Using the output of strsplit

tempList

unlist(tempList)

matrix(unlist(tempList), nrow=3)

matrix(unlist(tempList), nrow=3, byrow=T)

matrix(unlist(tempList), nrow=3, byrow=T)[,1]

-----Original Message-----
From: r-help-bounces at r-project.org 
[mailto:r-help-bounces at r-project.org] On Behalf Of James Rome
Sent: Tuesday, 19 January 2010 10:49 a.m.
To: r-help at r-project.org
Subject: [R] Using the output of strsplit

I successfully combined my data frames, and am now on my next hurdle.

I had combined the data and quarter, and used tapply to count 
the entries for each unique date/quarter pair.
ar= tapply(ewrgnd$gw, list(ewrgnd$dq), sum)   #for each date/quarter
combination sums the gw (which are all 1)
dq=row.names(ar)
spl=strsplit(dq)
But I need to split them back into the separate date and 
quarter. So I used strsplit(), and get

spl

[[1]]
[1] "2009-01-01" "60"       

[[2]]
[1] "2009-01-01" "61"       

[[3]]
[1] "2009-01-01" "62"       

[[4]]
[1] "2009-01-01" "63"       

[[5]]
[1] "2009-01-01" "68"       
. . .

But lists throw me. I want to get separate vectors of the 
date and quarter out of my list. All the things I have seen 
extract rows from the list. I need to extract columns.

Thanks list,
Jim Rome

I successfully combined my data frames, and am now on my next hurdle.

I had combined the data and quarter, and used tapply to count the
entries for each unique date/quarter pair.
ar= tapply(ewrgnd$gw, list(ewrgnd$dq), sum) ? #for each date/quarter
combination sums the gw (which are all 1)
dq=row.names(ar)
spl=strsplit(dq)
But I need to split them back into the separate date and quarter. So I
used strsplit(), and get

spl

[[1]]
[1] "2009-01-01" "60"

[[2]]
[1] "2009-01-01" "61"

[[3]]
[1] "2009-01-01" "62"

[[4]]
[1] "2009-01-01" "63"

[[5]]
[1] "2009-01-01" "68"
. . .

But lists throw me. I want to get separate vectors of the date and
quarter out of my list. All the things I have seen extract rows from the
list. I need to extract columns.

Thanks list,
Jim Rome