 0.616667???? 1
#3 5.083333???? 6
#4 0.858333???? 1
#5 0.466667???? 1
#6 2.936111???? 3
A.K.
From: Jorge I Velez <jorgeivanvelez at gmail.com>
To: arun <smartpink111 at yahoo.com>
Cc: bibek sharma <mbhpathak at gmail.com>; R help <r-help at r-project.org>
Sent: Wednesday, October 24, 2012 7:27 PM
Subject: Re: [R] Defining categories
To: arun <smartpink111 at yahoo.com>
Cc: bibek sharma <mbhpathak at gmail.com>; R help <r-help at r-project.org>
Sent: Wednesday, October 24, 2012 7:27 PM
Subject: Re: [R] Defining categories
See ?cut for a simpler way of doing this. HTH, Jorge.- On Thu, Oct 25, 2012 at 10:02 AM, arun <> wrote: Hi, >May be this: >dat1<-read.table(text=" > >2.880556 >0.616667 >5.083333 >0.858333 >0.466667 >2.936111 >4.258333 >0.258333 >2.033333 >2.583333 >1.088889 >0.447222 >1.872222 >0.080556 >4.033333 >4.116667 >1.633333 >2.147222 >",sep="",header=FALSE) >dat1$category<-ifelse(dat1$V1<=1 &dat1$V1>0,1,ifelse(dat1$V1>1 & dat1$V1<=2,2,ifelse(dat1$V1>2&dat1$V1<=3,3,ifelse(dat1$V1>3&dat1$V1<=4,4,ifelse(dat1$V1>4&dat1$V1<=5,5,6))))) > > >?head(dat1) >#??????? V1 category >#1 2.880556??????? 3 >#2 0.616667??????? 1 >#3 5.083333??????? 6 >#4 0.858333??????? 1 >#5 0.466667??????? 1 >#6 2.936111??????? 3 >A.K. > > > > >----- Original Message ----- >From: bibek sharma <> >To: r-help at r-project.org >Cc: >Sent: Wednesday, October 24, 2012 6:52 PM >Subject: [R] Defining categories > >Hello R user, > >Data below represent year in decimal. I would like to catagorize it >in such a way that any valye [0,1] goes to catagory 1 , (1,2] goes to >catagory 2 and so on.. >Any suggestion how it can be done with if else statement or any other way? > >2.880556 >0.616667 >5.083333 >0.858333 >0.466667 >2.936111 >4.258333 >0.258333 >2.033333 >2.583333 >1.088889 >0.447222 >1.872222 >0.080556 >4.033333 >4.116667 >1.633333 >2.147222 > >Thank you for? your help. >Bibek > >______________________________________________ >R-help at r-project.org mailing list >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code. > > >______________________________________________ >R-help at r-project.org mailing list >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code. >
Hi Maybe also findInterval can be used dat1$cat<-findInterval(dat1$V1, 1:6, rightmost.closed = T, all.inside = T) It is said to be more efficient than cut. Regards Petr
-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
project.org] On Behalf Of arun
Sent: Thursday, October 25, 2012 3:32 AM
To: Jorge I Velez; bibek sharma
Cc: R help
Subject: Re: [R] Defining categories
Hi,
?(Jorge: Thanks for the suggestion.)
cut? will be much easier.
dat1<-read.table(text="
2.880556
0.616667
5.083333
0.858333
0.466667
2.936111
4.258333
0.258333
2.033333
2.583333
1.088889
0.447222
1.872222
0.080556
4.033333
4.116667
1.633333
2.147222
",sep="",header=FALSE)
?dat1$Categ<-cut(dat1$V1,breaks=c(0,1,2,3,4,5,6))
#Either
library(car)
dat1$Categ<-
recode(dat1$Categ,"'(0,1]'=1;'(1,2]'=2;'(2,3]'=3;'(3,4]'=4;'(4,5]'=5;'(
5,6]'=6")
#or
dat1$Categ<-as.numeric(gsub(".*\\,(\\d+).*","\\1",dat1$Categ))
#formats the Categ column.
head(dat1)
#??????? V1 Categ
#1 2.880556???? 3
#2 0.616667???? 1
#3 5.083333???? 6
#4 0.858333???? 1
#5 0.466667???? 1
#6 2.936111???? 3
A.K.
