hello gurus,
i have a data frame like this
HTN HTN_FDR Dyslipidemia CAD t1d_ptype[1:25]
1 Y Y Y T1D
2 T1D
3 Ctrl_FDR
4 T1D
5 Y Ctrl
6 Ctrl
7 Ctrl_FDR
8 T1D
9 Y Y T1D
10 T1D
11 Ctrl_FDR
12 Y Y T1D
13 Y Y Y T1D
14 T1D
15 Ctrl
16 Ctrl
17 Ctrl_FDR
18 T1D
19 T1D
20 Y T1D
21 Ctrl_FDR
22 Ctrl_FDR
23 Ctrl
24 Ctrl
25 T1D
i am converting it to define the groups more uniformly using this code:
for( i in 1:dim(c1)[1])
{
num_comp<-0
for (j in 1:dim(c1)[2])
if (c1[i,j]==2) num_comp=num_comp+1 #"Y"=2
for (j in 1:dim(c1)[2])
if(num_comp>0)
{
if (data$t1d_ptype[i] == "T1D" && c1[i ,j] == 2) c2[i,j]<-"T1D_w"
if (data$t1d_ptype[i] == "T1D" && c1[i, j] == 1) c2[i,j]<-"T1D_oc"
if(substr(data$t1d_ptype[i],1,4) == "Ctrl" && c1[i,j] == 2)
c2[i,j]<-"Ctrl_w"
if (substr(data$t1d_ptype[i],1,4) == "Ctrl" && c1[i,j] == 1)
c2[i,j]<-"Ctrl_oc"
}
else
{
if(data$t1d_ptype[i] == "T1D") c2[i,j]<-"T1D_noc"
if(substr(data$t1d_ptype[i],1,4) == "Ctrl") c2[i,j]<-"Ctrl_noc"
}
}
it is giving me error
In `[<-.factor`(`*tmp*`, iseq, value = structure(c(NA, ... :
invalid factor level, NAs generated
Also it there a simple way to do this.
Thanks
Sharad
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Help with code
14 messages · 1Rnwb, William Dunlap, Justin Haynes +3 more
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Re
your column (i think its called t1d_ptype[1:25]) is a factor and using factors is dangerous at best.
This depends on how you want to define "dangerous". If t1d_ptype ought
take values from a certain set of strings then making it a factor gives
you some safety, since it warns you when you go outside of that set and
try to give it an illegal value. E.g.,
> sex <- factor(c("M","F","F"), levels=c("F", "M"))
> sex[2] <- "no"
Warning message:
In `[<-.factor`(`*tmp*`, 2, value = "no") :
invalid factor level, NAs generated
It does take more work to set up, since you need to enumerate the set
of good strings. That is tedium, not danger.
If t1d_ptype might take any value, then make it a character vector.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-----Original Message----- From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of Justin Haynes Sent: Tuesday, December 20, 2011 11:54 AM To: 1Rnwb Cc: r-help at r-project.org Subject: Re: [R] Help with code the short answer... which is a guess cause you didn't provide a reproducible example... is: your column (i think its called t1d_ptype[1:25]) is a factor and using factors is dangerous at best. you can check with ?str. see ?factor for how to convert back to strings and see if your code works. to answer your second question, yes I'm sure there is a better simple way to do this, but i can't follow what you're doing... for example, I don't know what c1 is... but, the place I would look is at the plyr package. its excellent at splitting and reordering data. and one final note, you should avoid naming things with pre-existing R functions (e.g. data). Justin On Tue, Dec 20, 2011 at 11:14 AM, 1Rnwb <sbpurohit at gmail.com> wrote:
hello gurus,
i have a data frame like this
HTN HTN_FDR Dyslipidemia CAD t1d_ptype[1:25]
1 Y Y Y T1D
2 T1D
3 Ctrl_FDR
4 T1D
5 Y Ctrl
6 Ctrl
7 Ctrl_FDR
8 T1D
9 Y Y T1D
10 T1D
11 Ctrl_FDR
12 Y Y T1D
13 Y Y Y T1D
14 T1D
15 Ctrl
16 Ctrl
17 Ctrl_FDR
18 T1D
19 T1D
20 Y T1D
21 Ctrl_FDR
22 Ctrl_FDR
23 Ctrl
24 Ctrl
25 T1D
i am converting it to define the groups more uniformly using this code:
for( i in 1:dim(c1)[1])
{
num_comp<-0
for (j in 1:dim(c1)[2])
if (c1[i,j]==2) num_comp=num_comp+1 #"Y"=2
for (j in 1:dim(c1)[2])
if(num_comp>0)
{
if (data$t1d_ptype[i] == "T1D" && c1[i ,j] == 2) c2[i,j]<-"T1D_w"
if (data$t1d_ptype[i] == "T1D" && c1[i, j] == 1) c2[i,j]<-"T1D_oc"
if(substr(data$t1d_ptype[i],1,4) == "Ctrl" && c1[i,j] == 2)
c2[i,j]<-"Ctrl_w"
if (substr(data$t1d_ptype[i],1,4) == "Ctrl" && c1[i,j] == 1)
c2[i,j]<-"Ctrl_oc"
}
else
{
if(data$t1d_ptype[i] == "T1D") c2[i,j]<-"T1D_noc"
if(substr(data$t1d_ptype[i],1,4) == "Ctrl") c2[i,j]<-"Ctrl_noc"
}
}
it is giving me error
In `[<-.factor`(`*tmp*`, iseq, value = structure(c(NA, ... :
invalid factor level, NAs generated
Also it there a simple way to do this.
