bind tables

Hi,

You don't even need to split.
This could be done
dat1<-read.table(text="
year? h? len fre
1994? 5 10.5? 2
1994? 5 14.0? 2
1994? 5 11.5? 1
1994? 9 13.0? 3
1994? 9 11.5? 1
1994? 9 13.5? 5
",sep="",header=TRUE)

?dat1[rep(row.names(dat1),dat1$fre),1:3]
#??? year h? len
#1?? 1994 5 10.5
#1.1 1994 5 10.5
#2?? 1994 5 14.0
#2.1 1994 5 14.0
#3?? 1994 5 11.5
#4?? 1994 9 13.0
#4.1 1994 9 13.0
#4.2 1994 9 13.0
#5?? 1994 9 11.5
#6?? 1994 9 13.5
#6.1 1994 9 13.5
#6.2 1994 9 13.5
#6.3 1994 9 13.5
#6.4 1994 9 13.5
A.K.



----- Original Message -----
From: "mmurenu at tiscali.it" <mmurenu at tiscali.it>
To: smartpink111 at yahoo.com
Cc: 
Sent: Saturday, January 12, 2013 1:23 PM
Subject: bind tables

Hi Arun,
Thank you very much for your reply.
I know that I was not clear enough, since my basic knowledge of r language.
To be more clear....

I have this df:

year? h? len fre
1994? 5 10.5?  2
1994? 5 14.0?  2
1994? 5 11.5?  1
1994? 9 13.0?  3
1994? 9 11.5?  1
1994? 9 13.5?  5


MY goal is to obtain:

year? h? len
1994? 5 10.5
1994? 5 10.5
1994? 5 14.0
1994? 5 14.0
1994? 5 11.5
1994? 9 13.0
1994? 9 13.0
1994? 9 13.0
1994? 9 11.5
1994? 9 13.5
1994? 9 13.5
1994? 9 13.5

i.e. disaggregate the freq variable.

To do that I'm trying to rbind as follow:
each row with fre=2 twice (aa,aa) having subset aa for fre=2
each row with fre=3 three times (aa,aa,aa) having subset aa for fre=3
each row with fre=3 three times (aa,aa,aa,aa,aa) having subset aa for fre=5

You probably know a faster and less rude way :)
best
Matteo