________________________________ From: Jorge I Velez <jorgeivanvelez at gmail.com> To: arun <smartpink111 at yahoo.com> Cc: bibek sharma <mbhpathak at gmail.com>; R help <r-help at r-project.org> Sent: Wednesday, October 24, 2012 7:27 PM Subject: Re: [R] Defining categories See ?cut for a simpler way of doing this. HTH, Jorge.- On Thu, Oct 25, 2012 at 10:02 AM, arun <> wrote: Hi, May be this: dat1<-read.table(text=" 2.880556 0.616667 5.083333 0.858333 0.466667 2.936111 4.258333 0.258333 2.033333 2.583333 1.088889 0.447222 1.872222 0.080556 4.033333 4.116667 1.633333 2.147222 ",sep="",header=FALSE) dat1$category<-ifelse(dat1$V1<=1 &dat1$V1>0,1,ifelse(dat1$V1>1 & dat1$V1<=2,2,ifelse(dat1$V1>2&dat1$V1<=3,3,ifelse(dat1$V1>3&dat1$V1<=4, 4,ifelse(dat1$V1>4&dat1$V1<=5,5,6))))) ?head(dat1) #??????? V1 category #1 2.880556??????? 3 #2 0.616667??????? 1 #3 5.083333??????? 6 #4 0.858333??????? 1 #5 0.466667??????? 1 #6 2.936111??????? 3 A.K. ----- Original Message ----- From: bibek sharma <> To: r-help at r-project.org Cc: Sent: Wednesday, October 24, 2012 6:52 PM Subject: [R] Defining categories Hello R user, Data below represent year in decimal. I would like to catagorize it in such a way that any valye [0,1] goes to catagory 1 , (1,2] goes to catagory 2 and so on.. Any suggestion how it can be done with if else statement or any other way? 2.880556 0.616667 5.083333 0.858333 0.466667 2.936111 4.258333 0.258333 2.033333 2.583333 1.088889 0.447222 1.872222 0.080556 4.033333 4.116667 1.633333 2.147222 Thank you for? your help. Bibek ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code.
Thank you Dr. Pikal for this alternative. Best, Jorge.- Sent from my phone. Please excuse my brevity and misspelling.
On Oct 25, 2012, at 8:29 PM, PIKAL Petr <petr.pikal at precheza.cz> wrote:
Hi Maybe also findInterval can be used dat1$cat<-findInterval(dat1$V1, 1:6, rightmost.closed = T, all.inside = T) It is said to be more efficient than cut. Regards Petr
-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
project.org] On Behalf Of arun
Sent: Thursday, October 25, 2012 3:32 AM
To: Jorge I Velez; bibek sharma
Cc: R help
Subject: Re: [R] Defining categories
Hi,
(Jorge: Thanks for the suggestion.)
cut? will be much easier.
dat1<-read.table(text="
2.880556
0.616667
5.083333
0.858333
0.466667
2.936111
4.258333
0.258333
2.033333
2.583333
1.088889
0.447222
1.872222
0.080556
4.033333
4.116667
1.633333
2.147222
",sep="",header=FALSE)
dat1$Categ<-cut(dat1$V1,breaks=c(0,1,2,3,4,5,6))
#Either
library(car)
dat1$Categ<-
recode(dat1$Categ,"'(0,1]'=1;'(1,2]'=2;'(2,3]'=3;'(3,4]'=4;'(4,5]'=5;'(
5,6]'=6")
#or
dat1$Categ<-as.numeric(gsub(".*\\,(\\d+).*","\\1",dat1$Categ))
#formats the Categ column.
head(dat1)
# V1 Categ
#1 2.880556 3
#2 0.616667 1
#3 5.083333 6
#4 0.858333 1
#5 0.466667 1
#6 2.936111 3
A.K.