Thanks
Sharad
--
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http://r.789695.n4.nabble.com/Help-with-code-tp4218989p4218989.html
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[[alternative HTML version deleted]]
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Hi
hello gurus,
i have a data frame like this
HTN HTN_FDR Dyslipidemia CAD t1d_ptype[1:25]
1 Y Y Y T1D
2 T1D
3 Ctrl_FDR
4 T1D
5 Y Ctrl
6 Ctrl
7 Ctrl_FDR
8 T1D
9 Y Y T1D
10 T1D
11 Ctrl_FDR
12 Y Y T1D
13 Y Y Y T1D
14 T1D
15 Ctrl
16 Ctrl
17 Ctrl_FDR
18 T1D
19 T1D
20 Y T1D
21 Ctrl_FDR
22 Ctrl_FDR
23 Ctrl
24 Ctrl
25 T1D
i am converting it to define the groups more uniformly using this code:
for( i in 1:dim(c1)[1])
{
num_comp<-0
for (j in 1:dim(c1)[2])
if (c1[i,j]==2) num_comp=num_comp+1 #"Y"=2
for (j in 1:dim(c1)[2])
if(num_comp>0)
{
if (data$t1d_ptype[i] == "T1D" && c1[i ,j] == 2) c2[i,j]<-"T1D_w"
if (data$t1d_ptype[i] == "T1D" && c1[i, j] == 1)
c2[i,j]<-"T1D_oc"
if(substr(data$t1d_ptype[i],1,4) == "Ctrl" && c1[i,j] == 2)
c2[i,j]<-"Ctrl_w"
if (substr(data$t1d_ptype[i],1,4) == "Ctrl" && c1[i,j] == 1)
c2[i,j]<-"Ctrl_oc"
}
else
{
if(data$t1d_ptype[i] == "T1D") c2[i,j]<-"T1D_noc"
if(substr(data$t1d_ptype[i],1,4) == "Ctrl") c2[i,j]<-"Ctrl_noc"
}
}
it is giving me error
In `[<-.factor`(`*tmp*`, iseq, value = structure(c(NA, ... :
invalid factor level, NAs generated
Also it there a simple way to do this.
To do what? The only error i get is Error: object 'c1' not found You probably named your data frame c1 but I do not see any numbers in c1 With your programming style you shall probably use C+ or similar. In R it is almost always better to operate on whole objects. Without knowing what you want to achive and without any data I can only suggest to look at ?factor ?interaction Regards Petr
Thanks Sharad -- View this message in context: http://r.789695.n4.nabble.com/Help-with- code-tp4218989p4218989.html Sent from the R help mailing list archive at Nabble.com.
