Hello,
I am using the dplyr's arrange() function to sort one of the many data frames on a character variable (named "prevalence").
Issue: I am not getting the desired output (line 7 is the problem, which should be the very last line in the sorted data frame) because the sorted field is character, not numeric.
The reproducible example and the output are appended below.
Is there any work-around to convert/treat this character variable (named "prevalence" in the data frame below) as numeric before using the arrange() function within the dplyr package?
Any hints will be appreciated.
Thanks,
Pradip Muhuri
# Reproducible Example
library("readr")
testdata <- read_csv(
"indicator, prevalence
1. Health check-up, 77.2 (1.19)
2. Blood cholesterol checked, 84.5 (1.14)
3. Recieved flu vaccine, 50.0 (1.33)
4. Blood pressure checked, 88.7 (0.88)
5. Aspirin use-problems, 11.7 (1.02)
6.Colonoscopy, 60.2 (1.41)
7. Sigmoidoscopy, 6.1 (0.61)
8. Blood stool test, 14.6 (1.00)
9.Mammogram, 72.6 (1.82)
10. Pap Smear test, 73.3 (2.37)")
# Sort on the character variable in descending order
arrange(testdata, desc(prevalence))
# Results from Console
indicator prevalence
(chr) (chr)
1 4. Blood pressure checked 88.7 (0.88)
2 2. Blood cholesterol checked 84.5 (1.14)
3 1. Health check-up 77.2 (1.19)
4 10. Pap Smear test 73.3 (2.37)
5 9.Mammogram 72.6 (1.82)
6 6.Colonoscopy 60.2 (1.41)
7 7. Sigmoidoscopy 6.1 (0.61)
8 3. Recieved flu vaccine 50.0 (1.33)
9 8. Blood stool test 14.6 (1.00)
10 5. Aspirin use-problems 11.7 (1.02)
Pradip K. Muhuri, AHRQ/CFACT
5600 Fishers Lane # 7N142A, Rockville, MD 20857
Tel: 301-427-1564
dplyr's arrange function
4 messages · Muhuri, Pradip (AHRQ/CFACT), Daniel Nordlund, Jim Lemon +1 more
On 6/15/2016 2:08 PM, Muhuri, Pradip (AHRQ/CFACT) wrote:
Hello,
I am using the dplyr's arrange() function to sort one of the many data frames on a character variable (named "prevalence").
Issue: I am not getting the desired output (line 7 is the problem, which should be the very last line in the sorted data frame) because the sorted field is character, not numeric.
The reproducible example and the output are appended below.
Is there any work-around to convert/treat this character variable (named "prevalence" in the data frame below) as numeric before using the arrange() function within the dplyr package?
Any hints will be appreciated.
Thanks,
Pradip Muhuri
# Reproducible Example
library("readr")
testdata <- read_csv(
"indicator, prevalence
1. Health check-up, 77.2 (1.19)
2. Blood cholesterol checked, 84.5 (1.14)
3. Recieved flu vaccine, 50.0 (1.33)
4. Blood pressure checked, 88.7 (0.88)
5. Aspirin use-problems, 11.7 (1.02)
6.Colonoscopy, 60.2 (1.41)
7. Sigmoidoscopy, 6.1 (0.61)
8. Blood stool test, 14.6 (1.00)
9.Mammogram, 72.6 (1.82)
10. Pap Smear test, 73.3 (2.37)")
# Sort on the character variable in descending order
arrange(testdata, desc(prevalence))
# Results from Console
indicator prevalence
(chr) (chr)
1 4. Blood pressure checked 88.7 (0.88)
2 2. Blood cholesterol checked 84.5 (1.14)
3 1. Health check-up 77.2 (1.19)
4 10. Pap Smear test 73.3 (2.37)
5 9.Mammogram 72.6 (1.82)
6 6.Colonoscopy 60.2 (1.41)
7 7. Sigmoidoscopy 6.1 (0.61)
8 3. Recieved flu vaccine 50.0 (1.33)
9 8. Blood stool test 14.6 (1.00)
10 5. Aspirin use-problems 11.7 (1.02)
Pradip K. Muhuri, AHRQ/CFACT
5600 Fishers Lane # 7N142A, Rockville, MD 20857
Tel: 301-427-1564
The problem is that you are sorting a character variable.
testdata$prevalence
[1] "77.2 (1.19)" "84.5 (1.14)" "50.0 (1.33)" "88.7 (0.88)" "11.7 (1.02)" [6] "60.2 (1.41)" "6.1 (0.61)" "14.6 (1.00)" "72.6 (1.82)" "73.3 (2.37)"
Notice that the 7th element is "6.1 (0.61)". The first CHARACTER is a "6", so it is going to sort BEFORE the "50.0 (1.33)" (in descending order). If you want the character value of line 7 to sort last, it would need to be "06.1 (0.61)" or " 6.1 (0.61)" (notice the leading space). Hope this is helpful, Dan Daniel Nordlund Port Townsend, WA USA
Hi Pradip,
I'll assume that you are reading the data from a file:
pm.df<-read.csv("pmdat.txt",stringsAsFactors=FALSE)
# create a vector of numeric values of prevalence
numprev<-as.numeric(sapply(strsplit(trimws(pm.df$prevalence)," "),"[",1))
# order the data frame by that vector
pm.df[order(numprev),]
Jim
On Thu, Jun 16, 2016 at 7:08 AM, Muhuri, Pradip (AHRQ/CFACT)
<Pradip.Muhuri at ahrq.hhs.gov> wrote:
Hello,
I am using the dplyr's arrange() function to sort one of the many data frames on a character variable (named "prevalence").