________________________________ From: Jorge I Velez <jorgeivanvelez at gmail.com> To: arun <smartpink111 at yahoo.com> Cc: bibek sharma <mbhpathak at gmail.com>; R help <r-help at r-project.org> Sent: Wednesday, October 24, 2012 7:27 PM Subject: Re: [R] Defining categories See ?cut for a simpler way of doing this. HTH, Jorge.- On Thu, Oct 25, 2012 at 10:02 AM, arun <> wrote: Hi, May be this: dat1<-read.table(text=" 2.880556 0.616667 5.083333 0.858333 0.466667 2.936111 4.258333 0.258333 2.033333 2.583333 1.088889 0.447222 1.872222 0.080556 4.033333 4.116667 1.633333 2.147222 ",sep="",header=FALSE) dat1$category<-ifelse(dat1$V1<=1 &dat1$V1>0,1,ifelse(dat1$V1>1 & dat1$V1<=2,2,ifelse(dat1$V1>2&dat1$V1<=3,3,ifelse(dat1$V1>3&dat1$V1<=4, 4,ifelse(dat1$V1>4&dat1$V1<=5,5,6))))) head(dat1) # V1 category #1 2.880556 3 #2 0.616667 1 #3 5.083333 6 #4 0.858333 1 #5 0.466667 1 #6 2.936111 3 A.K. ----- Original Message ----- From: bibek sharma <> To: r-help at r-project.org Cc: Sent: Wednesday, October 24, 2012 6:52 PM Subject: [R] Defining categories Hello R user, Data below represent year in decimal. I would like to catagorize it in such a way that any valye [0,1] goes to catagory 1 , (1,2] goes to catagory 2 and so on.. Any suggestion how it can be done with if else statement or any other way? 2.880556 0.616667 5.083333 0.858333 0.466667 2.936111 4.258333 0.258333 2.033333 2.583333 1.088889 0.447222 1.872222 0.080556 4.033333 4.116667 1.633333 2.147222 Thank you for your help. Bibek ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code.
HI Petr, Thanks for sharing the function.? True, very efficient than cut. dat1$cat<-findInterval(dat1$V1, 1:6, rightmost.closed = T, all.inside = T) ????????????????????????????????????????????????? ^^^ ?#? May be the interval is 0:6. dat1$cat1<-findInterval(dat1$V1, 1:6, rightmost.closed = T, all.inside = T) ?dat1$cat2<-findInterval(dat1$V1, 0:6, rightmost.closed = T, all.inside = T) ?head(dat1) #??????? V1 cat1 cat2 #1 2.880556??? 2??? 3 #2 0.616667??? 1??? 1 #3 5.083333??? 5??? 6 #4 0.858333??? 1??? 1 #5 0.466667??? 1??? 1 #6 2.936111??? 2??? 3 A.K. ----- Original Message ----- From: PIKAL Petr <petr.pikal at precheza.cz> To: arun <smartpink111 at yahoo.com>; Jorge I Velez <jorgeivanvelez at gmail.com>; bibek sharma <mbhpathak at gmail.com> Cc: R help <r-help at r-project.org> Sent: Thursday, October 25, 2012 5:29 AM Subject: RE: [R] Defining categories Hi Maybe also findInterval can be used dat1$cat<-findInterval(dat1$V1, 1:6, rightmost.closed = T, all.inside = T) It is said to be more efficient than cut. Regards Petr
-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
project.org] On Behalf Of arun
Sent: Thursday, October 25, 2012 3:32 AM
To: Jorge I Velez; bibek sharma
Cc: R help
Subject: Re: [R] Defining categories
Hi,
?(Jorge: Thanks for the suggestion.)
cut? will be much easier.