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
I do not know how to use dput, i am attaching the txt file for the data http://r.789695.n4.nabble.com/file/n4222616/foo.txt foo.txt c1<-read.dlim('foo.txt') c2<-c1 any_comp<-NULL for( i in 1:dim(c1)[1]) { num_comp<-0 for (j in 1:dim(c1)[2]) if (c1[i,j]==2) num_comp=num_comp+1 #"Y"=2 for (j in 1:dim(c1)[2]) if(num_comp>0) { if (data$t1d_ptype[i] == "T1D" && c1[i ,j] == 2) c2[i,j]<-"T1D_w" if (data$t1d_ptype[i] == "T1D" && c1[i, j] == 1) c2[i,j]<-"T1D_oc" if(substr(data$t1d_ptype[i],1,4) == "Ctrl" && c1[i,j] == 2) c2[i,j]<-"Ctrl_w" if (substr(data$t1d_ptype[i],1,4) == "Ctrl" && c1[i,j] == 1) c2[i,j]<-"Ctrl_oc" } else { if(data$t1d_ptype[i] == "T1D") c2[i,j]<-"T1D_noc" if(substr(data$t1d_ptype[i],1,4) == "Ctrl") c2[i,j]<-"Ctrl_noc" } } this gives me whether the particular t1d_ptype has a specific complication as well as there is another complication as well. I will appreciate help very much. thanks sharad -- View this message in context: http://r.789695.n4.nabble.com/Help-with-code-tp4218989p4222616.html Sent from the R help mailing list archive at Nabble.com.
To make it so others can produce
your dataset on their own computers (so
they can easily reproduce the problem you are
having) do, in R,
dump("c1", file=stdout())
and copy the text output by that that into your message.
E.g., suppose I made a data.frame with
junk <- data.frame(x=runif(4),y=runif(4))
and forgot to save the random seed before making it.
Instead of sending the calls to runif I could use dump():
dump("junk", file=stdout())
junk <-
structure(list(x = c(0.415693838847801, 0.399903971236199, 0.999439711682498,
0.331607921980321), y = c(0.827737988438457, 0.193867813330144,
0.0372913987375796, 0.62276106630452)), .Names = c("x", "y"), row.names = c(NA,
-4L), class = "data.frame")
and would copy all of its output into the mail message
(there is no need to copy the dump() command itself).
It isn't pretty but it gets the job done without any fuss.
Some mailers like to break lines that they consider
too long and that can change the meaning of the code
produced by dump(). If your mailer does that, use
dump("c1", file="c1.txt") # or "c:/temp/c1.txt", etc.
and attach the file c1.txt to your mail message.
We will see if my mailer breaks up the lines in my
example.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-----Original Message----- From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of 1Rnwb Sent: Wednesday, December 21, 2011 10:07 AM To: r-help at r-project.org Subject: Re: [R] Help with code I do not know how to use dput, i am attaching the txt file for the data http://r.789695.n4.nabble.com/file/n4222616/foo.txt foo.txt c1<-read.dlim('foo.txt') c2<-c1 any_comp<-NULL for( i in 1:dim(c1)[1]) { num_comp<-0 for (j in 1:dim(c1)[2]) if (c1[i,j]==2) num_comp=num_comp+1 #"Y"=2 for (j in 1:dim(c1)[2]) if(num_comp>0) { if (data$t1d_ptype[i] == "T1D" && c1[i ,j] == 2) c2[i,j]<-"T1D_w" if (data$t1d_ptype[i] == "T1D" && c1[i, j] == 1) c2[i,j]<-"T1D_oc" if(substr(data$t1d_ptype[i],1,4) == "Ctrl" && c1[i,j] == 2) c2[i,j]<-"Ctrl_w" if (substr(data$t1d_ptype[i],1,4) == "Ctrl" && c1[i,j] == 1) c2[i,j]<-"Ctrl_oc" } else { if(data$t1d_ptype[i] == "T1D") c2[i,j]<-"T1D_noc" if(substr(data$t1d_ptype[i],1,4) == "Ctrl") c2[i,j]<-"Ctrl_noc" } } this gives me whether the particular t1d_ptype has a specific complication as well as there is another complication as well. I will appreciate help very much. thanks sharad -- View this message in context: http://r.789695.n4.nabble.com/Help-with-code-tp4218989p4222616.html Sent from the R help mailing list archive at Nabble.com.