Issue: I am not getting the desired output (line 7 is the problem, which should be the very last line in the sorted data frame) because the sorted field is character, not numeric.
The reproducible example and the output are appended below.
Is there any work-around to convert/treat this character variable (named "prevalence" in the data frame below) as numeric before using the arrange() function within the dplyr package?
Any hints will be appreciated.
Thanks,
Pradip Muhuri
# Reproducible Example
library("readr")
testdata <- read_csv(
"indicator, prevalence
1. Health check-up, 77.2 (1.19)
2. Blood cholesterol checked, 84.5 (1.14)
3. Recieved flu vaccine, 50.0 (1.33)
4. Blood pressure checked, 88.7 (0.88)
5. Aspirin use-problems, 11.7 (1.02)
6.Colonoscopy, 60.2 (1.41)
7. Sigmoidoscopy, 6.1 (0.61)
8. Blood stool test, 14.6 (1.00)
9.Mammogram, 72.6 (1.82)
10. Pap Smear test, 73.3 (2.37)")
# Sort on the character variable in descending order
arrange(testdata, desc(prevalence))
# Results from Console
indicator prevalence
(chr) (chr)
1 4. Blood pressure checked 88.7 (0.88)
2 2. Blood cholesterol checked 84.5 (1.14)
3 1. Health check-up 77.2 (1.19)
4 10. Pap Smear test 73.3 (2.37)
5 9.Mammogram 72.6 (1.82)
6 6.Colonoscopy 60.2 (1.41)
7 7. Sigmoidoscopy 6.1 (0.61)
8 3. Recieved flu vaccine 50.0 (1.33)
9 8. Blood stool test 14.6 (1.00)
10 5. Aspirin use-problems 11.7 (1.02)
Pradip K. Muhuri, AHRQ/CFACT
5600 Fishers Lane # 7N142A, Rockville, MD 20857
Tel: 301-427-1564
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
On Jun 15, 2016, at 2:08 PM, Muhuri, Pradip (AHRQ/CFACT) <Pradip.Muhuri at ahrq.hhs.gov> wrote:
Hello,
I am using the dplyr's arrange() function to sort one of the many data frames on a character variable (named "prevalence").
Issue: I am not getting the desired output (line 7 is the problem, which should be the very last line in the sorted data frame) because the sorted field is character, not numeric.
The reproducible example and the output are appended below.
Is there any work-around to convert/treat this character variable (named "prevalence" in the data frame below) as numeric before using the arrange() function within the dplyr package?
Any hints will be appreciated.
Thanks,
Pradip Muhuri
# Reproducible Example
library("readr")
testdata <- read_csv(
"indicator, prevalence
1. Health check-up, 77.2 (1.19)
2. Blood cholesterol checked, 84.5 (1.14)
3. Recieved flu vaccine, 50.0 (1.33)
4. Blood pressure checked, 88.7 (0.88)
5. Aspirin use-problems, 11.7 (1.02)
6.Colonoscopy, 60.2 (1.41)
7. Sigmoidoscopy, 6.1 (0.61)
8. Blood stool test, 14.6 (1.00)
9.Mammogram, 72.6 (1.82)
10. Pap Smear test, 73.3 (2.37)")
# Sort on the character variable in descending order
arrange(testdata, desc(prevalence))
# Results from Console
indicator prevalence
(chr) (chr)
1 4. Blood pressure checked 88.7 (0.88)
2 2. Blood cholesterol checked 84.5 (1.14)
3 1. Health check-up 77.2 (1.19)
4 10. Pap Smear test 73.3 (2.37)
5 9.Mammogram 72.6 (1.82)
6 6.Colonoscopy 60.2 (1.41)
7 7. Sigmoidoscopy 6.1 (0.61)
8 3. Recieved flu vaccine 50.0 (1.33)
9 8. Blood stool test 14.6 (1.00)
10 5. Aspirin use-problems 11.7 (1.02)
Despite the fact that the prevalence columns is not really the mixed numeric/alpha , it still can be sorted quite easily with the very handy gtools::mixedorder function:
require(gtools)
Loading required package: gtools
testdata[ mixedorder(testdata$prevalence), ]
indicator prevalence 7 7. Sigmoidoscopy 6.1 (0.61) 5 5. Aspirin use-problems 11.7 (1.02) 8 8. Blood stool test 14.6 (1.00) 3 3. Recieved flu vaccine 50.0 (1.33) 6 6.Colonoscopy 60.2 (1.41) 9 9.Mammogram 72.6 (1.82) 10 10. Pap Smear test 73.3 (2.37) 1 1. Health check-up 77.2 (1.19) 2 2. Blood cholesterol checked 84.5 (1.14) 4 4. Blood pressure checked 88.7 (0.88)
The mixedorder function splits the strings at the space boundaries and tests for numeric or alpha.
Pradip K. Muhuri, AHRQ/CFACT 5600 Fishers Lane # 7N142A, Rockville, MD 20857 Tel: 301-427-1564
David Winsemius Alameda, CA, USA