dat1<-read.table(text="
2.880556
0.616667
5.083333
0.858333
0.466667
2.936111
4.258333
0.258333
2.033333
2.583333
1.088889
0.447222
1.872222
0.080556
4.033333
4.116667
1.633333
2.147222
",sep="",header=FALSE)
?dat1$Categ<-cut(dat1$V1,breaks=c(0,1,2,3,4,5,6))
#Either
library(car)
dat1$Categ<-
recode(dat1$Categ,"'(0,1]'=1;'(1,2]'=2;'(2,3]'=3;'(3,4]'=4;'(4,5]'=5;'(
5,6]'=6")
#or
dat1$Categ<-as.numeric(gsub(".*\\,(\\d+).*","\\1",dat1$Categ))
#formats the Categ column.
head(dat1)
#??????? V1 Categ
#1 2.880556???? 3
#2 0.616667???? 1
#3 5.083333???? 6
#4 0.858333???? 1
#5 0.466667???? 1
#6 2.936111???? 3
A.K.
________________________________ From: Jorge I Velez <jorgeivanvelez at gmail.com> To: arun <smartpink111 at yahoo.com> Cc: bibek sharma <mbhpathak at gmail.com>; R help <r-help at r-project.org> Sent: Wednesday, October 24, 2012 7:27 PM Subject: Re: [R] Defining categories See ?cut for a simpler way of doing this. HTH, Jorge.- On Thu, Oct 25, 2012 at 10:02 AM, arun <> wrote: Hi, May be this: dat1<-read.table(text=" 2.880556 0.616667 5.083333 0.858333 0.466667 2.936111 4.258333 0.258333 2.033333 2.583333 1.088889 0.447222 1.872222 0.080556 4.033333 4.116667 1.633333 2.147222 ",sep="",header=FALSE) dat1$category<-ifelse(dat1$V1<=1 &dat1$V1>0,1,ifelse(dat1$V1>1 & dat1$V1<=2,2,ifelse(dat1$V1>2&dat1$V1<=3,3,ifelse(dat1$V1>3&dat1$V1<=4, 4,ifelse(dat1$V1>4&dat1$V1<=5,5,6))))) ?head(dat1) #??????? V1 category #1 2.880556??????? 3 #2 0.616667??????? 1 #3 5.083333??????? 6 #4 0.858333??????? 1 #5 0.466667??????? 1 #6 2.936111??????? 3 A.K. ----- Original Message ----- From: bibek sharma <> To: r-help at r-project.org Cc: Sent: Wednesday, October 24, 2012 6:52 PM Subject: [R] Defining categories Hello R user, Data below represent year in decimal. I would like to catagorize it in such a way that any valye [0,1] goes to catagory 1 , (1,2] goes to catagory 2 and so on.. Any suggestion how it can be done with if else statement or any other way? 2.880556 0.616667 5.083333 0.858333 0.466667 2.936111 4.258333 0.258333 2.033333 2.583333 1.088889 0.447222 1.872222 0.080556 4.033333 4.116667 1.633333 2.147222 Thank you for? your help. Bibek ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code.
1 day later
Thank you all for your suggestions. It really helped me a lot. Best, Bibek
On Thu, Oct 25, 2012 at 4:44 AM, arun <smartpink111 at yahoo.com> wrote:
HI Petr,
Thanks for sharing the function. True, very efficient than cut.
dat1$cat<-findInterval(dat1$V1, 1:6, rightmost.closed = T, all.inside = T)
^^^
# May be the interval is 0:6.
dat1$cat1<-findInterval(dat1$V1, 1:6, rightmost.closed = T, all.inside = T)
dat1$cat2<-findInterval(dat1$V1, 0:6, rightmost.closed = T, all.inside = T)
head(dat1)
# V1 cat1 cat2
#1 2.880556 2 3
#2 0.616667 1 1
#3 5.083333 5 6
#4 0.858333 1 1
#5 0.466667 1 1
#6 2.936111 2 3
A.K.