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Thanks Bill, the output of dput was very similar to your example, I was not sure so did not put it on the post. however i uploaded the foo.txt file which contains the part of the data. sharad -- View this message in context: http://r.789695.n4.nabble.com/Help-with-code-tp4218989p4222947.html Sent from the R help mailing list archive at Nabble.com.
here is the dump and the code once again, sorry for creating so much noise.
c1<-structure(list(HTN = structure(c(2L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L), .Label = c("", "Y"), class = "factor"), HTN_FDR = structure(c(2L,
1L, 1L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 2L, 2L, 1L, 1L, 1L, 1L,
1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L), .Label = c("", "Y"), class = "factor"),
Dyslipidemia = structure(c(2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
2L, 1L, 1L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L), .Label = c("", "Y"), class = "factor"), CAD = structure(c(1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c("", "Y"), class =
"factor"),
CAD_FDR = structure(c(2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L,
1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L,
1L), .Label = c("", "Y"), class = "factor"), Prior_MI = structure(c(1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c("", "Y"), class =
"factor"),
t1d_ptype = structure(c(3L, 3L, 2L, 3L, 1L, 1L, 2L, 3L, 3L,
3L, 2L, 3L, 3L, 3L, 1L, 1L, 2L, 3L, 3L, 3L, 2L, 2L, 1L, 1L,
3L), .Label = c("Ctrl", "Ctrl_FDR", "T1D"), class = "factor")), .Names =
c("HTN",
"HTN_FDR", "Dyslipidemia", "CAD", "CAD_FDR", "Prior_MI", "t1d_ptype"
), row.names = c(NA, 25L), class = "data.frame")
c2<-c1
any_comp<-NULL
for( i in 1:dim(c1)[1])
{
num_comp<-0
for (j in 1:dim(c1)[2])
if (c1[i,j]==2) num_comp=num_comp+1 #"Y"=2
for (j in 1:dim(c1)[2])
if(num_comp>0)
{
if (data$t1d_ptype[i] == "T1D" && c1[i ,j] == 2) c2[i,j]<-"T1D_w"
if (data$t1d_ptype[i] == "T1D" && c1[i, j] == 1) c2[i,j]<-"T1D_oc"
if(substr(data$t1d_ptype[i],1,4) == "Ctrl" && c1[i,j] == 2)
c2[i,j]<-"Ctrl_w"
if (substr(data$t1d_ptype[i],1,4) == "Ctrl" && c1[i,j] == 1)
c2[i,j]<-"Ctrl_oc"
}
else
{
if(data$t1d_ptype[i] == "T1D") c2[i,j]<-"T1D_noc"
if(substr(data$t1d_ptype[i],1,4) == "Ctrl") c2[i,j]<-"Ctrl_noc"
}
}
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Hi
I do not know how to use dput, i am attaching the txt file for the data
dput(any.object) puts a structure of this object to console. You can copy it to your email and anybody can copy it back to R. Or you can transfer the structure to file see ?dput, ?dget
http://r.789695.n4.nabble.com/file/n4222616/foo.txt foo.txt c1<-read.dlim('foo.txt') c2<-c1 any_comp<-NULL for( i in 1:dim(c1)[1]) { num_comp<-0 for (j in 1:dim(c1)[2]) if (c1[i,j]==2) num_comp=num_comp+1 #"Y"=2
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
this line is never true. There is no 2 in a c1.
Maybe you shall really tell us what is your intention with some simple
example.
Here is a subset of your file c1
my.c1 <- structure(list(HTN = structure(c(2L, 1L, 1L), .Label = c("",
"Y"), class = "factor"), HTN_FDR = structure(c(2L, 2L, 2L), .Label = c("",
"Y"), class = "factor"), Dyslipidemia = structure(c(2L, 1L, 2L
), .Label = c("", "Y"), class = "factor"), CAD = c(NA, NA, NA
), CAD_FDR = structure(c(2L, 2L, 1L), .Label = c("", "Y"), class =
"factor"),
Prior_MI = c(NA, NA, NA)), .Names = c("HTN", "HTN_FDR",
"Dyslipidemia",
"CAD", "CAD_FDR", "Prior_MI"), row.names = c("1", "5", "9"), class =
"data.frame")
Forget your complicated code and tell us what is you desired output?