----- Original Message -----
From: PIKAL Petr <petr.pikal at precheza.cz>
To: arun <smartpink111 at yahoo.com>; Jorge I Velez <jorgeivanvelez at gmail.com>; bibek sharma <mbhpathak at gmail.com>
Cc: R help <r-help at r-project.org>
Sent: Thursday, October 25, 2012 5:29 AM
Subject: RE: [R] Defining categories
Hi
Maybe also findInterval can be used
dat1$cat<-findInterval(dat1$V1, 1:6, rightmost.closed = T, all.inside = T)
It is said to be more efficient than cut.
Regards
Petr
-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
project.org] On Behalf Of arun
Sent: Thursday, October 25, 2012 3:32 AM
To: Jorge I Velez; bibek sharma
Cc: R help
Subject: Re: [R] Defining categories
Hi,
(Jorge: Thanks for the suggestion.)
cut? will be much easier.
dat1<-read.table(text="
2.880556
0.616667
5.083333
0.858333
0.466667
2.936111
4.258333
0.258333
2.033333
2.583333
1.088889
0.447222
1.872222
0.080556
4.033333
4.116667
1.633333
2.147222
",sep="",header=FALSE)
dat1$Categ<-cut(dat1$V1,breaks=c(0,1,2,3,4,5,6))
#Either
library(car)
dat1$Categ<-
recode(dat1$Categ,"'(0,1]'=1;'(1,2]'=2;'(2,3]'=3;'(3,4]'=4;'(4,5]'=5;'(
5,6]'=6")
#or
dat1$Categ<-as.numeric(gsub(".*\\,(\\d+).*","\\1",dat1$Categ))
#formats the Categ column.
head(dat1)
# V1 Categ
#1 2.880556 3
#2 0.616667 1
#3 5.083333 6
#4 0.858333 1
#5 0.466667 1
#6 2.936111 3
A.K.
________________________________ From: Jorge I Velez <jorgeivanvelez at gmail.com> To: arun <smartpink111 at yahoo.com> Cc: bibek sharma <mbhpathak at gmail.com>; R help <r-help at r-project.org> Sent: Wednesday, October 24, 2012 7:27 PM Subject: Re: [R] Defining categories See ?cut for a simpler way of doing this. HTH, Jorge.- On Thu, Oct 25, 2012 at 10:02 AM, arun <> wrote: Hi, May be this: dat1<-read.table(text=" 2.880556 0.616667 5.083333 0.858333 0.466667 2.936111 4.258333 0.258333 2.033333 2.583333 1.088889 0.447222 1.872222 0.080556 4.033333 4.116667 1.633333 2.147222 ",sep="",header=FALSE) dat1$category<-ifelse(dat1$V1<=1 &dat1$V1>0,1,ifelse(dat1$V1>1 & dat1$V1<=2,2,ifelse(dat1$V1>2&dat1$V1<=3,3,ifelse(dat1$V1>3&dat1$V1<=4, 4,ifelse(dat1$V1>4&dat1$V1<=5,5,6))))) head(dat1) # V1 category #1 2.880556 3 #2 0.616667 1 #3 5.083333 6 #4 0.858333 1 #5 0.466667 1 #6 2.936111 3 A.K. ----- Original Message ----- From: bibek sharma <> To: r-help at r-project.org Cc: Sent: Wednesday, October 24, 2012 6:52 PM Subject: [R] Defining categories Hello R user, Data below represent year in decimal. I would like to catagorize it in such a way that any valye [0,1] goes to catagory 1 , (1,2] goes to catagory 2 and so on.. Any suggestion how it can be done with if else statement or any other way? 2.880556 0.616667 5.083333 0.858333 0.466667 2.936111 4.258333 0.258333 2.033333 2.583333 1.088889 0.447222 1.872222 0.080556 4.033333 4.116667 1.633333 2.147222 Thank you for your help. Bibek ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code.