Regards
Petr
for (j in 1:dim(c1)[2])
if(num_comp>0)
{
if (data$t1d_ptype[i] == "T1D" && c1[i ,j] == 2)
c2[i,j]<-"T1D_w"
if (data$t1d_ptype[i] == "T1D" && c1[i, j] == 1)
c2[i,j]<-"T1D_oc"
if(substr(data$t1d_ptype[i],1,4) == "Ctrl" && c1[i,j] == 2)
c2[i,j]<-"Ctrl_w"
if (substr(data$t1d_ptype[i],1,4) == "Ctrl" && c1[i,j] == 1)
c2[i,j]<-"Ctrl_oc"
}
else
{
if(data$t1d_ptype[i] == "T1D") c2[i,j]<-"T1D_noc"
if(substr(data$t1d_ptype[i],1,4) == "Ctrl")
c2[i,j]<-"Ctrl_noc"
} } this gives me whether the particular t1d_ptype has a specific
complication
as well as there is another complication as well. I will appreciate help very much. thanks sharad -- View this message in context: http://r.789695.n4.nabble.com/Help-with- code-tp4218989p4222616.html Sent from the R help mailing list archive at Nabble.com.
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
1 day later
this is how the ouput from the code should be
structure(list(HTN = 1:10, HTN_FDR = structure(c(4L, 2L, 1L,
2L, 3L, 1L, 1L, 2L, 3L, 2L), .Label = c("Ctrl_noc", "T1D_noc",
"T1D_oc", "T1d_w"), class = "factor"), Dyslipidemia = structure(c(3L,
2L, 1L, 2L, 4L, 1L, 1L, 2L, 4L, 2L), .Label = c("Ctrl_noc", "T1D_noc",
"T1D_oc", "T1D_w"), class = "factor"), CAD = structure(c(3L,
2L, 1L, 2L, 3L, 1L, 1L, 2L, 3L, 2L), .Label = c("Ctrl_noc", "T1D_noc",
"T1D_oc"), class = "factor"), CAD_FDR = structure(c(3L, 2L, 1L,
2L, 3L, 1L, 1L, 2L, 3L, 2L), .Label = c("Ctrl_noc", "T1D_noc",
"T1D_oc"), class = "factor"), Prior_MI = structure(c(3L, 2L,
1L, 2L, 3L, 1L, 1L, 2L, 3L, 2L), .Label = c("Ctrl_noc", "T1D_noc",
"T1D_oc"), class = "factor"), t1d_ptype = structure(c(3L, 3L,
2L, 3L, 1L, 1L, 2L, 3L, 3L, 3L), .Label = c("Ctrl", "Ctrl_FDR",
"T1D"), class = "factor")), .Names = c("HTN", "HTN_FDR", "Dyslipidemia",
"CAD", "CAD_FDR", "Prior_MI", "t1d_ptype"), class = "data.frame", row.names
= c(NA,
-10L))
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On Fri, Dec 23, 2011 at 9:25 AM, 1Rnwb <sbpurohit at gmail.com> wrote:
this is how the ouput from the code should be
What code might that be? Readers of the R-help email list have no idea whatsoever what you're asking. Please include context, as requested in the posting guide. Sarah
structure(list(HTN = 1:10, HTN_FDR = structure(c(4L, 2L, 1L,
2L, 3L, 1L, 1L, 2L, 3L, 2L), .Label = c("Ctrl_noc", "T1D_noc",
"T1D_oc", "T1d_w"), class = "factor"), Dyslipidemia = structure(c(3L,
2L, 1L, 2L, 4L, 1L, 1L, 2L, 4L, 2L), .Label = c("Ctrl_noc", "T1D_noc",
"T1D_oc", "T1D_w"), class = "factor"), CAD = structure(c(3L,
2L, 1L, 2L, 3L, 1L, 1L, 2L, 3L, 2L), .Label = c("Ctrl_noc", "T1D_noc",
"T1D_oc"), class = "factor"), CAD_FDR = structure(c(3L, 2L, 1L,
2L, 3L, 1L, 1L, 2L, 3L, 2L), .Label = c("Ctrl_noc", "T1D_noc",
"T1D_oc"), class = "factor"), Prior_MI = structure(c(3L, 2L,
1L, 2L, 3L, 1L, 1L, 2L, 3L, 2L), .Label = c("Ctrl_noc", "T1D_noc",
"T1D_oc"), class = "factor"), t1d_ptype = structure(c(3L, 3L,
2L, 3L, 1L, 1L, 2L, 3L, 3L, 3L), .Label = c("Ctrl", "Ctrl_FDR",
"T1D"), class = "factor")), .Names = c("HTN", "HTN_FDR", "Dyslipidemia",
"CAD", "CAD_FDR", "Prior_MI", "t1d_ptype"), class = "data.frame", row.names
= c(NA,
-10L))
Sarah Goslee http://www.functionaldiversity.org
Hello,
There are so many people posting answers that I'm curious and decided to try
one.
I don't know if this is it but it doesn't give an error and it reformats
your data
according to the rules in your original code.
#
nr <- dim(c1)[1]
nc <- dim(c1)[2]
c2 <- NULL
c2_row <- rep("", nc-1)
for(i in 1:nr){
ptype <- as.character(c1$t1d_ptype[i])
stype <- substr(ptype,1,4)
num_comp <- sum(c1[i,] == "Y")
for(j in 1:(nc-1)){
c2_row[j] <- ""
if(num_comp > 0){
c1_tmp <- as.integer(c1[i ,j])
if(ptype == "T1D"){
if(c1_tmp == 1) c2_row[j] <- "T1D_oc"
if(c1_tmp == 2) c2_row[j] <- "T1D_w"
}
if(stype == "Ctrl"){
if(c1_tmp == 1) c2_row[j] <- "Ctrl_oc"
if(c1_tmp == 2) c2_row[j] <- "Ctrl_w"
}
}
else{
if(ptype == "T1D") c2_row[j] <- "T1D_noc"
if(stype == "Ctrl") c2_row[j] <- "Ctrl_noc"
}
}
c2 <- rbind(c2, c(c2_row, ptype))
}
c2 <- data.frame(c2)
colnames(c2) <- colnames(c1)
c2
I bet there's a way to work on entire objects. This is C-like.
Rui Barradas
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3 days later
Hi Can you explain rules for propagating values? I do not see any pattern. Only when there is no Y in a line you want to fill all columns with either T1D_noc or Ctrl_noc based on t1d_ptype. I would start with narrowing the levels in last column as it seems to me there is no difference between Ctrl and Ctrl_FDR in desired result levels(c1$t1d_ptype)[1:2] <- "Ctrl" If you want to retain old values just make a new column with t1d_ptype and change levels only in this new column. select all rows without Y selection<-which(rowSums(c1[,1:6]=="")==6) change columns 1:6 to character instead of factors c1[,1:6]<-sapply(c2[,1:6], as.character) put values from last column to other columns and add "noc" c1[selection,1:6]<-paste(c1[selection,7], "noc", sep="_") and after that I am lost. Petr
structure(list(HTN = 1:10, HTN_FDR = structure(c(4L, 2L, 1L,
2L, 3L, 1L, 1L, 2L, 3L, 2L), .Label = c("Ctrl_noc", "T1D_noc",
"T1D_oc", "T1d_w"), class = "factor"), Dyslipidemia = structure(c(3L,
2L, 1L, 2L, 4L, 1L, 1L, 2L, 4L, 2L), .Label = c("Ctrl_noc", "T1D_noc",
"T1D_oc", "T1D_w"), class = "factor"), CAD = structure(c(3L,
2L, 1L, 2L, 3L, 1L, 1L, 2L, 3L, 2L), .Label = c("Ctrl_noc", "T1D_noc",
"T1D_oc"), class = "factor"), CAD_FDR = structure(c(3L, 2L, 1L,
2L, 3L, 1L, 1L, 2L, 3L, 2L), .Label = c("Ctrl_noc", "T1D_noc",
"T1D_oc"), class = "factor"), Prior_MI = structure(c(3L, 2L,
1L, 2L, 3L, 1L, 1L, 2L, 3L, 2L), .Label = c("Ctrl_noc", "T1D_noc",
"T1D_oc"), class = "factor"), t1d_ptype = structure(c(3L, 3L,
2L, 3L, 1L, 1L, 2L, 3L, 3L, 3L), .Label = c("Ctrl", "Ctrl_FDR",
"T1D"), class = "factor")), .Names = c("HTN", "HTN_FDR", "Dyslipidemia",
"CAD", "CAD_FDR", "Prior_MI", "t1d_ptype"), class = "data.frame",
row.names
= c(NA, -10L)) -- View this message in context: http://r.789695.n4.nabble.com/Help-with- code-tp4218989p4228759.html Sent from the R help mailing list archive at Nabble.com.
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